The PYQ practice room
GATE ME 2016 Set 3
All 65 solved GATE ME 2016 Set 3 questions in exam order. Open a question, commit to an answer, and learn from the step-by-step solution. One question at a time.
Go beyond PYQs with Success TrackerAI-powered personalised practice and doubt support. Unlimited practice on eligible plans; AI usage limits apply.Questions
65
Paper marks
100
Question formats
2
MCQ · NAT
Revision mode
Self-paced
No timer. Focus on understanding.
Explore the questions
General Aptitude (GA)
101
Q1MCQ1 markEasyBased on the given statements, select the appropriate option with respect to grammar and usage. Statements (i) The height of Mr. X is 6 feet. (ii) The height of Mr. Y is 5…Think it through. Then check your answer.Question
Based on the given statements, select the appropriate option with respect to grammar and usage.Statements
(i) The height of Mr. X is 6 feet.
(ii) The height of Mr. Y is 5 feet.Correct answer
(C) Mr. X is taller than Mr. Y.
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
When comparing the height of people, the standard adjective used is 'taller'. 'Longer' is typically used for horizontal dimensions or duration. 'Elongated' means stretched out. 'Lengthier' refers to duration or physical length of objects, not human height.2
Q2MCQ1 markEasyThe students ___________ the teacher on teachers’ day for twenty years of dedicated teaching.Think it through. Then check your answer.Question
The students ___________ the teacher on teachers’ day for twenty years of dedicated teaching.Correct answer
(B) felicitated
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The word 'felicitated' means to congratulate or honor someone, which is appropriate for students honoring a teacher for their service. 'Facilitated' means to make a process easier. 'Fantasized' means to imagine things. 'Facillitated' is an incorrect spelling.3
Q3MCQ1 markEasyAfter India’s cricket world cup victory in 1985, Shrotria who was playing both tennis and cricket till then, decided to concentrate only on cricket. And the rest is…Think it through. Then check your answer.Question
After India’s cricket world cup victory in 1985, Shrotria who was playing both tennis and cricket till then, decided to concentrate only on cricket. And the rest is history.What does the underlined phrase mean in this context?Correct answer
(C) rest is well known
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The idiom 'the rest is history' means that the subsequent events are so well known that they do not need to be mentioned or explained. Thus, 'rest is well known' is the correct meaning.4
Q4MCQ1 markEasyGiven , which one of the following statements is TRUE?Think it through. Then check your answer.Question
Given , which one of the following statements is TRUE?Correct answer
(C) 9 inches = 0.25 yards
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given the equation . Squaring both sides of the equation, we get , which simplifies to . This matches option (C).5
Q5MCQ1 markMediumand are working in shifts in a team to finish a project. works with twice the efficiency of others but for half as many days as worked. and have 6…Think it through. Then check your answer.Question
and are working in shifts in a team to finish a project. works with twice the efficiency of others but for half as many days as worked. and have 6 hour shifts in a day, whereas and have 12 hours shifts. What is the ratio of contribution of to contribution of in the project?Correct answer
(B) 1:2
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Let the efficiency of be . Given has twice the efficiency, efficiency of . Let the number of days worked be . Then worked for days. Shift hours are given as hours/day and hours/day. Contribution is calculated as Efficiency Days Hours per day. Contribution of . Contribution of . The ratio of contribution of to is . Thus, the correct option is (B).6
Q6MCQ2 marksEasyThe Venn diagram shows the preference of the student population for leisure activities. [figure] From the data given, the number of students who like to read books or play sports…Think it through. Then check your answer.Question
The Venn diagram shows the preference of the student population for leisure activities.From the data given, the number of students who like to read books or play sports is ______.
Correct answer
(D) 108
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The number of students who like to read books or play sports is the union of the 'Read books' set and the 'Play sports' set. From the Venn diagram, the regions belonging to either 'Read books' or 'Play sports' (or both) contain the numbers: 13, 12, 7, 44, 17, and 15. Summing these: . Therefore, the correct option is (D).7
Q7MCQ2 marksEasySocial science disciplines were in existence in an amorphous form until the colonial period when they were institutionalized. In varying degrees, they were intended to further the…Think it through. Then check your answer.Question
Social science disciplines were in existence in an amorphous form until the colonial period when they were institutionalized. In varying degrees, they were intended to further the colonial interest. In the time of globalization and the economic rise of postcolonial countries like India, conventional ways of knowledge production have become obsolete.Which of the following can be logically inferred from the above statements?(i) Social science disciplines have become obsolete.
(ii) Social science disciplines had a pre-colonial origin.
(iii) Social science disciplines always promote colonialism.
(iv) Social science must maintain disciplinary boundaries.Correct answer
(A) (ii) only
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Let's analyze the statements:
(i) The text states that "conventional ways of knowledge production have become obsolete", not the disciplines themselves. Thus, (i) is not a valid inference.
(ii) The text mentions that disciplines existed in an "amorphous form until the colonial period", which directly implies they had a pre-colonial origin. Thus, (ii) is a valid inference.
(iii) The text says they were "intended to further the colonial interest" in "varying degrees", which does not mean they "always" promote colonialism. Thus, (iii) is not a valid inference.
