GATE ME 2017 Set 1 — Question 2

MCQ+1 / -0.33EasyIndeterminate Forms & L'HospitalSingle Variable CalculusEngineering MathematicsLimits, Continuity & Differentiability

Engineering Mathematics → Single Variable Calculus → Indeterminate Forms & L'Hospital

Last updated 5 September 2026

Question

\lim_{x \to 0} \frac{x^3 - \sin(x)}{x}

\lim_{x \to 0} \left( \frac{x^3}{x} - \frac{\sin(x)}{x} \right) = \lim_{x \to 0} (x^2) - \lim_{x \to 0} \left( \frac{\sin(x)}{x} \right)

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\lim_{x \to 0} \left( \frac{x^3}{x} - \frac{\sin(x)}{x} \right) = \lim_{x \to 0} (x^2) - \lim_{x \to 0} \left( \frac{\sin(x)}{x} \right)

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