GATE ME 2015 Set 1 — Question 8
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Question
A tiger is 50 leaps of its own behind a deer. The tiger takes 5 leaps per minute to the deer's 4. If the tiger and the deer cover 8 metre and 5 metre per leap respectively, what distance in metres will the tiger have to run before it catches the deer?
Correct answer
800 to 800
Solution
1.Initial distance between tiger and deer = 50 tiger leaps = metres.
2.Speed of tiger = 5 leaps/min = metres/min.
3.Speed of deer = 4 leaps/min = metres/min.
4.Relative speed of tiger with respect to deer = metres/min.
5.Time taken by tiger to catch the deer = minutes.
6.Total distance run by the tiger = metres.
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