GATE CE 2018 Set 1 — Question 9

MCQ+2 / -0.67MediumSeriesQuantitative AptitudeGeneral Aptitude

General Aptitude → Quantitative Aptitude → Series

Last updated 5 September 2026

Question

a_1, a_2, a_3, \dots, a_n

S_{50} = \sum_{n=1}^{50} a_n = \sum_{n=1}^{50} \left( \frac{1}{n} - \frac{1}{n+2} \right)

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S_{50} = \sum_{n=1}^{50} a_n = \sum_{n=1}^{50} \left( \frac{1}{n} - \frac{1}{n+2} \right)

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