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GATE EE 2025 Set 1 — Question 15

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MCQ+1 / -0.33EasyConditional ProbabilityProbabilityEngineering MathematicsExpectation & Variance

Engineering Mathematics → Probability → Conditional Probability

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Question

Consider discrete random variables XX and YY with probabilities as follows:P(X=0 and Y=0)=14P(X = 0 \text{ and } Y = 0) = \frac{1}{4}P(X=1 and Y=0)=18P(X = 1 \text{ and } Y = 0) = \frac{1}{8}P(X=0 and Y=1)=12P(X = 0 \text{ and } Y = 1) = \frac{1}{2}P(X=1 and Y=1)=18P(X = 1 \text{ and } Y = 1) = \frac{1}{8}Given X=1X = 1, the expected value of YY is
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