(iv) Disciplinary boundaries are not mentioned or implied in the text. Thus, (iv) is not a valid inference.Therefore, only (ii) can be logically inferred.8
Q8MCQ2 marksEasyTwo and a quarter hours back, when seen in a mirror, the reflection of a wall clock without number markings seemed to show 1:30. What is the actual current time shown by the clock?Think it through. Then check your answer.Question
Two and a quarter hours back, when seen in a mirror, the reflection of a wall clock without number markings seemed to show 1:30. What is the actual current time shown by the clock?Correct answer
(D) 12:45
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
1.The mirror image of a clock showing time is given by .2.The reflection showed 1:30, so the actual time at that moment was .3.This was "two and a quarter hours back", which means 2 hours and 15 minutes ago.4.The current actual time is .9
Q9MCQ2 marksMediumM and N start from the same location. M travels 10 km East and then 10 km North-East. N travels 5 km South and then 4 km South-East. What is the shortest distance…Think it through. Then check your answer.Question
M and N start from the same location. M travels 10 km East and then 10 km North-East. N travels 5 km South and then 4 km South-East. What is the shortest distance (in km) between M and N at the end of their travel?Correct answer
(C) 20.61
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Let the starting point be .Final position of M:- First, 10 km East:
- Then, 10 km North-East ():
- First, 5 km South:
- Then, 4 km South-East ():
.10
Q10MCQ2 marksMediumA wire of length 340 mm is to be cut into two parts. One of the parts is to be made into a square and the other into a rectangle where sides are in the ratio of 1:2. What is the…Think it through. Then check your answer.Question
A wire of length 340 mm is to be cut into two parts. One of the parts is to be made into a square and the other into a rectangle where sides are in the ratio of 1:2. What is the length of the side of the square (in mm) such that the combined area of the square and the rectangle is a MINIMUM?Correct answer
(B) 40
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Let the total length of the wire be mm.
Let the wire be cut into two parts of lengths and .1.Square part:Let the length be used to form a square.
Perimeter of square =
Side of square,
Area of square,2.Rectangle part:Let the length be used to form a rectangle with sides in the ratio .
Let the sides be and .
Perimeter of rectangle =
Side
Area of rectangle,3.Total Area Optimization:Total Area
To find the minimum area, differentiate with respect to and set it to zero:
4.Side of the square:The side of the square is
Substituting mm:
Thus, the length of the side of the square for minimum combined area is 40 mm.
Mechanical Engineering (ME)
5511
Q11MCQ1 markEasyA real square matrix is called skew-symmetric ifThink it through. Then check your answer.Question
A real square matrix is called skew-symmetric ifCorrect answer
(C) A^T = -A
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
By definition, a real square matrix is skew-symmetric if its transpose is equal to its negative, i.e., . For a symmetric matrix, .12
Q12MCQ1 markEasyis equal toThink it through. Then check your answer.Question
is equal toCorrect answer
(C) (4)/(3)
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The limit is of the form . Applying L'Hopital's Rule:Substituting :Alternatively, using standard limits:13
Q13MCQ1 markEasySolutions of Laplace’s equation having continuous second-order partial derivatives are calledThink it through. Then check your answer.Question
Solutions of Laplace’s equation having continuous second-order partial derivatives are calledCorrect answer
(B) harmonic functions
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
By definition, a function that satisfies Laplace's equation and has continuous second-order partial derivatives is called a harmonic function. Biharmonic functions satisfy .14
Q14NAT1 markEasyThe area (in percentage) under standard normal distribution curve of random variable within limits from to is __________Think it through. Then check your answer.Question
The area (in percentage) under standard normal distribution curve of random variable within limits from to is __________Correct answer
99.6 to 99.8
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For a standard normal distribution , the area within the limits to is given by . Using standard normal tables, and . Thus, . In percentage terms, this is . This is also known as the empirical rule or the rule, which states that approximately of the data falls within three standard deviations of the mean for a normal distribution.15
Q15MCQ1 markEasyThe root of the function obtained after first iteration on application of Newton-Raphson scheme using an initial guess of isThink it through. Then check your answer.Question
The root of the function obtained after first iteration on application of Newton-Raphson scheme using an initial guess of isCorrect answer
(C) 0.750
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given .
First derivative: .
Initial guess .
.
.
Newton-Raphson formula: .
For first iteration (): .
Thus, the root after the first iteration is 0.750.16
Q16MCQ1 markEasyA force is acting on a bent bar which is clamped at one end as shown in the figure. [figure] The CORRECT free body diagram isThink it through. Then check your answer.Question
A force is acting on a bent bar which is clamped at one end as shown in the figure.The CORRECT free body diagram is
Correct answer
(A) [figure]
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
A clamped or fixed support in a two-dimensional plane prevents translation in both the horizontal () and vertical () directions, as well as rotation. Consequently, it exerts three reaction components: a horizontal force (), a vertical force (), and a reactive moment (). The applied force acts at the free end of the bent bar at an angle of to the horizontal. A correct Free Body Diagram (FBD) must represent all external applied forces and all support reactions. Option (A) is the only diagram that correctly includes both force reactions (), the moment reaction () at the fixed end, and the applied force at its specified orientation.17
Q17MCQ1 markMediumThe cross-sections of two solid bars made of the same material are shown in the figure. The square cross-section has flexural (bending) rigidity , while the circular…Think it through. Then check your answer.Question
The cross-sections of two solid bars made of the same material are shown in the figure. The square cross-section has flexural (bending) rigidity , while the circular cross-section has flexural rigidity . Both sections have the same cross-sectional area. The ratio is
Correct answer
(C) π/3
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Flexural rigidity is defined as . Since both bars are made of the same material, the Young's modulus is the same for both. Therefore, the ratio of their flexural rigidities is simply the ratio of their area moments of inertia: .Let the cross-sectional area of both bars be .1.For the square section with side :
2.For the circular section with radius :
Taking the ratio:
.18
Q18MCQ1 markMediumThe state of stress at a point on an element is shown in figure (a). The same state of stress is shown in another coordinate system in figure (b). [figure] The components…Think it through. Then check your answer.Question
The state of stress at a point on an element is shown in figure (a). The same state of stress is shown in another coordinate system in figure (b).The components are given by
Correct answer
(B) (0, 0, p)
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Figure (a) shows an element rotated by relative to the horizontal. The normal stresses on these planes are (tensile) and (compressive). This represents a state of pure shear when viewed in the coordinate system.Using stress transformation equations to find stresses in the system (where is the rotation from to ):
Substituting , , and :
Adding the two equations gives . Subtracting them gives .
