The PYQ practice room
GATE EE 2025 Set 1
All 65 solved GATE EE 2025 Set 1 questions in exam order. Open a question, commit to an answer, and learn from the step-by-step solution. One question at a time.
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65
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100
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General Aptitude (GA)
101
Q1MCQ1 markEasyKavya _______ go to work yesterday as she ________ feeling well. Select the most appropriate option to complete the above sentence.Think it through. Then check your answer.Question
Kavya _______ go to work yesterday as she ________ feeling well.
Select the most appropriate option to complete the above sentence.Correct answer
(D) couldn’t; wasn’t
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The sentence refers to a past event indicated by the word "yesterday".1.The first blank requires an auxiliary verb in the past tense to indicate inability or lack of action. "couldn't" (could not) is appropriate here to express that she was unable to go.2.The second blank describes her state of being in the past, so "wasn't" (was not) is the correct past tense form of the verb "to be".Therefore, option (D) "couldn't; wasn't" is the most appropriate choice.2
Q2MCQ1 markEasyGood : Evil :: Genuine : _______ Select the most appropriate option to complete the analogy.Think it through. Then check your answer.Question
Good : Evil :: Genuine : _______
Select the most appropriate option to complete the analogy.Correct answer
(A) Counterfeit
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The relationship in the first pair is that of antonyms: "Good" is the opposite of "Evil".
Following the same logic for the second pair, the opposite of "Genuine" (authentic/real) is "Counterfeit" (fake/forged).- Contraband refers to illegal goods.
- Counterfoil is a part of a check or ticket kept as a record.
- Counterpart refers to a person or thing holding a corresponding position.
3
Q3MCQ1 markEasyThe relationship between two variables and is given by and is shown in the figure. Find the values of and . Note: The figure shown is…Think it through. Then check your answer.Question
The relationship between two variables and is given by and is shown in the figure. Find the values of and .Note: The figure shown is representative.
Correct answer
(A) p = -(1)/(2); q = 2
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The given equation of the line is .
From the provided graph, we can identify two points on the line:1.The x-intercept is at . Substituting these values into the equation:2.The y-intercept is at . Substituting these values and the value of into the equation:
So, and , which matches option (A).4
Q4MCQ1 markEasyEach row of Column-I has three items and each item is represented by a circle in Column-II. The arrangement of circles in Column-II represents the relationship among the items in…Think it through. Then check your answer.Question
Each row of Column-I has three items and each item is represented by a circle in Column-II. The arrangement of circles in Column-II represents the relationship among the items in Column-I.Identify the option that has the most appropriate match between Column-I and Column-II.Note: The figures shown are representative.
Correct answer
(B) (1) – (Q); (2) – (R); (3) – (S); (4) – (P)
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Let's analyze the relationships in Column-I:1.Animals, Zebra, Giraffe: Zebra and Giraffe are two distinct (disjoint) categories that both fall under the broader category of Animals. This is represented by two separate circles inside a larger circle, which is diagram (Q).2.Director, Producer, Actor: A person can be any combination of these three roles (e.g., a director can also be an actor and a producer). This is represented by three mutually intersecting circles, which is diagram (R).3.Word, Sentence, Novel: A word is a part of a sentence, and a sentence is a part of a novel. This is a nested hierarchical relationship represented by three concentric circles, which is diagram (S).4.Pianist, Guitarist, Instrumentalist: Both Pianists and Guitarists are types of Instrumentalists. Some people can play both instruments. This is represented by two intersecting circles inside a larger circle, which is diagram (P).Matching these gives: (1)-(Q), (2)-(R), (3)-(S), (4)-(P), which corresponds to option (B).5
Q5MCQ1 markEasyWhat is the value of ?Think it through. Then check your answer.Question
What is the value of ?Correct answer
(C) 3²³
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Given expression: Step 1: Express 27 as a power of 3.
So, Step 2: Simplify the fraction inside the parentheses.
Step 3: Apply the outer exponent.
Thus, the correct option is (C).6
Q6MCQ2 marksEasyIdentify the option that has the most appropriate sequence such that a coherent paragraph is formed: P. It is because deer, like most of the animals that tigers normally prey…Think it through. Then check your answer.Question
Identify the option that has the most appropriate sequence such that a coherent paragraph is formed:P. It is because deer, like most of the animals that tigers normally prey on, run much faster! It simply means, another day of empty stomach for the big cats.
Q. Tigers spend most of their life searching for food.
R. If they trace the scent of deer, tigers follow the trail, chase the deer for a mile or two in the dark, and yet may not catch them.
S. For several nights, they relentlessly prowl through the forest, hunting for a trail that may lead to their prey.Correct answer
(C) Q → S → R → P
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To form a coherent paragraph, we look for logical flow:1.Q is the best opening sentence as it introduces the general subject: tigers and their constant search for food.2.S follows Q by describing the specific method of this search: prowling for nights hunting for a trail.3.R describes a specific scenario that occurs once a trail (scent) is found: the chase and the possibility of failure.4.P provides the reason for the failure mentioned in R (deer run faster) and concludes with the consequence (empty stomach).The logical sequence is Q → S → R → P, which is option (C).7
Q7MCQ2 marksMediumIn the given figure, EF and HJ are coded as 30 and 80, respectively. Which one among the given options is most appropriate for the entries marked (i) and (ii) ? [figure]Think it through. Then check your answer.Question
In the given figure, EF and HJ are coded as 30 and 80, respectively. Which one among the given options is most appropriate for the entries marked (i) and (ii) ?
Correct answer
(C) (i) EG; (ii) 42
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The coding logic is based on the product of the alphabetical positions of the letters.- E is the 5th letter and F is the 6th letter, so EF = .
- H is the 8th letter and J is the 10th letter, so HJ = .
- EF (30) is opposite the sector containing 30.
- HJ (80) is opposite the sector containing 80.
- FG is opposite the sector marked (ii). Since F is the 6th letter and G is the 7th, FG = . Thus, (ii) = 42.
- The sector containing 35 is opposite the sector marked (i). Since , and the 5th letter is E and the 7th letter is G, (i) must be EG.
8
Q8MCQ2 marksEasyScores obtained by two students P and Q in seven courses are given in the table below. Based on the information given in the table, which one of the following statements is…Think it through. Then check your answer.Question
Scores obtained by two students P and Q in seven courses are given in the table below. Based on the information given in the table, which one of the following statements is INCORRECT?P 22 89 50 45 78 60 39 Q 35 65 60 56 81 45 50 Correct answer
(B) Median score of P is same as the median score of Q.
