GATE EC 2014 Set 1 — Question 19
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Question
In the figure, assume that the forward voltage drops of the PN diode and Schottky diode are and , respectively. If ON denotes conducting state of the diode and OFF denotes non-conducting state of the diode, then in the circuit,
(A) both and are ON
(B) is ON and is OFF
(C) both and are OFF
(D) is OFF and is ON
(A) both and are ON
(B) is ON and is OFF
(C) both and are OFF
(D) is OFF and is ON
Correct answer
(D) D₁ is OFF and D₂ is ON
Solution
Let be the voltage at the node between the resistor and the parallel branches.
Assume is ON. Then .
The total current from the source is .
If is OFF, then .
.
For to be ON, the voltage must be at least . Since , is indeed OFF.
Since , is forward biased and ON.
Therefore, is OFF and is ON.
Assume is ON. Then .
The total current from the source is .
If is OFF, then .
.
For to be ON, the voltage must be at least . Since , is indeed OFF.
Since , is forward biased and ON.
Therefore, is OFF and is ON.
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