Since there are no other external loads, and .
In the notation of the question, , , and . Thus, the components are .19
Q19MCQ1 markEasyA rigid link is undergoing plane motion as shown in the figure ( and are non-zero). is the relative velocity of point with respect to point .…Think it through. Then check your answer.Question
A rigid link is undergoing plane motion as shown in the figure ( and are non-zero). is the relative velocity of point with respect to point .Which one of the following is TRUE?
Correct answer
(D) V_(QP) has only one component perpendicular to PQ
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For a rigid link, the distance between any two points and must remain constant during motion. This constraint implies that the component of the relative velocity along the line joining and must be zero (otherwise the link would be stretching or compressing). Consequently, the relative velocity vector must be entirely perpendicular to the link .20
Q20MCQ1 markEasyThe number of degrees of freedom in a planar mechanism having links and simple hinge joints isThink it through. Then check your answer.Question
The number of degrees of freedom in a planar mechanism having links and simple hinge joints isCorrect answer
(B) 3(n - 1) - 2j
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The Kutzbach criterion for the number of degrees of freedom () of a planar mechanism is given by the formula:where:- is the number of links.
- is the number of simple hinge joints (lower pairs with 1 degree of freedom).
- is the number of higher pairs (with 2 degrees of freedom).
21
Q21NAT1 markEasyThe static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity . The natural…Think it through. Then check your answer.Question
The static deflection of a spring under gravity, when a mass of 1 kg is suspended from it, is 1 mm. Assume the acceleration due to gravity . The natural frequency of this spring-mass system (in rad/s) is_____________Correct answer
99 to 101
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The natural frequency of a spring-mass system is given by the formula:From the condition of static equilibrium under gravity, the weight of the mass is balanced by the spring force:Where:- is the mass.
- is the acceleration due to gravity.
- is the static deflection.
22
Q22MCQ1 markEasyWhich of the bearings given below SHOULD NOT be subjected to a thrust load?Think it through. Then check your answer.Question
Which of the bearings given below SHOULD NOT be subjected to a thrust load?Correct answer
(C) Cylindrical (straight) roller bearing
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Bearings are designed to handle different types of loads:- Deep groove ball bearings can carry both radial and a moderate amount of axial (thrust) load.
- Angular contact ball bearings are specifically designed to carry combined radial and significant axial loads.
- Cylindrical (straight) roller bearings are designed primarily for heavy radial loads. Because the rollers are cylindrical and the races are straight, they have very little to no capacity to support axial (thrust) loads unless they are specifically modified with ribs.
- Tapered roller bearings are designed to carry heavy combined radial and axial loads.
23
Q23NAT1 markEasyA channel of width branches into two sub-channels having width and as shown in figure. If the volumetric flow rate (taking unit…Think it through. Then check your answer.Question
A channel of width branches into two sub-channels having width and as shown in figure. If the volumetric flow rate (taking unit depth) of an incompressible flow through the main channel is and the velocity in the sub-channel of width is , the velocity in the sub-channel of width is _____________ m/s.Assume both inlet and outlet to be at the same elevation.
Correct answer
0.99 to 1.01
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given:
Main channel width
Volumetric flow rate
Sub-channel 1 width
Velocity in sub-channel 1
Sub-channel 2 width
Depth (unit depth)From the continuity equation for incompressible flow:24
Q24MCQ1 markEasyFor a certain two-dimensional incompressible flow, velocity field is given by . The streamlines for this flow are given by the family of curvesThink it through. Then check your answer.Question
For a certain two-dimensional incompressible flow, velocity field is given by . The streamlines for this flow are given by the family of curvesCorrect answer
(B) xy² = constant
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The equation for a streamline in a 2D flow is given by:
Given the velocity field , we have and .
