GATE CS 2019 Set 1 — Question 36
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Programming & Data Structures → C Programming → Functions & Recursion
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Question
Consider the following C function.Which one of the following will happen when the function convert is called with any positive integer n as argument?
void convert(int n){
if(n<0)
printf("%d",n);
else {
convert(n/2);
printf("%d",n%2);
}
}
Correct answer
(D) It will not print anything and will not terminate
Solution
Let's trace the function with a positive integer, say .
1.
convert(1) is called.2.
n < 0 is false.3.
else block executes: calls convert(1/2) which is convert(0).4.Inside
convert(0):n < 0is false.elseblock executes: callsconvert(0/2)which isconvert(0).
convert(0) calling convert(0).The printf statement is after the recursive call. Since the recursion never terminates (until stack overflow), the control never reaches the printf statement. Therefore, nothing is printed.Thus, the program will not print anything and will not terminate.Continue learning with Success Tracker
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