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First, let's calculate the required statistics for both students:Student P:- Sorted scores: 22, 39, 45, 50, 60, 78, 89
- Sum =
- Average =
- Median = 50 (the 4th value in the sorted list)
- Range (Max - Min) =
- Sorted scores: 35, 45, 50, 56, 60, 65, 81
- Sum =
- Average =
- Median = 56 (the 4th value in the sorted list)
- Range (Max - Min) =
(A) Average P (54.71) < Average Q (56). This is TRUE.
(B) Median P (50) is same as Median Q (56). This is FALSE.
(C) Range P (67) > Range Q (46). This is TRUE.
(D) Median Q (56) and Average Q (56) are same. This is TRUE.The incorrect statement is (B).9
Q9MCQ2 marksMediumSpheres of unit diameter are centered at where , and take every possible integer values. The distance between two spheres is computed from the center of one…Think it through. Then check your answer.Question
Spheres of unit diameter are centered at where , and take every possible integer values.The distance between two spheres is computed from the center of one sphere to the center of the other sphere. For a given sphere, is the distance to its nearest sphere and is the distance to its next nearest sphere. The value of is:Correct answer
(C) √(2)
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The centers of the spheres form a simple cubic lattice with a lattice constant (since the centers are at integer coordinates).Consider a sphere centered at the origin :1.The nearest spheres are located at , , and . The distance to these spheres is .2.The next nearest spheres are located at , , and . The distance to these spheres is .The ratio .10
Q10MCQ2 marksMediumIn the triangle , the lengths of and are in the ratio of . is parallel to . Two semicircles are drawn with and as diameters, as shown in the…Think it through. Then check your answer.Question
In the triangle , the lengths of and are in the ratio of . is parallel to . Two semicircles are drawn with and as diameters, as shown in the figure.Which one of the following statements is true about the shaded area ?Note: The figure shown is representative.
Correct answer
(A) The shaded area is (16)/(9) times the area of the semicircle with the diameter PS.
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In , since , by the Basic Proportionality Theorem (or similarity of triangles and ):Given , we have:Thus, .Let be the area of the semicircle with diameter :Let be the area of the semicircle with diameter :The shaded area is the region between the two semicircles:Therefore, the shaded area is times the area of the semicircle with diameter .
Electrical Engineering (EE)
5511
Q11MCQ1 markMediumConsider the set of points which minimize the real valued function Which of the following statements is true…Think it through. Then check your answer.Question
Consider the set of points which minimize the real valued functionWhich of the following statements is true about the set ?Correct answer
(B) The number of elements in the set S is infinite.
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Let . The function can be rewritten as a function of a single variable :To find the minimum, we take the derivative with respect to and set it to zero:Since , this value of corresponds to a minimum. Thus, the function is minimized whenever .
The set represents a line in the 2D plane. A line contains an infinite number of points. Therefore, the number of elements in the set is infinite.12
Q12MCQ1 markEasyLet and be the two eigenvectors corresponding to distinct eigenvalues of a real symmetric matrix. Which one of the following statements…Think it through. Then check your answer.Question
Let and be the two eigenvectors corresponding to distinct eigenvalues of a real symmetric matrix. Which one of the following statements is true?Correct answer
(B) v₁^T v₂ = 0
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A fundamental property of real symmetric matrices is that eigenvectors corresponding to distinct eigenvalues are orthogonal. For two vectors and , orthogonality implies that their inner product (dot product) is zero:Thus, option (B) is correct.13
Q13MCQ1 markEasyLet , and . Then, the system of linear equations…Think it through. Then check your answer.Question
Let , and . Then, the system of linear equations hasCorrect answer
(B) infinitely many solutions.
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The system of linear equations can be analyzed using the rank of the coefficient matrix and the augmented matrix .Matrix .Performing row operations on :
.Rearranging rows:
.The rank of is .Now, consider the augmented matrix .Performing the same row operation :
.The rank of the augmented matrix is .Since , which is less than the number of variables (), the system has infinitely many solutions.14
Q14MCQ1 markEasyLet and let be the identity matrix. Then is equal toThink it through. Then check your answer.Question
Let and let be the identity matrix. Then is equal toCorrect answer
(A) 2P - I
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To find , we multiply matrix by itself:Now, let's evaluate option (A) :Since , option (A) is correct.15
Q15MCQ1 markEasyConsider discrete random variables and with probabilities as follows: …Think it through. Then check your answer.Question
Consider discrete random variables and with probabilities as follows:Given , the expected value of isCorrect answer
(B) (1)/(2)
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The expected value of given is defined as:First, we find the marginal probability :
Next, we find the conditional probabilities :
Now, calculate the expected value:
E[Y | X = 1] = 0 \cdot \left(\frac{1}{2}\right) + 1 \cdot \left(\frac{1}{2} ight) = \frac{1}{2}Thus, the expected value of given is .16
Q16MCQ1 markEasyWhich one of the following statements is true about the small signal voltage gain of a MOSFET based single stage amplifier?Think it through. Then check your answer.Question
Which one of the following statements is true about the small signal voltage gain of a MOSFET based single stage amplifier?Correct answer
(C) Common source amplifier is inverting and common gate amplifier is non-inverting amplifier
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In MOSFET single-stage amplifiers:1.Common Source (CS): The voltage gain is . The negative sign indicates a phase shift, making it an inverting amplifier.2.Common Gate (CG): The voltage gain is . The positive sign indicates that the output is in phase with the input, making it a non-inverting amplifier.3.Common Drain (CD): Also known as a source follower, it has a positive gain , making it non-inverting.Therefore, option (C) is correct.17
Q17MCQ1 markMediumAssuming ideal op-amps, the circuit represents a [figure]Think it through. Then check your answer.Question
Assuming ideal op-amps, the circuit represents a
Correct answer
(D) buffer.
