GATE CS 2014 Set 3 — Question 20
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Programming & Data Structures → Arrays & Strings → Array Operations (1D, 2D)
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Question
Let be a square matrix of size . Consider the following pseudocode. What is the expected output?
C = 100;
for i = 1 to n do
for j = 1 to n do
{
Temp = A[i][j] + C;
A[i][j] = A[j][i];
A[j][i] = Temp - C;
}
for i = 1 to n do
for j = 1 to n do
output(A[i][j]);
Correct answer
(A) The matrix A itself
Solution
The pseudocode iterates through all elements of the matrix using nested loops for and from to . Inside the loop, it performs a swap operation between and using a temporary variable and an offset . Let's trace the operation for a pair of indices where :
1.When : The code swaps and .
2.When : The code swaps and again.
Since the loops cover all pairs , every off-diagonal element is swapped twice, returning it to its original position. Diagonal elements () are swapped with themselves, remaining unchanged. Thus, the matrix remains unchanged.Continue learning with Success Tracker
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