GATE CS 2014 Set 3 — Question 41
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Operating System → Deadlocks → Deadlock Numericals
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Question
A system contains three programs and each requires three tape units for its operation. The minimum number of tape units which the system must have such that deadlocks never arise is _________.
Correct answer
7 to 7
Solution
Let be the number of processes and be the max demand of each process.
Given:
The condition for deadlock-free operation is:
where is the number of resources (tape units).Substituting the values:
Thus, the minimum number of tape units required is 7.
Given:
The condition for deadlock-free operation is:
where is the number of resources (tape units).Substituting the values:
Thus, the minimum number of tape units required is 7.
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