GATE CS 2015 Set 3 — Question 52
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Engineering Mathematics → Linear Algebra → System of Linear Equations
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Question
If the following system has non-trivial solution,px + qy + rz = 0
qx + ry + pz = 0
rx + py + qz = 0,then which one of the following options is TRUE?
qx + ry + pz = 0
rx + py + qz = 0,then which one of the following options is TRUE?
Correct answer
(C) p + q + r = 0 or p = q = r
Solution
1.Analyze Dependencies:
- At time 2, writes A.
- At time 7, reads A.
- This is a "dirty read" because reads a value written by before has committed.
- commits at time 8.
- is still active and fails after time 9.
- A schedule is recoverable if for every transaction that reads from , commits before commits.
- Here, reads from , but commits before . Thus, the schedule is non-recoverable.
- Since fails, it must be rolled back (aborted) to ensure atomicity. However, has already committed and cannot be aborted (Durability property). But used a value from which is now invalid. This inconsistency means atomicity cannot be ensured for the system as a whole given the commit of .
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