GATE CS 2016 Set 2 — Question 61
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Databases → Transactions & Concurrency → Recoverability
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Question
Consider the following database schedule with two transactions, and .where denotes a read operation by transaction on a variable , denotes a write operation by on a variable and denotes an abort by transaction .
Which one of the following statements about the above schedule is TRUE?
Which one of the following statements about the above schedule is TRUE?
Correct answer
(C) S does not have a cascading abort
Solution
Let's analyze the schedule :
1.
2.
3.
4.
5.
6.
7. (Abort )
8. (Abort )
Recoverability: A schedule is recoverable if for every transaction that reads a value written by , commits before commits. In this schedule, there are no "dirty reads" (reading a value written by an uncommitted transaction). reads and before any writes occur. reads and before any writes occur. Since no transaction reads from another, the schedule is trivially recoverable.Cascading Abort: A cascading abort occurs if reads a value written by , and then aborts, forcing to abort. Since there are no read dependencies (no transaction reads data written by another uncommitted transaction), there is no cascading abort. The fact that both abort is independent of data dependencies. Thus, does not have a cascading abort (it is ACA - Avoids Cascading Aborts).Strictness: A schedule is strict if a transaction can neither read nor write a data item until the last transaction that wrote has committed or aborted. Here, writes at step 4 (). Then writes at step 6 (). At step 6, has not yet committed or aborted. Thus, overwrites an uncommitted value. This violates the strict property.Therefore, statement (C) is true.Continue learning with Success Tracker
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