GATE CS 2018 Set 1 — Question 64
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Computer Networks → Network Layer: Addressing → IPv4 Packet & Fragmentation
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Question
Consider an IP packet with a length of 4,500 bytes that includes a 20-byte IPv4 header and a 40-byte TCP header. The packet is forwarded to an IPv4 router that supports a Maximum Transmission Unit (MTU) of 600 bytes. Assume that the length of the IP header in all the outgoing fragments of this packet is 20 bytes. Assume that the fragmentation offset value stored in the first fragment is 0. The fragmentation offset value stored in the third fragment is _______.
Correct answer
144 to 144
Solution
1.Total IP packet length = 4500 bytes.
2.IP header length = 20 bytes.
3.Payload (Data) length = bytes.
4.MTU = 600 bytes.
5.Maximum payload per fragment = bytes.
6.Since the fragmentation offset is measured in units of 8 bytes, the payload size in each fragment (except possibly the last) must be a multiple of 8. The largest multiple of 8 less than or equal to 580 is ().
7.Fragment 1: Payload = 576 bytes. Offset = 0.
8.Fragment 2: Payload = 576 bytes. Offset = .
9.Fragment 3: Payload = 576 bytes. Offset = .
Therefore, the fragmentation offset value stored in the third fragment is 144.Continue learning with Success Tracker
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