GATE EE 2017 Set 2 — Question 9

MCQ+2 / -0.67EasyLissajous FiguresElectronic & Digital InstrumentsElectrical & Electronic Measurements

Electrical & Electronic Measurements → Electronic & Digital Instruments → Lissajous Figures

Last updated 5 September 2026

Question

A stationary closed Lissajous pattern on an oscilloscope has 3 horizontal tangencies and 2 vertical tangencies for a horizontal input with frequency 3 kHz. The frequency of the vertical input is

\frac{f_y}{f_x} = \frac{\text{Number of horizontal tangencies } (N_h)}{\text{Number of vertical tangencies } (N_v)}

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\frac{f_y}{f_x} = \frac{\text{Number of horizontal tangencies } (N_h)}{\text{Number of vertical tangencies } (N_v)}

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