Substituting these into the streamline equation:
Integrating both sides:
Squaring both sides:
Thus, the streamlines are given by .25
Q25NAT1 markEasySteady one-dimensional heat conduction takes place across the faces 1 and 3 of a composite slab consisting of slabs A and B in perfect contact as shown in the figure, where…Think it through. Then check your answer.Question
Steady one-dimensional heat conduction takes place across the faces 1 and 3 of a composite slab consisting of slabs A and B in perfect contact as shown in the figure, where denote the respective thermal conductivities. Using the data as given in the figure, the interface temperature (in ) is __________
Correct answer
67 to 68
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For steady one-dimensional heat conduction through a composite slab, the heat flux is constant throughout:
where is the thermal resistance per unit area.Given data from the figure:
,
, Equating heat flux:26
Q26MCQ1 markEasyGrashof number signifies the ratio ofThink it through. Then check your answer.Question
Grashof number signifies the ratio ofCorrect answer
(B) buoyancy force to viscous force
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The Grashof number () is a dimensionless number in fluid dynamics and heat transfer which approximates the ratio of the buoyancy to viscous force acting on a fluid. It frequently arises in the study of situations involving natural convection.27
Q27MCQ1 markEasyThe INCORRECT statement about the characteristics of critical point of a pure substance is thatThink it through. Then check your answer.Question
The INCORRECT statement about the characteristics of critical point of a pure substance is thatCorrect answer
(C) the ice directly converts from solid phase to vapor phase
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Statement (C) is incorrect because the direct conversion of ice (solid) to vapor is called sublimation, which occurs at pressures and temperatures below the triple point, not at the critical point. At the critical point, the liquid and vapor phases become indistinguishable, and there is no distinct phase change process at constant temperature (A). On a diagram, the critical point is a point of inflection where and (B). Saturated liquid and vapor states are identical at this point (D).28
Q28MCQ1 markEasyFor a heat exchanger, is the maximum temperature difference and is the minimum temperature difference between the two fluids. LMTD is the log…Think it through. Then check your answer.Question
For a heat exchanger, is the maximum temperature difference and is the minimum temperature difference between the two fluids. LMTD is the log mean temperature difference. and are the minimum and the maximum heat capacity rates. The maximum possible heat transfer () between the two fluids isCorrect answer
(B) Cₘᵢₙ Δ Tₘₐₓ
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The maximum possible heat transfer rate () in a heat exchanger is defined as the heat transfer that would occur if the fluid with the minimum heat capacity rate () underwent the maximum possible temperature difference available in the exchanger, which is the difference between the inlet temperatures of the hot and cold fluids (). Thus, .29
Q29NAT1 markMediumThe blade and fluid velocities for an axial turbine are as shown in the figure. [figure] The magnitude of absolute velocity at entry is at an angle of …Think it through. Then check your answer.Question
The blade and fluid velocities for an axial turbine are as shown in the figure.The magnitude of absolute velocity at entry is at an angle of to the axial direction, while the magnitude of the absolute velocity at exit is . The exit velocity vector has a component in the downward direction. Given that the axial (horizontal) velocity is the same at entry and exit, the specific work (in kJ/kg) is__________
Correct answer
50 to 54
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given data:- Absolute velocity at entry,
- Angle of with axial direction,
- Absolute velocity at exit,
- Blade speed,
- Axial velocity is constant,
Step 2: Calculate the whirl velocity at exit ().
Since and :
Step 3: Calculate the specific work ().
The problem states that the exit velocity vector has a component in the downward direction. In the diagram, the entry whirl velocity is upward (in the direction of blade motion), and the exit whirl velocity is downward (opposite to blade motion).
Using Euler's turbine equation:
Since is in the opposite direction to , we take it as negative:
The calculated value falls within the range of to .30
Q30MCQ1 markEasyEngineering strain of a mild steel sample is recorded as . The true strain isThink it through. Then check your answer.Question
Engineering strain of a mild steel sample is recorded as . The true strain isCorrect answer
(C) 0.099\%
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The relationship between true strain () and engineering strain () is given by:Given .In percentage: .31
Q31MCQ1 markMediumEqual amounts of a liquid metal at the same temperature are poured into three moulds made of steel, copper and aluminum. The shape of the cavity is a cylinder with …Think it through. Then check your answer.Question
Equal amounts of a liquid metal at the same temperature are poured into three moulds made of steel, copper and aluminum. The shape of the cavity is a cylinder with diameter. The size of the moulds are such that the outside temperature of the moulds do not increase appreciably beyond the atmospheric temperature during solidification. The sequence of solidification in the mould from the fastest to slowest is (Thermal conductivities of steel, copper and aluminum are , and , respectively.
Specific heats of steel, copper and aluminum are , and , respectively.
Densities of steel, copper and aluminum are , and , respectively.)Correct answer
(C) Copper - Aluminum - Steel
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The rate of solidification depends on the thermal effusivity (heat diffusivity) of the mould material, defined as . A higher effusivity means the mould can extract heat faster, leading to faster solidification.1.Copper:2.Aluminum:3.Steel:Comparing the values, the sequence from fastest to slowest is Copper > Aluminum > Steel.32
Q32MCQ1 markEasyIn a wire-cut EDM process the necessary conditions that have to be met for making a successful cut are thatThink it through. Then check your answer.Question
In a wire-cut EDM process the necessary conditions that have to be met for making a successful cut are thatCorrect answer
(B) wire and sample are electrically conducting
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
In Electrical Discharge Machining (EDM), including wire-cut EDM, material removal occurs through a series of discrete electrical sparks between the tool (the wire) and the workpiece (the sample). For these sparks to occur, both the tool and the workpiece must be electrically conductive to complete the electrical circuit. Therefore, both the wire and the sample must be electrically conducting.33
Q33MCQ1 markEasyInternal gears are manufactured byThink it through. Then check your answer.Question
Internal gears are manufactured byCorrect answer
(B) shaping with pinion cutter