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Let's analyze the circuit:1.The first op-amp has at its non-inverting terminal ().2.The output of the first op-amp is connected to the non-inverting terminal of the second op-amp.3.The second op-amp is in a voltage follower (buffer) configuration, so its output is equal to its non-inverting input.4.The final output is fed back to the inverting terminal of the first op-amp ().5.For an ideal op-amp with negative feedback, . Therefore, .Since the output voltage is equal to the input voltage with unity gain and high input impedance, the circuit represents a buffer.18
Q18MCQ1 markEasyThe I-V characteristics of the element between the nodes X and Y is best depicted by [figure]Think it through. Then check your answer.Question
The I-V characteristics of the element between the nodes X and Y is best depicted by
Correct answer
(B) [figure]
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Applying Kirchhoff's Current Law (KCL) at node X:
The current entering node X must equal the sum of the currents leaving node X through the parallel branches.This is a linear equation of the form where:- Intercept (at )
- Slope (positive slope)
19
Q19MCQ1 markMediumA nullator is defined as a circuit element where the voltage across the device and the current through the device are both zero. A series combination of a nullator and a resistor…Think it through. Then check your answer.Question
A nullator is defined as a circuit element where the voltage across the device and the current through the device are both zero. A series combination of a nullator and a resistor of value, , will behave as aCorrect answer
(B) nullator.
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A nullator is a theoretical two-terminal network element defined by having zero voltage across its terminals () and zero current flowing through it (). When a nullator is connected in series with a resistor of value :1.The current through the entire series combination must be the same as the current through the nullator, which is .2.The voltage across the resistor is .3.The total voltage across the series combination is .Since the total voltage across the combination is zero and the total current through it is zero, the combination behaves exactly like a nullator.20
Q20MCQ1 markEasyConsider a discrete-time linear time-invariant (LTI) system , where Let…Think it through. Then check your answer.Question
Consider a discrete-time linear time-invariant (LTI) system , whereLetwhere is the discrete-time unit impulse function. For an input signal , the output isCorrect answer
(A) x[n] + x[n - 1] + x[n - 2]
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The impulse response of the system is defined as the output when the input is a unit impulse .
Given:
This can be written as: For any LTI system, the output for an input is given by the convolution sum:
Using the property :21
Q21MCQ1 markEasyConsider a continuous-time signal where is the continuous-time unit step function. Let be the continuous-time unit…Think it through. Then check your answer.Question
Consider a continuous-time signalwhere is the continuous-time unit step function. Let be the continuous-time unit impulse function. The value ofisCorrect answer
(A) -9
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The sifting property of the unit impulse function states that:In this problem, we have , which means .
So, the integral is equal to .Given :
Since for and for :
Therefore:22
Q22MCQ1 markMediumSelected data points of the step response of a stable first-order linear time-invariant (LTI) system are given below. The closest value of the time-constant, in sec, of the system…Think it through. Then check your answer.Question
Selected data points of the step response of a stable first-order linear time-invariant (LTI) system are given below. The closest value of the time-constant, in sec, of the system isTime (sec) 0.6 1.6 2.6 10 Output 0.78 1.65 2.18 2.98 3 Correct answer
(B) 2
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The step response of a stable first-order LTI system is given by , where is the steady-state gain and is the time constant.
From the table, as , , so .
Using the data point at s:
Taking the natural logarithm on both sides:
s.
Checking with s:
, which matches the table value of 1.65.23
Q23MCQ1 markMediumThe Nyquist plot of a strictly stable having the numerator polynomial as encircles the critical point once in the anti-clockwise direction. Which one of the…Think it through. Then check your answer.Question
The Nyquist plot of a strictly stable having the numerator polynomial as encircles the critical point once in the anti-clockwise direction. Which one of the following statements on the closed-loop system shown in figure, is correct?
Correct answer
(D) The system is unstable.
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According to the Nyquist stability criterion, , where:- is the number of anti-clockwise encirclements of the critical point .
- is the number of open-loop poles in the right-half plane (RHP).
- is the number of closed-loop poles in the RHP.
The problem states that the plot encircles once in the anti-clockwise direction, so .
Substituting into the formula: .
Since the number of poles cannot be negative, this indicates a contradiction in the standard stability condition for a stable closed-loop system. In competitive exams, any non-zero encirclement when implies that the system is unstable.24
Q24MCQ1 markEasyDuring a power failure, a domestic household uninterruptible power supply (UPS) supplies AC power to a limited number of lights and fans in various rooms. As per a Newton-Raphson…Think it through. Then check your answer.Question
During a power failure, a domestic household uninterruptible power supply (UPS) supplies AC power to a limited number of lights and fans in various rooms. As per a Newton-Raphson load-flow formulation, the UPS would be represented as aCorrect answer
(A) Slack bus
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In a load-flow study, the slack bus (or swing bus) is used as a reference bus where the voltage magnitude and phase angle are specified. In an isolated system, such as a household running on a UPS during a power failure, the UPS acts as the primary source that maintains the system's voltage and frequency. Therefore, it is modeled as a slack bus.25
Q25MCQ1 markMediumWhich one of the following figures represents the radial electric field distribution caused by a spherical cloud of electrons with a volume charge density, …Think it through. Then check your answer.Question
Which one of the following figures represents the radial electric field distribution caused by a spherical cloud of electrons with a volume charge density, for (both , are positive and is the radial distance) and for ?
Correct answer
(C) Fig. (iii)
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Using Gauss's Law in spherical coordinates:
For :
This is a linear decrease from 0 at the center to at .For :
This represents a decay in the negative region.Comparing with the given figures, Fig. (iii) correctly represents this distribution.26
Q26MCQ1 markMediumThe operating region of the developed torque () and speed () of an induction motor drive is given by the shaded region OQRE in the figure. The load torque ()…Think it through. Then check your answer.Question
The operating region of the developed torque () and speed () of an induction motor drive is given by the shaded region OQRE in the figure. The load torque () characteristic is also shown. The motor drive moves from the initial operating point O to the final operating point S. Which one of the following trajectories will take the shortest time?
Correct answer
(A) O - Q - R - S
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The dynamic equation for a motor drive is given by:
To find the time taken to accelerate from speed to :
To minimize the time , we must maximize the accelerating torque at every speed. The maximum developed torque available in the operating region is along the boundary . Therefore, the trajectory provides the maximum possible accelerating torque throughout the speed range, resulting in the shortest acceleration time.27
Q27MCQ1 markMediumThe input voltage and current of a converter are given by, …Think it through. Then check your answer.Question
The input voltage and current of a converter are given by,
where, rad/s. The input power factor of the converter is closest toCorrect answer
(A) 0.845
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The input power factor () is defined as:
Given , the RMS voltage is .
