GATE EE 2015 Set 2 — Question 16
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Electric Circuits → AC Power & Three-Phase → Two-Wattmeter Method
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Question
A 3-phase balanced load which has a power factor of 0.707 is connected to a balanced supply. The power consumed by the load is 5 kW. The power is measured by the two-wattmeter method. The readings of the two wattmeters are
Correct answer
(A) 3.94 kW and 1.06 kW
Solution
Total power kW.
Power factor .
In the two-wattmeter method, the relationship between the readings and the phase angle is given by .
Substituting the values:
kW.
We have two equations:
1)
2)
Adding (1) and (2): kW.
Subtracting (2) from (1): kW.
Thus, the readings are approximately 3.94 kW and 1.06 kW.
Power factor .
In the two-wattmeter method, the relationship between the readings and the phase angle is given by .
Substituting the values:
kW.
We have two equations:
1)
2)
Adding (1) and (2): kW.
Subtracting (2) from (1): kW.
Thus, the readings are approximately 3.94 kW and 1.06 kW.
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