GATE ME 2018 Set 2 — Question 41
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Strength of Materials → Beams & Columns → Torsion of Shafts
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Question
A bar of circular cross section is clamped at ends P and Q as shown in the figure. A torsional moment Nm is applied at a distance of 100 mm from end P. The torsional reactions in Nm at the ends P and Q respectively are
(All dimensions are in mm)
Correct answer
(C) (100, 50)
Solution
For a bar clamped at both ends, the total torque is the sum of the reactions at the ends: Nm.
Since the bar is clamped at both ends, the angle of twist at the point of application of must be the same when calculated from either end.
Given mm and mm:
Substituting this into the equilibrium equation:
Nm
Then, Nm.
Thus, .
Since the bar is clamped at both ends, the angle of twist at the point of application of must be the same when calculated from either end.
Given mm and mm:
Substituting this into the equilibrium equation:
Nm
Then, Nm.
Thus, .
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