Since the voltage only has a fundamental component, only the fundamental component of current contributes to active power:
The total RMS current is:
Now,
The closest option is 0.845.28
Q28MSQ1 markMediumInstrument(s) required to synchronize an alternator to the grid is/areThink it through. Then check your answer.Question
Instrument(s) required to synchronize an alternator to the grid is/areCorrect answer
(A) Voltmeter; (C) Synchroscope
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To synchronize an alternator with an infinite bus (grid), the following conditions must be satisfied:1.Voltage Magnitude: The terminal voltage of the incoming alternator must be equal to the grid voltage. This is checked using a Voltmeter.2.Frequency: The frequency of the alternator must be equal to (or slightly higher than) the grid frequency.3.Phase Sequence: The phase sequence of the alternator must be the same as that of the grid.4.Phase Angle: The phase displacement between the corresponding phases must be zero.A Synchroscope is specifically designed to indicate the frequency difference and the phase angle between the incoming machine and the grid. Therefore, both a Voltmeter and a Synchroscope are essential instruments for the synchronization process.29
Q29MSQ1 markMediumThe open-loop transfer function of the system shown in the figure, is For , which of the following real axis point(s) is/are…Think it through. Then check your answer.Question
The open-loop transfer function of the system shown in the figure, isFor , which of the following real axis point(s) is/are on the root locus?
Correct answer
(A) -1; (C) -6
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The root locus exists on the real axis at points to the left of an odd number of open-loop poles and zeros.
Given , the open-loop singularities are:- Zeros at and
- Poles at and
- Segment : 1 singularity to the right (odd) On Root Locus.
- Segment : 2 singularities to the right (even) Not on Root Locus.
- Segment : 3 singularities to the right (odd) On Root Locus.
- Segment : 4 singularities to the right (even) Not on Root Locus.
(A) is in Yes.
(B) is in No.
(C) is in Yes.
(D) is in No.30
Q30NAT1 markEasyA continuous time periodic signal is If is the period of , then…Think it through. Then check your answer.Question
A continuous time periodic signal isIf is the period of , then _____(round off to the nearest integer).Correct answer
7 to 7
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The expression represents the average power () of the periodic signal .
For a signal , the average power is given by:Given :- (at Hz)
- (at Hz)
- (at Hz)
31
Q31NAT1 markMediumThe maximum percentage error in the equivalent resistance of two parallel-connected resistors of and with each having a maximum error is…Think it through. Then check your answer.Question
The maximum percentage error in the equivalent resistance of two parallel-connected resistors of and with each having a maximum error is ____________ (round off to nearest integer value).Correct answer
5 to 5
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The equivalent resistance of two parallel resistors is given by:Taking the natural logarithm on both sides:Differentiating both sides:The maximum percentage error is obtained by taking the sum of the absolute values of the individual errors:Given and , , :Rounding to the nearest integer, the value is 5.32
Q32NAT1 markMediumConsider a distribution feeder, with ratio of . At the receiving end, a load is connected. The maximum voltage drop will occur from the sending end to…Think it through. Then check your answer.Question
Consider a distribution feeder, with ratio of . At the receiving end, a load is connected. The maximum voltage drop will occur from the sending end to the receiving end, when the power factor of the load is ___________(round off to three decimal places).Correct answer
0.975 to 0.985
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The approximate voltage drop in a distribution feeder is given by:where is the power factor. To find the power factor that maximizes the voltage drop, we differentiate the expression with respect to and set it to zero:Given the ratio is , we have . Thus:The power factor is :Rounding to three decimal places, the power factor is .33
Q33NAT1 markMediumThe bus impedance matrix of a 3-bus system (in pu) is …Think it through. Then check your answer.Question
The bus impedance matrix of a 3-bus system (in pu) is A symmetrical fault (through a fault impedance of pu) occurs at bus 2. Neglecting pre-fault loading conditions, the voltage at bus 1, during the fault is ________ pu (round off to three decimal places).Correct answer
0.38 to 0.4
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1.Identify the pre-fault conditions: Neglecting pre-fault loading, the pre-fault voltage at all buses is assumed to be pu.2.Identify the fault parameters: A symmetrical fault occurs at bus 2 through a fault impedance pu.3.Calculate the fault current ():The fault current at bus 2 is given by:
From the given matrix, the diagonal element for bus 2 is pu.
4.Calculate the voltage at bus 1 during the fault ():The change in voltage at bus 1 due to the fault is . Thus, the voltage during the fault is:
From the given matrix, the mutual impedance between bus 1 and bus 2 is pu.
5.Final Answer: Rounding to three decimal places as requested, the voltage at bus 1 is pu.34
Q34NAT1 markMediumIn the circuit with ideal devices, the power MOSFET is operated with a duty cycle of 0.4 in a switching cycle with A and V. The power delivered by the current…Think it through. Then check your answer.Question
In the circuit with ideal devices, the power MOSFET is operated with a duty cycle of 0.4 in a switching cycle with A and V. The power delivered by the current source, in W, is ____________ (round off to the nearest integer).
Correct answer
90 to 90
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In a switching cycle, the power delivered by the current source is given by , where is the average voltage across the current source.
When the MOSFET is ON (for time ), the voltage across it (and thus the current source) is V (ideal device).
When the MOSFET is OFF (for time ), the current flows through the diode to the voltage source . The voltage across the current source is then V.
The average voltage is V.
The power delivered is W.35
Q35NAT1 markHardThe induced emf in a , pole, -phase star connected synchronous motor is considered to be equal and in phase with the terminal voltage under no load…Think it through. Then check your answer.Question
The induced emf in a , pole, -phase star connected synchronous motor is considered to be equal and in phase with the terminal voltage under no load condition. On application of a mechanical load, the induced emf phasor is deflected by an angle of mechanical with respect to the terminal voltage phasor. If the synchronous reactance is , and stator resistance is negligible, then the motor armature current magnitude, in ampere, during loaded condition is closest to, ____________ (round off to two decimal places).Correct answer
66.25 to 66.75
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Given:
Line voltage,
Phase voltage for star connection,
Number of poles,
Mechanical deflection angle,
Electrical deflection angle,
Synchronous reactance,
Stator resistance, At no load, the induced emf is equal to and in phase with the terminal voltage . Thus, .Under loaded condition, the induced emf phasor is deflected by . In a motor, lags by the load angle .
Taking as the reference:
The armature current is calculated as:
The magnitude of the armature current is:
Since :
Rounding off to two decimal places, the armature current magnitude is .36
Q36MCQ2 marksMediumLet and be continuous random variables with probability density functions and , respectively. Further, let and…Think it through. Then check your answer.Question
Let and be continuous random variables with probability density functions and , respectively. Further, let andWhich one of the following options is correct?Correct answer
(A) P_Y(y) = cases 12√(y), & y ∈ (0,1] \ 0, & otherwise cases
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Given is uniformly distributed on , its PDF is for .
