GATE CS 2014 Set 3 — Question 21
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Question
The minimum number of arithmetic operations required to evaluate the polynomial for a given value of , using only one temporary variable is ______.
Correct answer
7 to 7
Solution
Official answer (7). Factor in Horner style using only and one temporary :
1. ()
2. ()
3.
4. ()
5.
6. ()
7.
This uses 4 multiplications and 3 additions, i.e. 7 operations, which is the official GATE 2014 answer.Note on the dispute. The coefficients allow a shorter scheme, since :evaluated as , , , , , , which is 6 operations with one temporary. The official key accepts only 7, and that key is retained here.Answer: 7 (official key)Continue learning with Success Tracker
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