GATE EE 2016 Set 2 — Question 6
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General Aptitude → Quantitative Aptitude → Data Interpretation (Bar, Pie, Graphs, Tables)
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Question
The following graph represents the installed capacity for cement production (in tonnes) and the actual production (in tonnes) of nine cement plants of a cement company. Capacity utilization of a plant is defined as ratio of actual production of cement to installed capacity. A plant with installed capacity of at least 200 tonnes is called a large plant and a plant with lesser capacity is called a small plant. The difference between total production of large plants and small plants, in tonnes is
____.
____.
Correct answer
120 to 120
Solution
Step 1: Identify Large and Small plants based on Installed Capacity (IC).
Large plants (IC 200): Plants 1, 4, 8, 9.
Small plants (IC < 200): Plants 2, 3, 5, 6, 7.Step 2: Calculate total Actual Production (AP) for Large plants.
Total AP (Large) = AP(1) + AP(4) + AP(8) + AP(9)
Total AP (Large) = 160 + 190 + 230 + 190 = 770 tonnes.Step 3: Calculate total Actual Production (AP) for Small plants.
Total AP (Small) = AP(2) + AP(3) + AP(5) + AP(6) + AP(7)
Total AP (Small) = 150 + 160 + 120 + 100 + 120 = 650 tonnes.Step 4: Find the difference.
Difference = 770 - 650 = 120 tonnes.
Large plants (IC 200): Plants 1, 4, 8, 9.
Small plants (IC < 200): Plants 2, 3, 5, 6, 7.Step 2: Calculate total Actual Production (AP) for Large plants.
Total AP (Large) = AP(1) + AP(4) + AP(8) + AP(9)
Total AP (Large) = 160 + 190 + 230 + 190 = 770 tonnes.Step 3: Calculate total Actual Production (AP) for Small plants.
Total AP (Small) = AP(2) + AP(3) + AP(5) + AP(6) + AP(7)
Total AP (Small) = 150 + 160 + 120 + 100 + 120 = 650 tonnes.Step 4: Find the difference.
Difference = 770 - 650 = 120 tonnes.
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