Let . Since , also lies in .
The Cumulative Distribution Function (CDF) of is:
The Probability Density Function (PDF) of is the derivative of the CDF:
for .
Thus, option (A) is correct.37
Q37MCQ2 marksMediumA Boolean function is given as The…Think it through. Then check your answer.Question
A Boolean function is given as
The simplified form of this function is represented byCorrect answer
(A) [figure]
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The given Boolean function is:
Let .
Let , , , .The expression can be rewritten as:
Using the distributive law repeatedly:
First, consider
Next, consider
Now, multiply these two simplified terms:
Substitute back :
This simplified Boolean function represents an OR gate with inputs and .Option (A) shows an OR gate where the input is first inverted to and then fed into the OR gate along with . This matches the simplified expression .The final answer is .38
Q38MCQ2 marksHardIn the circuit, is an ideal current source. The transistors and are assumed to be biased in saturation, wherein is the input signal and is…Think it through. Then check your answer.Question
In the circuit, is an ideal current source. The transistors and are assumed to be biased in saturation, wherein is the input signal and is fixed DC voltage. Both transistors have a small signal resistance of and trans-conductance of . The small signal output impedance of this circuit is
Correct answer
(C) gₘ r_(ds)² + 2r_(ds)
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To find the small signal output impedance (), we turn off all independent input sources (set ) and apply a test voltage at the output, then find the current flowing into the output. .In this circuit, is a common-source stage, and acts as a common-gate stage because its gate is connected to a fixed DC voltage (). The output is taken from the drain of .1.Analyze with :When , the small-signal gate-source voltage of () is zero. In this condition, behaves as its output resistance connected between its drain and ground.2.Analyze (common-gate stage):The output impedance of a common-gate stage (looking into its drain) when its source is connected to a resistance is given by:
Here, is the impedance looking into the source of . From step 1, the source of is connected to the drain of , and the impedance looking into the drain of (with ) is .
So, .3.Substitute and simplify:Given that both transistors have a small signal resistance of and trans-conductance of , we have and .
Substitute these into the common-gate output impedance formula:
This matches option (C).The ideal current source has infinite impedance and does not affect the small-signal output impedance calculation in this configuration, as it's in series with the output path.The final answer is .39
Q39MCQ2 marksEasyIn the circuit, shown below, if the values of and are very large, the form of the output voltage for a very high frequency square wave input, is best represented by…Think it through. Then check your answer.Question
In the circuit, shown below, if the values of and are very large, the form of the output voltage for a very high frequency square wave input, is best represented by
Correct answer
(C) [figure]
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The given circuit is a passive RC circuit with the output taken across the capacitor. No, the output is taken across the resistor. Let's re-examine the circuit diagram. The output is across the resistor . The input is applied to the series RC combination.This is a high-pass RC filter if the output is taken across the resistor, or a differentiator if the time constant is small compared to the input signal period.The transfer function of the circuit, with output across , is:
The problem states two conditions:1."values of and are very large": This implies that the time constant is very large.2."very high frequency square wave input": This implies that the period of the input square wave is very small.Combining these two conditions, we have . This means the time constant is much larger than the period of the input signal.Let's analyze the circuit behavior under this condition:
When , the capacitor does not have enough time to charge or discharge significantly during one cycle of the high-frequency input. Therefore, the voltage across the capacitor () remains approximately constant over a cycle.Since , and is approximately constant, the output voltage will essentially follow the input voltage but shifted by a DC offset (). If the input square wave is symmetric around zero, then the average value of is zero. For a capacitor in a series circuit, the average voltage across the resistor () must also be zero in steady state. This implies that the average voltage across the capacitor () must be zero. Thus, . This would result in a square wave output, which is option (B).However, the correct answer is (C), which shows a triangular wave. A triangular wave output for a square wave input is characteristic of an integrator circuit. A passive RC circuit acts as an integrator when the output is taken across the capacitor and the time constant is much larger than the period of the input signal. But here the output is across the resistor.Let's re-evaluate the differentiator/integrator conditions for a passive RC circuit where output is across R:- Differentiator behavior: Occurs when . The capacitor acts like a short circuit for most of the time, and the output across R is proportional to the derivative of the input, resulting in spikes for a square wave input. This is not the case here as .
- High-pass filter behavior: For , the circuit passes high frequencies. If the input is a square wave, the output would be a square wave with some distortion, but not typically a triangular wave.
If , then for high frequencies, , so . This is an integrator. For a square wave input, an integrator produces a triangular wave output. This matches option (C).There seems to be a discrepancy in the question's diagram or the intended output. If the output is across the resistor, and , the output should be approximately the input square wave (option B). If the output was across the capacitor, then for , it would be an integrator, producing a triangular wave (option C).Given that option (C) is the correct answer, it implies that the circuit is intended to function as an integrator, which means the output should be taken across the capacitor, or the conditions imply integrator behavior despite the output being shown across the resistor. In typical exam questions, if is large and frequency is high, it's often interpreted as , leading to integrator behavior if output is across C, or passing the input if output is across R.Assuming the question implicitly expects integrator behavior (output across C) or that the diagram is misleading and the conditions very large and high frequency lead to integration:
For a square wave input, an integrator produces a triangular wave output.Let's assume the diagram is correct and output is across R. If and are very large, and frequency is very high, then . The capacitor voltage cannot change much. So is almost constant. . If is a square wave, is also a square wave. This leads to option B.However, if the question implies that the circuit is a low-pass filter (output across C) and the time constant is large enough to integrate the high-frequency square wave, then the output would be triangular. Since the output is explicitly shown across R, this is a high-pass filter. For a high-pass filter, if , the signal passes through with minimal attenuation, so the output would be a square wave (option B).Let's consider the possibility that "very large R and C" means is large compared to the period, but not so large that is constant. If is large enough to cause significant integration, but the output is taken across R, this is contradictory.Given the provided correct answer (C), the most plausible interpretation is that the circuit is intended to act as an integrator, which would mean the output is effectively taken across the capacitor, or the conditions are set up for integration. For a square wave input, an integrator produces a triangular wave output.The final answer is .40
Q40MCQ2 marksMediumLet continuous-time signals and be…Think it through. Then check your answer.Question
Let continuous-time signals and beConsider the convolution . Then isCorrect answer
(A) 1.5
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The area of the convolution of two signals is equal to the product of the areas of the individual signals.
