GATE CS 2019 Set 1 — Question 34
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Programming & Data Structures → C Programming → Arrays & Strings in C
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Question
Consider the following C program:
The number that will be displayed on execution of the program is __________.
#include <stdio.h>
int main(){
int arr[]={1,2,3,4,5,6,7,8,9,0,1,2,5}, *ip=arr+4;
printf("%d\n", ip[1]);
return 0;
}
The number that will be displayed on execution of the program is __________.
Correct answer
6 to 6
Solution
To find the output of the given C program, let us analyze the array declaration and pointer arithmetic step by step:
$ \text{arr} = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 5\}$ The indices of the elements in
The pointer
$ \text{ip} = \text{arr} + 4$ In C, adding an integer to an array name (which decays to a pointer to its first element) points to the element at index . Therefore,
$ \text{ip}[1] = *(\text{ip} + 1)$ Substituting :
$ \text{ip}[1] = *((\text{arr} + 4) + 1) = *(\text{arr} + 5) = \text{arr}[5]$
1.Array Initialization:
The array arr is initialized with the following elements:$ \text{arr} = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 5\}$ The indices of the elements in
arr are:arr[0] = 1arr[1] = 2arr[2] = 3arr[3] = 4arr[4] = 5arr[5] = 6arr[6] = 7- and so on.
The pointer
ip is initialized as:$ \text{ip} = \text{arr} + 4$ In C, adding an integer to an array name (which decays to a pointer to its first element) points to the element at index . Therefore,
ip points to arr[4], which has the value 5.3.Pointer Indexing:
The expression ip[1] is evaluated using pointer arithmetic as:$ \text{ip}[1] = *(\text{ip} + 1)$ Substituting :
$ \text{ip}[1] = *((\text{arr} + 4) + 1) = *(\text{arr} + 5) = \text{arr}[5]$
4.Value Retrieval:
The value at arr[5] is 6.Thus, the printf statement prints 6.Continue learning with Success Tracker
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