GATE CS 2015 Set 3 — Question 29
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Databases → SQL → Subqueries
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Question
Consider the following relationCinema(theater, address, capacity)Which of the following options will be needed at the end of the SQL querySELECT P1.address
FROM Cinema P1such that it always finds the addresses of theaters with maximum capacity?
FROM Cinema P1such that it always finds the addresses of theaters with maximum capacity?
Correct answer
(A) WHERE P1.capacity = All (select P2.capacity from Cinema P2)
Solution
Let's construct the Binary Search Tree (BST) by inserting the elements in the given sequence:
Elements: 71, 65, 84, 69, 67, 83
71 (Level 0)
/ \
65 84 (Level 1)
71
/ \
65 84
\
69 (Level 2)
71
/ \
65 84
\
69
/
67 (Level 3)
71 (Level 0)
/ \
65 84 (Level 1)
\ /
69 83 (Level 2)
/
67 (Level 3)The levels are:
Level 0: {71}
Level 1: {65, 84}
Level 2: {69, 83}
Level 3: {67}The element in the lowest level (Level 3) is 67.Therefore, the correct option is (B).
Elements: 71, 65, 84, 69, 67, 83
1.Insert 71: The root is 71. (Level 0)
2.Insert 65: , so 65 becomes the left child of 71. (Level 1)
3.Insert 84: , so 84 becomes the right child of 71. (Level 1)
Current BST:71 (Level 0)
/ \
65 84 (Level 1)
4.Insert 69: . Compare with 65: , so 69 becomes the right child of 65. (Level 2)
Current BST:71
/ \
65 84
\
69 (Level 2)
5.Insert 67: . Compare with 65: . Compare with 69: , so 67 becomes the left child of 69. (Level 3)
Current BST:71
/ \
65 84
\
69
/
67 (Level 3)
6.Insert 83: . Compare with 84: , so 83 becomes the left child of 84. (Level 2)
Final BST:71 (Level 0)
/ \
65 84 (Level 1)
\ /
69 83 (Level 2)
/
67 (Level 3)The levels are:
Level 0: {71}
Level 1: {65, 84}
Level 2: {69, 83}
Level 3: {67}The element in the lowest level (Level 3) is 67.Therefore, the correct option is (B).
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