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Internal gears are typically manufactured using gear shaping with a pinion-shaped cutter. This process allows the cutter to operate inside the gear blank. Hobbing is generally restricted to external gears because the hob cannot physically reach the internal surface of a ring gear. Rack cutters are also primarily used for external gears due to clearance issues.34
Q34MCQ1 markEasyMatch the following part programming codes with their respective functions | Part Programming Codes | Functions | | :--- | :--- | | P. G01 | I. Spindle stop | | Q. G03 | II.…Think it through. Then check your answer.Question
Match the following part programming codes with their respective functionsPart Programming Codes Functions P. G01 I. Spindle stop Q. G03 II. Spindle rotation, clockwise R. M03 III. Circular interpolation, anticlockwise S. M05 IV. Linear interpolation Correct answer
(C) P – IV, Q – III, R – II, S – I
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The standard G and M codes for CNC programming are as follows:- G01: Linear interpolation (IV)
- G03: Circular interpolation, anticlockwise (III)
- M03: Spindle rotation, clockwise (II)
- M05: Spindle stop (I)
P IV
Q III
R II
S IThis corresponds to option (C).35
Q35MCQ1 markEasyIn PERT chart, the activity time distribution isThink it through. Then check your answer.Question
In PERT chart, the activity time distribution isCorrect answer
(D) Beta
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
In PERT (Program Evaluation and Review Technique), the activity time distribution is assumed to follow a Beta distribution. This distribution is chosen because it is flexible and can be defined by three time estimates: optimistic (), most likely (), and pessimistic (). In contrast, CPM (Critical Path Method) uses deterministic time estimates.36
Q36NAT2 marksMediumThe number of linearly independent eigenvectors of matrix is _________37
Q37NAT2 marksMediumThe value of the line integral , where is a circle of radius units is ________ Here,…Think it through. Then check your answer.Question
The value of the line integral , where is a circle of radius units is ________Here, and is the UNIT tangent vector on the curve at an arc length from a reference point on the curve. and are the basis vectors in the Cartesian reference. In evaluating the line integral, the curve has to be traversed in the counter-clockwise direction.Correct answer
15.9 to 16.1
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The line integral is given by . Since is the unit tangent vector, . Thus, the integral becomes:Using Green's Theorem, which states that , where is the region enclosed by :
Here, and .Substituting these into the integral:This integral represents the area of the region , which is a circle of radius .Therefore, the value of the line integral is 16.38
Q38MCQ2 marksEasyisThink it through. Then check your answer.Question
isCorrect answer
(C) 1/2
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
To find the limit , we rationalize the expression by multiplying and dividing by its conjugate:As , the terms and approach :Thus, the correct option is (C).39
Q39MCQ2 marksMediumThree cards were drawn from a pack of 52 cards. The probability that they are a king, a queen, and a jack isThink it through. Then check your answer.Question
Three cards were drawn from a pack of 52 cards. The probability that they are a king, a queen, and a jack isCorrect answer
(A) (16)/(5525)
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The total number of ways to draw 3 cards from a pack of 52 is given by :A standard deck contains 4 kings, 4 queens, and 4 jacks. The number of ways to draw exactly one king, one queen, and one jack is:The probability is the ratio of favorable outcomes to total outcomes:Thus, the correct option is (A).40
Q40NAT2 marksEasyAn inextensible massless string goes over a frictionless pulley. Two weights of N and N are attached to the two ends of the string. The weights are released from rest,…Think it through. Then check your answer.Question
An inextensible massless string goes over a frictionless pulley. Two weights of N and N are attached to the two ends of the string. The weights are released from rest, and start moving due to gravity. The tension in the string (in N) is __________
Correct answer
130 to 135
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Let N and N be the weights of the two blocks. The masses are and .For the N block moving downwards with acceleration :
--- (1)For the N block moving upwards with acceleration :
--- (2)Dividing equation (1) by equation (2):Alternatively, using the direct formula for tension in an Atwood machine:The tension in the string is approximately N, which falls within the range of 130 to 135.41
Q41NAT2 marksMediumA circular disc of radius mm and mass kg, initially at rest at position A, rolls without slipping down a curved path as shown in figure. The speed of the disc when…Think it through. Then check your answer.Question
A circular disc of radius mm and mass kg, initially at rest at position A, rolls without slipping down a curved path as shown in figure. The speed of the disc when it reaches position B is _________ m/s.Acceleration due to gravity m/s.
Correct answer
19.9 to 20.1
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Using the principle of conservation of energy for a body rolling without slipping:
Total Energy at A = Total Energy at B
For a circular disc, the moment of inertia . For rolling without slipping, , so .
Substituting these into the energy equation:
Given m and m/s:
m/s.42
Q42NAT2 marksMediumA rigid rod (AB) of length m is undergoing translational as well as rotational motion in the - plane (see the figure). The point A has the velocity…Think it through. Then check your answer.Question
A rigid rod (AB) of length m is undergoing translational as well as rotational motion in the - plane (see the figure). The point A has the velocity m/s. The end B is constrained to move only along the direction.The magnitude of the velocity (in m/s) at the end B is __________
Correct answer
2.9 to 3.1
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For a rigid rod, the component of velocity of both ends along the length of the rod must be equal to maintain the constant length constraint.
Let and .
The position vector of B relative to A is .
Given , .
The unit vector along the rod is .
Equating velocity components along the rod:
m/s.43
Q43NAT2 marksMediumA square plate of dimension is subjected to a uniform pressure load MPa on its edges as shown in the figure. Assume plane stress conditions. The Young’s…Think it through. Then check your answer.Question
A square plate of dimension is subjected to a uniform pressure load MPa on its edges as shown in the figure. Assume plane stress conditions. The Young’s modulus GPa.The deformed shape is a square of dimension . If m and m, the Poisson’s ratio of the plate material is __________
Correct answer
0.18 to 0.22
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The change in length of the side is .
The normal strain in the and directions is:
Under plane stress conditions, the strain-stress relationship is:
Since uniform pressure is applied on all edges, MPa.
