GATE CS 2024 Set 2 — Question 63

NAT+2 / -0MediumGroups, Rings & FieldsSets & CombinatoricsEngineering Mathematics

Engineering Mathematics → Sets & Combinatorics → Groups, Rings & Fields

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Question

Let ZnZ_n be the group of integers {0,1,2,,n1}\{0, 1, 2, \dots, n - 1\} with addition modulo nn as the group operation. The number of elements in the group Z2×Z3×Z4Z_2 \times Z_3 \times Z_4 that are their own inverses is ________

Correct answer

4 to 4

Solution

An element (a,b,c)(a, b, c) in the group G=Z2×Z3×Z4G = Z_2 \times Z_3 \times Z_4 is its own inverse if (a,b,c)+(a,b,c)=(0,0,0)(a, b, c) + (a, b, c) = (0, 0, 0), where (0,0,0)(0, 0, 0) is the identity element of the group. This condition is equivalent to solving the following congruences independently for each component:
1.In Z2Z_2: 2a0(mod2)2a \equiv 0 \pmod 2. This is satisfied by a=0a = 0 and a=1a = 1. Thus, there are 2 such elements in Z2Z_2.
2.In Z3Z_3: 2b0(mod3)2b \equiv 0 \pmod 3. Since gcd(2,3)=1\gcd(2, 3) = 1, the only solution is b=0b = 0. Thus, there is 1 such element in Z3Z_3.
3.In Z4Z_4: 2c0(mod4)2c \equiv 0 \pmod 4. This is satisfied by c=0c = 0 and c=2c = 2. Thus, there are 2 such elements in Z4Z_4.
According to the fundamental principle of counting, the total number of elements in the product group Z2×Z3×Z4Z_2 \times Z_3 \times Z_4 that are their own inverses is the product of the number of solutions in each component:Total elements=2×1×2=4\text{Total elements} = 2 \times 1 \times 2 = 4The specific elements are (0,0,0),(0,0,2),(1,0,0), and (1,0,2)(0, 0, 0), (0, 0, 2), (1, 0, 0), \text{ and } (1, 0, 2).

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