Area of
Area of
Area of .41
Q41MCQ2 marksMediumLet . Then the closed-loop system shown in the figure below, is [figure]Think it through. Then check your answer.Question
Let . Then the closed-loop system shown in the figure below, is
Correct answer
(B) unstable for all K 2.
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The characteristic equation of the closed-loop system is .
Substituting :
For stability, all coefficients of the characteristic equation must be positive.1.2.Thus, the system is stable for and unstable for . Option (B) correctly states it is unstable for all .42
Q42MCQ2 marksMediumThe continuous-time unit impulse signal is applied as an input to a continuous-time linear time-invariant system 𝑺. The output is observed to be the continuous-time unit step…Think it through. Then check your answer.Question
The continuous-time unit impulse signal is applied as an input to a continuous-time linear time-invariant system 𝑺. The output is observed to be the continuous-time unit step signal . Which one of the following statements is true?Correct answer
(B) It is possible to find a bounded input signal which when applied to 𝑺 results in an unbounded output signal.
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The impulse response of the system is .
A system is BIBO (Bounded-Input Bounded-Output) stable if and only if its impulse response is absolutely integrable: .
For this system, . Thus, the system is unstable.
An unstable system means there exists at least one bounded input that produces an unbounded output. For example, if (which is bounded), the output is , which is unbounded as . Therefore, statement (B) is true.43
Q43MCQ2 marksHardThe transformer connection given in the figure is part of a balanced 3-phase circuit where the phase sequence is “abc”. The primary to secondary turns ratio is 2:1. If…Think it through. Then check your answer.Question
The transformer connection given in the figure is part of a balanced 3-phase circuit where the phase sequence is “abc”. The primary to secondary turns ratio is 2:1. If , then the relationship between and will be
Correct answer
(A) I_A I_(ad) = 12√(3) and I_(ad) lags I_A by 30^.
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1.Primary Side (Star Connection):The primary is star-connected, so the line current is equal to the phase current in the primary winding of Leg 1.2.Secondary Side (Zig-zag Connection):In a zig-zag connection, each phase current is formed by the difference of currents in two windings from different legs. From the diagram, the line current flows through the top winding of Leg 1 and the bottom winding of Leg 2.
Let be the primary turns and be the turns of each secondary winding. The given turns ratio is .3.Ampere-Turn Balance:For Leg 1, the ampere-turn balance equation (considering dot conventions for a standard zig-zag transformer) is:
4.Phasor Analysis:For a balanced sequence, let . Then .
Substituting the turns ratio :
This implies and lags by .5.Conclusion:Based on the specific definition of turns ratio and connection details intended in the problem, the magnitude ratio is and lags by .44
Q44MCQ2 marksHardA DC series motor with negligible series resistance is running at a certain speed driving a load, where the load torque varies as cube of the speed. The motor is fed from a…Think it through. Then check your answer.Question
A DC series motor with negligible series resistance is running at a certain speed driving a load, where the load torque varies as cube of the speed. The motor is fed from a DC source and draws armature current. Assume linear magnetic circuit. The external resistance, in , that must be connected in series with the armature to reduce the speed of the motor by half, is closest toCorrect answer
(A) 23.28
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1.Torque Relationships:- Load torque .
- Motor torque . For a linear magnetic circuit, , so .
- At steady state, .
- , , .
- Since is negligible, .
- .
- .
- .
- .
- .
- .
- .
- .
45
Q45MCQ2 marksHardA 3-phase, , pole, star connected induction motor has the following parameters referred to the stator:…Think it through. Then check your answer.Question
A 3-phase, , pole, star connected induction motor has the following parameters referred to the stator:
Stator resistance, magnetizing reactance and core loss of the motor are neglected. The motor is run with constant control from a drive. For maximum starting torque, the voltage and frequency output, respectively, from the drive, is closest to,Correct answer
(C) 100 V and 12.5 Hz
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1.Condition for Maximum Starting Torque: Starting torque is maximum when the rotor resistance equals the equivalent standstill reactance: .2.Frequency Dependence: Reactance varies linearly with frequency . Let be the operating frequency.- .
- .
- .
46
Q46MCQ2 marksMediumThe 3-phase modulating waveforms (, and ), used in sinusoidal PWM in a Voltage Source Inverter (VSI) are …Think it through. Then check your answer.Question
The 3-phase modulating waveforms (, and ), used in sinusoidal PWM in a Voltage Source Inverter (VSI) arewhere is the fundamental frequency. The modulating waveforms are compared with a 10 kHz triangular carrier whose magnitude varies between +1 and −1. The VSI has a DC link voltage of 600 V and feeds a star connected motor. The per phase fundamental RMS motor voltage, in volts, is closest toCorrect answer
(A) 169.71
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In a three-phase Voltage Source Inverter (VSI) using sinusoidal pulse width modulation (SPWM), the peak value of the fundamental component of the phase (line-to-neutral) voltage is determined by the modulation index and the DC link voltage.1.Determine the amplitude modulation index ():The modulation index is the ratio of the peak amplitude of the control (modulating) signal to the peak amplitude of the carrier signal.
Peak of modulating signal,
Peak of triangular carrier, (since it varies between and )
2.Calculate the peak phase voltage ():For linear modulation (), the peak of the fundamental component of the phase voltage is:
Given ,
3.Calculate the RMS phase voltage ():The RMS value of the fundamental component is:
The value is closest to . Thus, option (A) is correct.47
Q47MCQ2 marksMediumAn ideal sinusoidal voltage source feeds an ideal inductor through an ideal SCR with firing angle . If…Think it through. Then check your answer.Question
An ideal sinusoidal voltage source feeds an ideal inductor through an ideal SCR with firing angle . If , then the peak of the inductor current, in ampere, is closest to
Correct answer
(A) 20.71
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Given:
Voltage source
Peak voltage
Angular frequency rad/s
Inductance
Firing angle For an ideal SCR and inductor, the current starts flowing at . The governing equation is:Integrating from to :The peak current occurs when (at ):The closest value is 20.71.48
Q48MCQ2 marksMediumIn the following circuit, the average voltage where is the firing angle. If the power dissipated in the…Think it through. Then check your answer.Question
In the following circuit, the average voltagewhere is the firing angle. If the power dissipated in the resistor is 64 W, then the closest value of in degrees is
Correct answer
(A) 35.9
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Given:
Power dissipated in the resistor,
Resistance,
Back EMF,
Inductance, Assuming the load current is constant (ripple-free) due to the large inductance, the RMS current is equal to the average current .The average output voltage of the converter is given by:Using the provided formula for the average voltage:Therefore, the closest value of is .49
Q49MCQ2 marksMediumIn the system shown below, the generator was initially supplying power to the grid. A temporary LLLG bolted fault occurs at very close to circuit breaker 1. The circuit…Think it through. Then check your answer.Question
In the system shown below, the generator was initially supplying power to the grid. A temporary LLLG bolted fault occurs at very close to circuit breaker 1. The circuit breakers open to isolate the line. The fault self-clears. The circuit breakers reclose and restore the line. Which one of the following diagrams best indicates the rotor accelerating and decelerating areas?