.44
Q44MCQ2 marksMediumTwo circular shafts made of same material, one solid (S) and one hollow (H), have the same length and polar moment of inertia. Both are subjected to same torque. Here, …Think it through. Then check your answer.Question
Two circular shafts made of same material, one solid (S) and one hollow (H), have the same length and polar moment of inertia. Both are subjected to same torque. Here, is the twist and is the maximum shear stress in the solid shaft, whereas is the twist and is the maximum shear stress in the hollow shaft. Which one of the following is TRUE?Correct answer
(D) θ_S = θ_H and τ_S < τ_H
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For a shaft under torsion, the relationship is given by .1.Twist (): . Since the torque (), length (), shear modulus (), and polar moment of inertia () are the same for both shafts, their twists are equal: .2.Maximum Shear Stress (): . Since and are the same, .For a solid shaft: .
For a hollow shaft: .
Given , we have , which implies .
Since the maximum shear stress occurs at the outer radius, and . Because , it follows that .45
Q45MCQ2 marksMediumA beam of length is carrying a uniformly distributed load per unit length. The flexural rigidity of the beam is . The reaction at the simple support at the right end…Think it through. Then check your answer.Question
A beam of length is carrying a uniformly distributed load per unit length. The flexural rigidity of the beam is . The reaction at the simple support at the right end is
Correct answer
(B) (3wL)/(8)
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
This is a propped cantilever beam. We can use the method of superposition to find the reaction at the simple support.1.Deflection at the free end due to UDL on a cantilever: (downwards).2.Deflection at the free end due to a point reaction at the support: (upwards).For the net deflection at the simple support to be zero:
.46
Q46NAT2 marksMediumTwo masses are attached to opposite sides of a rigid rotating shaft in the vertical plane. Another pair of equal masses is attached to the opposite sides of the shaft in…Think it through. Then check your answer.Question
Two masses are attached to opposite sides of a rigid rotating shaft in the vertical plane. Another pair of equal masses is attached to the opposite sides of the shaft in the vertical plane as shown in figure.Consider and . For the system to be dynamically balanced, should be ________ kg.
Correct answer
1.9 to 2.1
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For a system to be dynamically balanced, the net centrifugal force and the net moment of centrifugal forces about any point must be zero.1.Static Balance: . Since the masses are on opposite sides, the forces cancel out if and . This condition is satisfied by the symmetry of the arrangement.2.Dynamic Balance: . Let's take the moment about the position of the left mass (origin ):- Left mass at , eccentricity (downwards).
- Left mass at , eccentricity (upwards).
- Right mass at , eccentricity (downwards).
- Right mass at , eccentricity (upwards).
Thus, the value of for dynamic balancing is 2 kg.47
Q47NAT2 marksMediumA single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of , the ratio of the…Think it through. Then check your answer.Question
A single degree of freedom spring-mass system is subjected to a harmonic force of constant amplitude. For an excitation frequency of , the ratio of the amplitude of steady state response to the static deflection of the spring is __________
Correct answer
0.49 to 0.51
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given:
Excitation frequency
Natural frequency The frequency ratio is:
The ratio of the amplitude of steady state response () to the static deflection () for an undamped system is given by the magnification factor:
Substituting :
Thus, the ratio is 0.5.48
Q48NAT2 marksMediumA bolted joint has four bolts arranged as shown in figure. The cross sectional area of each bolt is . A torque is acting on the joint.…Think it through. Then check your answer.Question
A bolted joint has four bolts arranged as shown in figure. The cross sectional area of each bolt is . A torque is acting on the joint. Neglecting friction due to clamping force, maximum shear stress in a bolt is ______ MPa.
Correct answer
39.9 to 40.1
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given:
Torque
Number of bolts
Bolt circle diameter Radius
Area of each bolt The torque is resisted by the shear force in each bolt:
The shear stress in each bolt is:
Thus, the maximum shear stress is 40 MPa.49
Q49NAT2 marksMediumConsider a fully developed steady laminar flow of an incompressible fluid with viscosity through a circular pipe of radius . Given that the velocity at a radial location…Think it through. Then check your answer.Question
Consider a fully developed steady laminar flow of an incompressible fluid with viscosity through a circular pipe of radius . Given that the velocity at a radial location of from the centerline of the pipe is , the shear stress at the wall is , where is __________Correct answer
2.6 to 2.7
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For fully developed laminar flow in a circular pipe, the velocity profile is parabolic:
Given :
The shear stress is given by Newton's law of viscosity:
At the wall ():
Substituting :
Comparing with , we get .50
Q50NAT2 marksMediumThe water jet exiting from a stationary tank through a circular opening of diameter impinges on a rigid wall as shown in the figure. Neglect all minor losses and…Think it through. Then check your answer.Question
The water jet exiting from a stationary tank through a circular opening of diameter impinges on a rigid wall as shown in the figure. Neglect all minor losses and assume the water level in the tank to remain constant. The net horizontal force experienced by the wall is ___________ kN.Density of water is .Acceleration due to gravity .
Correct answer
8.76 to 8.78
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given:
Height of water level,
Diameter of opening,
Density of water,
Acceleration due to gravity,1.Velocity of the jet: Using Torricelli's law, the velocity of the jet exiting the tank is:2.Area of the opening:3.Mass flow rate:4.Force on the wall: The net horizontal force experienced by the wall is equal to the rate of change of momentum of the jet in the horizontal direction (assuming the jet loses all its horizontal momentum upon impact):51
Q51MCQ2 marksMediumFor a two-dimensional flow, the velocity field is , where and are the basis vectors in the…Think it through. Then check your answer.Question
For a two-dimensional flow, the velocity field is , where and are the basis vectors in the Cartesian coordinate system. Identify the CORRECT statements from below.
(1) The flow is incompressible.
(2) The flow is unsteady.
