GATE CS 2025 Set 1 — Question 38

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MCQ+2 / -0.67HardPriority SchedulingProcess SchedulingOperating SystemScheduling Numericals

Operating System → Process Scheduling → Priority Scheduling

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A computer has two processors, M1M_1 and M2M_2. Four processes P1,P2,P3,P4P_1, P_2, P_3, P_4 with CPU bursts of 20,16,25,20, 16, 25, and 1010 milliseconds, respectively, arrive at the same time and these are the only processes in the system. The scheduler uses non-preemptive priority scheduling, with priorities decided as follows:
  • M1M_1 uses priority of execution for the processes as, P1>P3>P2>P4P_1 > P_3 > P_2 > P_4, i.e., P1P_1 and P4P_4 have highest and lowest priorities, respectively.
  • M2M_2 uses priority of execution for the processes as, P2>P3>P4>P1P_2 > P_3 > P_4 > P_1, i.e., P2P_2 and P1P_1 have highest and lowest priorities, respectively.
A process PiP_i is scheduled to a processor MkM_k, if the processor is free and no other process PjP_j is waiting with higher priority. At any given point of time, a process can be allocated to any one of the free processors without violating the execution priority rules. Ignore the context switch time. What will be the average waiting time of the processes in milliseconds?
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