GATE CS 2015 Set 3 — Question 29
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Databases → SQL → Subqueries
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Question
Consider the following relationCinema(theater, address, capacity)Which of the following options will be needed at the end of the SQL querySELECT P1.address
FROM Cinema P1such that it always finds the addresses of theaters with maximum capacity?
FROM Cinema P1such that it always finds the addresses of theaters with maximum capacity?
Correct answer
(A) WHERE P1.capacity = All (select P2.capacity from Cinema P2)
Solution
We want exactly the theaters whose capacity equals the maximum capacity (ties included).
- (A)
P1.capacity >= ALL (SELECT P2.capacity FROM Cinema P2)is true for a row exactly when its capacity is at least every capacity in the table, i.e. when it equals the maximum. All tied maximum theaters are returned. Correct. - (B)
>= ANY (...)is true if the capacity is at least some capacity in the table. Every row satisfies this (it is at least its own capacity, and at least the minimum), so all theaters are returned. Wrong. - (C)
> ALL (SELECT max(P2.capacity) ...)requires a capacity strictly greater than the maximum, which is impossible, so the result is empty. Wrong. - (D)
> ANY (SELECT max(P2.capacity) ...): the subquery returns a single value (the maximum), so this is again "capacity > max", which is never true. Wrong.
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