(3) y-component of acceleration,
(4) x-component of acceleration,Correct answer
(B) (1) and (3)
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Velocity components are and .1.Incompressibility check:
Thus, the flow is incompressible. Statement (1) is correct.2.Steadiness check:The velocity field does not depend on time , so the flow is steady. Statement (2) is incorrect.3.Acceleration components:
Statement (4) is incorrect.
Statement (3) is correct.Correct statements are (1) and (3). Option (B) is correct.52
Q52NAT2 marksMediumTwo large parallel plates having a gap of 10 mm in between them are maintained at temperatures and . Given emissivity values,…Think it through. Then check your answer.Question
Two large parallel plates having a gap of 10 mm in between them are maintained at temperatures and . Given emissivity values, and Stefan-Boltzmann constant , the heat transfer between the plates (in kW/m) is __________Correct answer
10.9 to 11.2
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The net radiation heat transfer rate per unit area () between two large parallel plates is given by the formula:Given data:53
Q53NAT2 marksMediumA cylindrical steel rod, in diameter and in length is first heated to and then immersed in a water bath at…Think it through. Then check your answer.Question
A cylindrical steel rod, in diameter and in length is first heated to and then immersed in a water bath at . The heat transfer coefficient is . The density, specific heat and thermal conductivity of steel are , , and , respectively. The time required for the rod to reach is ________ seconds.Correct answer
42 to 45
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
To determine the time required for the rod to cool to , we first evaluate if the lumped heat capacity analysis is applicable by calculating the Biot number ().1.Characteristic Length ():For a cylinder of radius and length :
Given and :2.Biot Number ():
Since , the lumped analysis is valid.3.Lumped Analysis Equation:
Substituting the given values (, , ):
Using the long rod approximation () yields . Both results fall within the specified range of to .54
Q54NAT2 marksEasySteam at an initial enthalpy of and inlet velocity of , enters an insulated horizontal nozzle. It leaves the nozzle at . The…Think it through. Then check your answer.Question
Steam at an initial enthalpy of and inlet velocity of , enters an insulated horizontal nozzle. It leaves the nozzle at . The exit enthalpy (in kJ/kg) is __________Correct answer
84 to 86
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For a steady-flow process in an insulated horizontal nozzle, we apply the Steady Flow Energy Equation (SFEE):Given:- Insulated nozzle:
- Horizontal nozzle:
- No external work:
Rearranging for the exit enthalpy :
Substituting the values (, , ):
Note: . To keep in kJ/kg, we divide the kinetic energy term by .
The exit enthalpy is .55
Q55NAT2 marksMediumIn a mixture of dry air and water vapor at a total pressure of , the partial pressure of water vapor is . The humidity ratio of the air in…Think it through. Then check your answer.Question
In a mixture of dry air and water vapor at a total pressure of , the partial pressure of water vapor is . The humidity ratio of the air in grams of water vapor per kg of dry air () is __________Correct answer
16.9 to 17.1
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The humidity ratio () of a mixture of dry air and water vapor is calculated using the partial pressures of the components:Where:- is the partial pressure of water vapor ()
- is the total pressure of the mixture ()
To convert this to grams of water vapor per kg of dry air ():
The humidity ratio is approximately .56
Q56NAT2 marksMediumIn a 3-stage air compressor, the inlet pressure is , discharge pressure is and the intermediate pressures are and (). The total pressure ratio of…Think it through. Then check your answer.Question
In a 3-stage air compressor, the inlet pressure is , discharge pressure is and the intermediate pressures are and (). The total pressure ratio of the compressor is 10 and the pressure ratios of the stages are equal. If kPa, the value of the pressure (in kPa) is __________Correct answer
460 to 470
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
For a multi-stage compressor with equal pressure ratios per stage, the stage pressure ratio is given by:
where is the total pressure ratio and is the number of stages.
Given:
Total pressure ratio
Number of stages
So,
The intermediate pressures are:
Substituting the values:
kPa.57
Q57NAT2 marksHardIn the vapour compression cycle shown in the figure, the evaporating and condensing temperatures are 260 K and 310 K, respectively. The compressor takes in liquid-vapour mixture…Think it through. Then check your answer.Question
In the vapour compression cycle shown in the figure, the evaporating and condensing temperatures are 260 K and 310 K, respectively. The compressor takes in liquid-vapour mixture (state 1) and isentropically compresses it to a dry saturated vapour condition (state 2). The specific heat of the liquid refrigerant is 4.8 kJ/kg-K and may be treated as constant. The enthalpy of evaporation for the refrigerant at 310 K is 1054 kJ/kg.
The difference between the enthalpies at state points 1 and 0 (in kJ/kg) is ____________
Correct answer
1095 to 1130
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
From the T-s diagram, state 0 is saturated liquid at K and state 1 is a liquid-vapour mixture at the same temperature. Process 1-2 is isentropic compression to dry saturated vapour at K.
Since process 1-2 is isentropic, .
We need to find the enthalpy difference .
Using the relation for entropy in the mixture region:
The entropy difference can be expanded as:
kJ/kg-K
kJ/kg-K
Total entropy difference: kJ/kg-K
Finally, kJ/kg.58
Q58NAT2 marksMediumSpot welding of two steel sheets each 2 mm thick is carried out successfully by passing 4 kA of current for 0.2 seconds through the electrodes. The resulting weld nugget formed…Think it through. Then check your answer.Question
Spot welding of two steel sheets each 2 mm thick is carried out successfully by passing 4 kA of current for 0.2 seconds through the electrodes. The resulting weld nugget formed between the sheets is 5 mm in diameter. Assuming cylindrical shape for the nugget, the thickness of the nugget is________mm.Property Value Latent heat of fusion for steel 1400 kJ/kg Effective resistance of the weld joint 200 Density of steel 8000 kg/m Correct answer
2.85 to 2.95
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
1.Heat generated ():J.2.Heat required to melt the nugget ():
where mm = 0.005 m, kg/m, kJ/kg = J/kg.
m = 2.91 mm.59
Q59MCQ2 marksMediumFor an orthogonal cutting operation, tool material is HSS, rake angle is , chip thickness is , speed is and feed is .…Think it through. Then check your answer.Question
For an orthogonal cutting operation, tool material is HSS, rake angle is , chip thickness is , speed is and feed is . The shear plane angle (in degrees) isCorrect answer
(B) 29.70
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given:
Rake angle,
Chip thickness,
Feed,
In orthogonal cutting, uncut chip thickness .
