GATE EC 2016 Set 2 — Question 44
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Network Theory → Transient & AC Analysis → RL, RC & RLC Transients
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Question
The switch S in the circuit shown has been closed for a long time. It is opened at time and remains open after that. Assume that the diode has zero reverse current and zero forward voltage drop.
The steady state magnitude of the capacitor voltage (in volts) is ______

Correct answer
99 to 101
Solution
When the switch is closed for a long time, the circuit reaches steady state. In DC steady state, the inductor acts as a short circuit and the capacitor acts as an open circuit.
The steady state magnitude of the capacitor voltage is .
1.Initial Inductor Current ():
The current through the inductor is determined by the source and the resistor:2.Initial Capacitor Voltage ():
Since the inductor is a short circuit to ground, the node voltage at the anode of the diode is . Thus, the capacitor is uncharged:3.After the switch is opened ():
The inductor current cannot change instantaneously. It flows through the diode into the capacitor. The diode allows current to flow only into the capacitor, preventing it from discharging back through the inductor. The energy initially stored in the inductor is completely transferred to the capacitor at steady state.4.Energy Conservation:
Substituting the given values (, , ):The steady state magnitude of the capacitor voltage is .
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