GATE CS 2024 Set 1 — Question 62

NAT+2 / -0EasyPaging & Address TranslationMemory ManagementOperating System

Operating System → Memory Management → Paging & Address Translation

Last updated 20 August 2026

Question

2\text{ KB}

2\text{ KB} = 2 \times 1024\text{ bytes} = 2048\text{ bytes}

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2\text{ KB} = 2 \times 1024\text{ bytes} = 2048\text{ bytes}

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