GATE CS 2020 Set 1 — Question 60
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Operating System → Process Scheduling → FCFS & SJF
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Question
Consider the following set of processes, assumed to have arrived at time 0. Consider the CPU scheduling algorithms Shortest Job First (SJF) and Round Robin (RR). For RR, assume that the processes are scheduled in the order .
If the time quantum for RR is 4 ms, then the absolute value of the difference between the average turnaround times (in ms) of SJF and RR (round off to 2 decimal places) is ______.
| Processes | ||||
|---|---|---|---|---|
| Burst time (in ms) | 8 | 7 | 2 | 4 |
Correct answer
5.25 to 5.25
Solution
Given processes with arrival time :1. Shortest Job First (SJF) - Non-preemptive:
Order of execution based on burst time: .
Order: .
Difference = ms.
Order of execution based on burst time: .
- finishes at . .
- finishes at . .
- finishes at . .
- finishes at . .
Order: .
- : executes (Remaining: )
- : executes (Remaining: )
- : executes and finishes. .
- : executes and finishes. .
- : executes and finishes. .
- : executes and finishes. .
Difference = ms.
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