GATE CS 2025 Set 1 — Question 44
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Theory of Computation → Finite Automata & Regular Languages → Pumping Lemma (Regular)
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Question
Consider the following two languages over the alphabet :Which ONE of the following statements is CORRECT?
Correct answer
(C) L₁ is not a regular language but L₂ is a regular language.
Solution
Step 1: Analyze .
Since , we can write for some . Thus .
Notice that any string in must start and end with 'a' and have length at least 3 (since and , ).
Conversely, any string that starts and ends with 'a' and has length can be written as where . By choosing , , and , we see that .
Therefore, , which is a regular language.Step 2: Analyze .
This is the set of strings that have a non-overlapping border. Consider the intersection of with the regular language .
A string is in if and only if it has a non-overlapping border . Since must be a prefix and a suffix starting with 'a', the only possible borders are of the form . For to be a prefix, . For it to be a suffix, . For it to be non-overlapping, .
It can be shown that if and only if . The language is not regular. Since the intersection of with a regular language is not regular, itself is not regular.Conclusion: is not regular, but is regular.
Since , we can write for some . Thus .
Notice that any string in must start and end with 'a' and have length at least 3 (since and , ).
Conversely, any string that starts and ends with 'a' and has length can be written as where . By choosing , , and , we see that .
Therefore, , which is a regular language.Step 2: Analyze .
This is the set of strings that have a non-overlapping border. Consider the intersection of with the regular language .
A string is in if and only if it has a non-overlapping border . Since must be a prefix and a suffix starting with 'a', the only possible borders are of the form . For to be a prefix, . For it to be a suffix, . For it to be non-overlapping, .
It can be shown that if and only if . The language is not regular. Since the intersection of with a regular language is not regular, itself is not regular.Conclusion: is not regular, but is regular.
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