GATE EE 2020 Set 1 — Question 40
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Analog & Digital Electronics → Diode Circuits → Maximum Power Transfer
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Question
Consider the diode circuit shown below. The diode, , obeys the current-voltage characteristic , where , , is the voltage across the diode and is the current through it. The circuit is biased so that voltage, and current, . If you had to design this circuit to transfer maximum power from the current source () to a resistive load (not shown) at the output, what values of and would you choose?
Correct answer
(D) Small R₁ and large R₂.
Solution
The circuit is the equivalent circuit of a photovoltaic-type source: the current source with the diode and the resistor across it (shunt elements), and in series with the output.
1.Shunt resistor should be large. The current divides between the diode, and the output. Current through , equal to , is lost and never reaches the load. Making large makes this leakage small, so more of reaches the output. (The diode current is set by its voltage and cannot be chosen through or .)
2.Series resistor should be small. All the load current flows through , and the drop (with its loss ) lowers the voltage at the output terminals. Making small keeps the output voltage, and hence the power delivered to the load, as high as possible.
Therefore the design choice is small and large , option (D).Continue learning with Success Tracker
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