GATE EE 2025 Set 1 — Question 40

MCQ+2 / -0.67MediumConvolution Integral & SumLTI SystemsSignals & Systems

Signals & Systems → LTI Systems → Convolution Integral & Sum

Last updated 5 September 2026

Question

x_1(t)

x_1(t) = \int_{0}^{1} 1 dt + \int_{1}^{2} (2-t) dt = [t]_0^1 + [2t - \frac{t^2}{2}]_1^2 = 1 + (4-2) - (2-0.5) = 1 + 2 - 1.5 = 1.5

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x_1(t) = \int_{0}^{1} 1 dt + \int_{1}^{2} (2-t) dt = [t]_0^1 + [2t - \frac{t^2}{2}]_1^2 = 1 + (4-2) - (2-0.5) = 1 + 2 - 1.5 = 1.5

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