GATE EE 2015 Set 1 — Question 30

MCQ+1 / -0.33MediumSeries & Parallel ResonanceTransient & AC Steady-StateElectric Circuits

Electric Circuits → Transient & AC Steady-State → Series & Parallel Resonance

Last updated 5 September 2026

Question

i

Z = \frac{(j\omega L)(\frac{1}{j\omega C})}{j\omega L + \frac{1}{j\omega C}} = \frac{j\omega L}{1 - \omega^2 LC}

Review answer and solution without JavaScript

Interactive answer checking needs JavaScript. The published solution is available below.

Z = \frac{(j\omega L)(\frac{1}{j\omega C})}{j\omega L + \frac{1}{j\omega C}} = \frac{j\omega L}{1 - \omega^2 LC}

Continue learning with Success Tracker

Use Success Tracker to ask about the reasoning, then try another GATE EE question to check your understanding.

AI-powered practice· Unlimited practice on eligible plans

PYQs with solutions: Attempt available previous-year questions, then compare your reasoning with the worked solution. Coverage varies by stream.
Practice that adapts: Choose a topic, work on weaker areas and bookmark questions to revisit. Your attempts feed your progress tracking.
AI doubt support: Ask follow-up questions about a step or concept while practising, instead of stopping at the final answer.

Unlimited practice is available on eligible plans. Free practice and AI usage have limits; check the current plan allowances before choosing.

This page stays readable without an account. AI responses can be wrong; check them against the solution and source material.