Correct answer
(B) Fig. (ii)
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1.Pre-fault condition: The generator is supplying power at an initial rotor angle . The electrical power output is .2.Fault condition: A bolted LLLG fault occurs at the generator terminals ( is very close to CB1). This causes the terminal voltage to drop to zero, resulting in . The rotor accelerates due to the power mismatch . The accelerating area is the area under the line from to the clearing angle .3.Post-fault condition: The fault is cleared, and the line is restored. The electrical power output returns to . Since at this stage, the rotor decelerates. The decelerating area is the area between the curve and the line from to the maximum angle .4.Conclusion: Fig. (ii) correctly represents these areas, where is the rectangular area under (since during fault) and is the area above under the sinusoidal power-angle curve.50
Q50MCQ2 marksMediumAn air filled cylindrical capacitor (capacitance ) of length , with and as its inner and outer radii, respectively, consists of two coaxial conducting surfaces.…Think it through. Then check your answer.Question
An air filled cylindrical capacitor (capacitance ) of length , with and as its inner and outer radii, respectively, consists of two coaxial conducting surfaces. Its cross-sectional view is shown in Fig. (i). In order to increase the capacitance, a dielectric material of relative permittivity is inserted inside 50% of the annular region as shown in Fig. (ii). The value of for which the capacitance of the capacitor in Fig. (ii), becomes is
Correct answer
(C) 9
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Capacitance of an air-filled cylindrical capacitor is . In Fig (ii), the dielectric is inserted in 50% of the annular region (half the circumference). This forms two capacitors in parallel: (air part) and (dielectric part). Total capacitance . Given , we have .51
Q51MSQ2 marksMediumLet be the unit radial vector in the spherical co-ordinate system. For which of the following value(s) of , the divergence of the radial vector field…Think it through. Then check your answer.Question
Let be the unit radial vector in the spherical co-ordinate system. For which of the following value(s) of , the divergence of the radial vector field is independent of ?Correct answer
(B) -1; (D) 2
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In spherical coordinates, the divergence of a radial vector field is given by . Given , we have . For the divergence to be independent of , the exponent of must be zero: .52
Q52MSQ2 marksHardConsider two coupled circuits, having self-inductances and , that carry non-zero currents and , respectively. The mutual inductance between the circuits is…Think it through. Then check your answer.Question
Consider two coupled circuits, having self-inductances and , that carry non-zero currents and , respectively. The mutual inductance between the circuits is with unity coupling coefficient. The stored magnetic energy of the coupled circuits is minimum at which of the following value(s) of ?Correct answer
(A) -(M)/(L₁); (D) -(L₂)/(M)
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The stored magnetic energy in a coupled circuit is given by . For minimum energy, the mutual term must be subtractive: .
Let . Then .
To find the minimum, differentiate with respect to : .
If we consider the relative signs of currents, the ratio is for subtractive polarity.
Given unity coupling coefficient, .
Thus, and .
Therefore, . Both options (A) and (D) represent the same value.53
Q53NAT2 marksMediumLet . The rate of change of the real valued function, at the origin in the direction of the point is ___________ (round…Think it through. Then check your answer.Question
Let . The rate of change of the real valued function,at the origin in the direction of the point is ___________ (round off to the nearest integer).Correct answer
0 to 1
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To find the rate of change of the function at the origin in the direction of the point , we calculate the directional derivative.1.Find the gradient of :2.Evaluate the gradient at the origin :3.Determine the unit direction vector:The direction is given by the vector from the origin to , which is .
The magnitude of is .
The unit vector is:
4.Calculate the directional derivative:The rate of change is the dot product of the gradient and the unit direction vector:
5.Round to the nearest integer:Rounding to the nearest integer gives . According to the official answer key, the accepted range is 0 to 1.54
Q54NAT2 marksEasyConsider ordinary differential equations given by with initial conditions and . If…Think it through. Then check your answer.Question
Consider ordinary differential equations given bywith initial conditions and .
If , then at , __________ (round off to the nearest integer).Correct answer
2 to 2
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Given for .
Integrating: .
Using . So, .
Now, .
Integrating: .
Using . So, .
At , .55
Q55NAT2 marksEasyLet be a clockwise oriented closed curve in the complex plane defined by . Further, let be a complex function, where . Then,…Think it through. Then check your answer.Question
Let be a clockwise oriented closed curve in the complex plane defined by . Further, let be a complex function, where . Then, (round off to the nearest integer).Correct answer
0 to 0
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The function is a polynomial in , which is an entire function (analytic everywhere in the complex plane). According to Cauchy's Integral Theorem, the integral of an analytic function over any closed contour is zero. Therefore, .56
Q56NAT2 marksMediumThe op-amps in the following circuit are ideal. The voltage gain of the circuit is ____ (round off to the nearest integer). [figure]Think it through. Then check your answer.Question
The op-amps in the following circuit are ideal. The voltage gain of the circuit is ____ (round off to the nearest integer).
Correct answer
2 to 2
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The circuit consists of two operational amplifier stages. Let the input voltage be , where and are the voltages at the non-inverting terminals of the first and second op-amps, respectively.1.First Stage (Left Op-amp): This is a non-inverting amplifier configuration. The output of the first op-amp, , is given by:2.Second Stage (Right Op-amp): The second op-amp acts as a combination of a non-inverting amplifier for and an inverting amplifier for . Using the principle of superposition:3.Total Gain: Substituting into the equation for :Therefore, the voltage gain .57
Q57NAT2 marksMediumThe switch (S) closes at sec. The time, in sec, the capacitor takes to charge to 50 V is _____ (round off to one decimal place). [figure]Think it through. Then check your answer.Question
The switch (S) closes at sec. The time, in sec, the capacitor takes to charge to 50 V is _____ (round off to one decimal place).
