GATE ME 2026 Set 1 — Question 48
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Engineering Mechanics → Statics → Free-Body Diagrams & Equilibrium
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Question
A block of kg mass is on an inclined plane. The block is connected to another hanging mass by an inextensible massless string through two massless pulleys as shown in the figure below. The coefficient of static friction between the block and the inclined plane is . Neglecting pulley friction, the minimum value of required to start the upward motion of the block is ________ kg (rounded off to decimal place).

Correct answer
18.5 to 19.5
Solution
To find the minimum mass required to start the upward motion of the kg block, we analyze the forces at the point of impending motion.
Let be the tension in the string. For the hanging mass in equilibrium:
The movable pulley attached to the block is pulled by two segments of the same string. Thus, the total upward force along the incline is:
At the verge of moving up the incline, the upward force must balance the downward forces (weight component and maximum static friction):
Dividing by :
1.Analyze the Pulley System:
The string is fixed at the top, goes around a movable pulley attached to the kg block, and then over a fixed pulley to the hanging mass . Let be the tension in the string. For the hanging mass in equilibrium:
The movable pulley attached to the block is pulled by two segments of the same string. Thus, the total upward force along the incline is:
2.Analyze the Forces on the 50 kg Block:
- Mass of the block kg
- Angle of inclination
- Coefficient of static friction
- Normal force
- Frictional force (opposing upward motion)
- Component of weight down the incline
At the verge of moving up the incline, the upward force must balance the downward forces (weight component and maximum static friction):
Dividing by :
4.Calculation:
Rounding to decimal place, the minimum value of is kg.Continue learning with Success Tracker
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