GATE CS 2025 Set 2 — Question 36
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Computer Networks → Data Link Layer → Efficiency Numericals
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Question
Suppose we are transmitting frames between two nodes using Stop-and-Wait protocol. The frame size is 3000 bits. The transmission rate of the channel is 2000 bps (bits/second) and the propagation delay between the two nodes is 100 milliseconds. Assume that the processing times at the source and destination are negligible. Also, assume that the size of the acknowledgement packet is negligible.Which ONE of the following most accurately gives the channel utilization for the above scenario in percentage?
Correct answer
(A) 88.23
Solution
Given:
Frame size () = 3000 bits
Transmission rate () = 2000 bps
Propagation delay () = 100 ms = secondsTransmission delay () is calculated as:For Stop-and-Wait protocol, the channel utilization (efficiency) is given by:Substituting the values:Converting to percentage:The closest option is 88.23.
Frame size () = 3000 bits
Transmission rate () = 2000 bps
Propagation delay () = 100 ms = secondsTransmission delay () is calculated as:For Stop-and-Wait protocol, the channel utilization (efficiency) is given by:Substituting the values:Converting to percentage:The closest option is 88.23.
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