GATE ME 2016 Set 3 — Question 62
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Metrology, CIM & Additive Mfg → Metrology & Inspection → Comparators & Interferometry
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Question
Two optically flat plates of glass are kept at a small angle as shown in the figure. Monochromatic light is incident vertically.
If the wavelength of light used to get a fringe spacing of 1 mm is 450 nm, the wavelength of light (in nm) to get a fringe spacing of 1.5 mm is _________
Correct answer
674 to 676
Solution
The fringe spacing () for an air wedge formed between two glass plates is given by the formula:where:
is the wavelength of the incident light,
is the small angle of the wedge (in radians).Since the wedge angle remains constant for both cases, we can write:Given:
We need to find the new wavelength :The wavelength of light required to get a fringe spacing of 1.5 mm is 675 nm.
is the wavelength of the incident light,
is the small angle of the wedge (in radians).Since the wedge angle remains constant for both cases, we can write:Given:
We need to find the new wavelength :The wavelength of light required to get a fringe spacing of 1.5 mm is 675 nm.
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