Chip thickness ratio,
The shear plane angle is given by:Thus, the correct option is (B).60
Q60NAT2 marksEasyIn a sheet metal of mm thickness a hole of mm diameter needs to be punched. The yield strength in tension of the sheet material is MPa and its ultimate shear…Think it through. Then check your answer.Question
In a sheet metal of mm thickness a hole of mm diameter needs to be punched. The yield strength in tension of the sheet material is MPa and its ultimate shear strength is MPa. The force required to punch the hole (in kN) is __________Correct answer
4.9 to 5.1
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Given:
Thickness of sheet, mm
Diameter of hole, mm
Ultimate shear strength, MPaThe force required to punch a hole is given by the product of the shear area and the ultimate shear strength of the material.
Shear area,
mmForce,
N
NConverting to kN:
kNThe range specified is 4.9 to 5.1 kN.61
Q61NAT2 marksEasyIn a single point turning operation with cemented carbide tool and steel work piece, it is found that the Taylor’s exponent is . If the cutting speed is reduced by …Think it through. Then check your answer.Question
In a single point turning operation with cemented carbide tool and steel work piece, it is found that the Taylor’s exponent is . If the cutting speed is reduced by then the tool life changes by ______ times.Correct answer
14 to 18
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Taylor's tool life equation is given by:
where:
= cutting speed
= tool life
= Taylor's exponent
= constantGiven:
Let initial speed be and initial tool life be .
New speed, From Taylor's equation:
Thus, the tool life increases by 16 times.62
Q62NAT2 marksMediumTwo optically flat plates of glass are kept at a small angle as shown in the figure. Monochromatic light is incident vertically. [figure] If the wavelength of light used…Think it through. Then check your answer.Question
Two optically flat plates of glass are kept at a small angle as shown in the figure. Monochromatic light is incident vertically.If the wavelength of light used to get a fringe spacing of 1 mm is 450 nm, the wavelength of light (in nm) to get a fringe spacing of 1.5 mm is _________
Correct answer
674 to 676
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
The fringe spacing () for an air wedge formed between two glass plates is given by the formula:where:
is the wavelength of the incident light,
is the small angle of the wedge (in radians).Since the wedge angle remains constant for both cases, we can write:Given:
We need to find the new wavelength :The wavelength of light required to get a fringe spacing of 1.5 mm is 675 nm.63
Q63MCQ2 marksMediumA point is translated by and then rotated counter clockwise by about the -axis. The new position of the point isThink it through. Then check your answer.Question
A point is translated by and then rotated counter clockwise by about the -axis. The new position of the point isCorrect answer
(A) (-6, 3, -9)
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
1.Translation: The point is translated by the vector .New coordinates .2.Rotation: Rotation about the -axis by counter-clockwise.The transformation matrix for rotation about -axis by is:For :Alternatively, the mapping is .
So, .The new position is . Correct option is (A).64
Q64MCQ2 marksEasyThe demand for a two-wheeler was units and units in April 2015 and May 2015, respectively. The forecast for the month of April 2015 was units. Considering a…Think it through. Then check your answer.Question
The demand for a two-wheeler was units and units in April 2015 and May 2015, respectively. The forecast for the month of April 2015 was units. Considering a smoothing constant of , the forecast for the month of June 2015 isCorrect answer
(D) 970 units
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Using the exponential smoothing formula: Given:
,
Step 1: Calculate forecast for May 2015 ()
units.Step 2: Calculate forecast for June 2015 ()
units.Correct option is (D).65
Q65NAT2 marksMediumA firm uses a turning center, a milling center and a grinding machine to produce two parts. The table below provides the machining time required for each part and the maximum…Think it through. Then check your answer.Question
A firm uses a turning center, a milling center and a grinding machine to produce two parts. The table below provides the machining time required for each part and the maximum machining time available on each machine. The profit per unit on parts I and II are Rs. 40 and Rs. 100, respectively. The maximum profit per week of the firm is Rs._________Type of machine Machining time required for the machine part (minutes) I Machining time required for the machine part (minutes) II Maximum machining time available per week (minutes) Turning Center 12 6 6000 Milling Center 4 10 4000 Grinding Machine 2 3 1800 Correct answer
39000 to 41000
Turn this into a strength.Explore AI-powered practice and doubt support with Success Tracker.Step-by-step solution
Let and be the number of units of parts I and II produced per week, respectively.The objective is to maximize the total profit:
Maximize Subject to the following constraints based on machine availability:1.Turning Center:2.Milling Center:3.Grinding Machine:4.Non-negativity:To find the maximum profit, we evaluate the objective function at the corner points of the feasible region:- At :
- At (from ):
- At (from ):
- Intersection of and :
Substituting into :
Check this point in the third constraint: (Satisfied)
At : Comparing the values, the maximum profit is Rs. 40,000, which falls within the range of 39000 to 41000.