GATE ME 2019 Set 1 — Question 39
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Engineering Mechanics → Dynamics → Dynamics of Rigid Bodies
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Question
A car having weight is moving in the direction as shown in the figure. The center of gravity (CG) of the car is located at height from the ground, midway between the front and rear wheels. The distance between the front and rear wheels is . The acceleration of the car is , and acceleration due to gravity is . The reactions on the front wheels () and rear wheels () are given by
Correct answer
(C) R_f = (W)/(2) - (W)/(g) ((h)/(l)) a; Rᵣ = (W)/(2) + (W)/(g) ((h)/(l)) a
Solution
Using D'Alembert's principle, an inertial force acts at the CG in the direction opposite to the motion (to the left).
Then, .
1.Vertical equilibrium: .
2.Taking moments about the rear wheel contact point: .
Solving for : .Then, .
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