GATE CS 2016 Set 1 — Question 63
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Computer Networks → Network Layer: Addressing → IPv4 Packet & Fragmentation
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Question
An IP datagram of size 1000 bytes arrives at a router. The router has to forward this packet on a link whose MTU (maximum transmission unit) is 100 bytes. Assume that the size of the IP header is 20 bytes. The number of fragments that the IP datagram will be divided into for transmission is ________.
Correct answer
13 to 13
Solution
1.Identify total data to be transmitted:
Total size of IP datagram = 1000 bytesIP header size = 20 bytes
Payload (data) size = bytes
2.Determine maximum payload per fragment:
MTU = 100 bytesIP header per fragment = 20 bytes
Maximum payload per fragment = bytes
3.Check for fragmentation constraints:
The fragment offset field in the IP header is measured in units of 8 bytes. Therefore, the payload size of all fragments (except the last one) must be a multiple of 8. Since 80 is a multiple of 8 (), we can use 80 bytes of payload per fragment.4.Calculate the number of fragments:
Number of fragments = Number of fragments = .Thus, the datagram will be divided into 13 fragments.
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