Correct answer
4 to 4.2
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When the switch S closes at , we analyze the circuit to find the Thevenin equivalent across the capacitor terminals.1.Thevenin Resistance (): Deactivating the sources (shorting 100V, opening 3A):2.Thevenin Voltage (): Using nodal analysis at the capacitor node with the capacitor removed:3.Time Constant ():4.Charging Equation: The capacitor voltage is . We solve for when V:Note: Based on the official GATE answer key range of 4.0 to 4.2, there is likely a discrepancy in the printed component values (e.g., if F, s). Following the official key, the answer is 4.1.58
Q58NAT2 marksMediumIn an experiment to measure the active power drawn by a single-phase RL Load connected to an AC source through a resistor, three voltmeters are connected as shown in…Think it through. Then check your answer.Question
In an experiment to measure the active power drawn by a single-phase RL Load connected to an AC source through a resistor, three voltmeters are connected as shown in the figure below. The voltmeter readings are as follows: , , . Assuming perfect resistors and ideal voltmeters, the Load-active power measured in this experiment, in W, is ________ (round off to one decimal place).
Correct answer
78 to 81
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The active power in the load can be calculated using the three-voltmeter method formula:Given:
Substituting the values into the formula:The Load-active power is .59
Q59NAT2 marksMediumIn the Wheatstone bridge shown below, the sensitivity of the bridge in terms of change in balancing voltage for unit change in the resistance , in mV/, is…Think it through. Then check your answer.Question
In the Wheatstone bridge shown below, the sensitivity of the bridge in terms of change in balancing voltage for unit change in the resistance , in mV/, is ______________ (round off to two decimal places).
Correct answer
1.94 to 2
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The balancing voltage (Thevenin voltage across the detector terminals) is given by:The sensitivity of the bridge with respect to is defined as :Given values: , , .Converting to mV/:60
Q60NAT2 marksHardThe steady state capacitor current of a conventional DC-DC buck converter, working in CCM, is shown in one switching cycle. If the input voltage is , the value of the…Think it through. Then check your answer.Question
The steady state capacitor current of a conventional DC-DC buck converter, working in CCM, is shown in one switching cycle. If the input voltage is , the value of the inductor used, in mH, is _____________ (round off to one decimal place).
Correct answer
1.7 to 1.9
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In a buck converter, the capacitor current is the ripple component of the inductor current .1.Determine Inductor Current Ripple ():From the waveform, the peak-to-peak ripple in inductor current is:
2.Determine Duty Cycle () and Switching Period ():The total period .
The current crosses zero at during the rising ramp. For a symmetric triangular wave centered at zero, the zero crossing occurs at the midpoint of the ramp. Thus, the on-time () is:
Duty cycle .3.Calculate Output Voltage ():4.Calculate Inductance ():During the on-time, the voltage across the inductor is :
The value of the inductor is .61
Q61NAT2 marksEasyAn ideal low pass filter has frequency response given by Let be its time domain…Think it through. Then check your answer.Question
An ideal low pass filter has frequency response given by Let be its time domain representation. Then (round off to the nearest integer).Correct answer
200 to 200
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The impulse response is the inverse Fourier transform of the frequency response . The relationship is given by:We are asked to find the value of at . Substituting into the equation:Given the frequency response of the ideal low pass filter:The integral becomes:Therefore, .62
Q62NAT2 marksEasyConsider the state-space model where are the state, input and output,…Think it through. Then check your answer.Question
Consider the state-space modelwhere are the state, input and output, respectively. The matrices are given belowThe sum of the magnitudes of the poles is _______________ (round off to nearest integer).Correct answer
3 to 3
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The poles of the system are the eigenvalues of the state matrix . The characteristic equation is given by .Solving the quadratic equation:The poles are and . The magnitudes of the poles are and .The sum of the magnitudes of the poles is .63
Q63NAT2 marksMediumUsing shunt capacitors, the power factor of a 3-phase, induction motor (drawing at ) is to be corrected to…Think it through. Then check your answer.Question
Using shunt capacitors, the power factor of a 3-phase, induction motor (drawing at ) is to be corrected to . The line current of the capacitor bank, in , is ____________ (round off to one decimal place).Correct answer
8.5 to 10
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Given:- Line voltage (3-phase)
- Apparent power
- Initial power factor
- Target power factor
Step 2: Calculate initial reactive power ():
Step 3: Calculate target reactive power ():
Step 4: Calculate reactive power supplied by the capacitor bank ():
Step 5: Calculate line current of the capacitor bank ():
For a 3-phase capacitor bank, the total reactive power is given by:
Rounding off to one decimal place, the line current is .The official range for the answer is to .64
Q64NAT2 marksHardTwo units, rated at 100 MW and 150 MW, are enabled for economic load dispatch. When the overall incremental cost is 10,000 Rs./MWh, the units are dispatched to 50 MW and 80 MW…Think it through. Then check your answer.Question
Two units, rated at 100 MW and 150 MW, are enabled for economic load dispatch. When the overall incremental cost is 10,000 Rs./MWh, the units are dispatched to 50 MW and 80 MW respectively. At an overall incremental cost of 10,600 Rs./MWh, the power output of the units are 80 MW and 92 MW, respectively. The total plant MW-output (without overloading any unit) at an overall incremental cost of 11,800 Rs./MWh is ________ (round off to the nearest integer).Correct answer
216 to 216
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Assume linear incremental cost curves for both units: .For Unit 1:
Using the given data points and :
Subtracting the first from the second: Rs/MW h.
Rs/MWh.
So, .For Unit 2:
Using the given data points and :
Subtracting the first from the second: Rs/MW h.
Rs/MWh.
So, .At overall incremental cost Rs/MWh:
For Unit 1: MW.
For Unit 2: MW.Check against ratings:
Unit 1 is rated at 100 MW. Since the calculated MW exceeds its rating, it must be limited to MW to avoid overloading.
Unit 2 is rated at 150 MW. The calculated MW is within its rating.Total plant output = MW.65
Q65NAT2 marksMediumA controller of the form is to be designed for the plant as shown in the figure. The value of that yields a…Think it through. Then check your answer.Question
A controller of the form is to be designed for the plant as shown in the figure. The value of that yields a phase margin of at the gain cross-over frequency of is ________________ (round off to one decimal place).
Correct answer
0.1 to 0.1
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The open-loop transfer function is .The phase of the open-loop system is:
At the gain cross-over frequency :
The phase margin () is defined as:
Given :
.Verification of gain condition :
.
The condition is satisfied.