GATE EC 2020 Set 1 — Question 52

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MCQ+2 / -0.67MediumDSB-SC & SSBAnalog CommunicationsCommunications

Communications → Analog Communications → DSB-SC & SSB

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Question

For the modulated signal x(t)=m(t)cos(2πfct)x(t) = m(t) \cos(2\pi f_c t), the message signal m(t)=4cos(1000πt)m(t) = 4 \cos(1000\pi t) and the carrier frequency fcf_c is 11 MHz. The signal x(t)x(t) is passed through a demodulator, as shown in the figure below. The output y(t)y(t) of the demodulator is
Block diagram of a demodulator consisting of a multiplier that mixes the input signal $x(t)$ with $\cos(2\pi(f_c + 40)t)$, followed by an Ideal Low Pass Filter with a cut-off frequency of 510 Hz and a rectangular frequency response graph.
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