GATE ME 2018 Set 1 — Question 59
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Manufacturing Processes → Machining & Machine Tools → Merchant's Circle & Forces
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Question
An orthogonal cutting operation is being carried out in which uncut thickness is mm, cutting speed is m/min, rake angle is and width of cut is mm. It is observed that the chip thickness is mm, the cutting force is N and the thrust force is N. The ratio of friction energy to total energy is __________ (correct to two decimal places).
Correct answer
0.39 to 0.49
Solution
Given data:
Uncut chip thickness, mm
Chip thickness, mm
Cutting speed, m/min
Rake angle,
Cutting force, N
Thrust force, NStep 1: Calculate the chip thickness ratio ():
Step 2: Calculate the friction force () acting on the rake face:
NStep 3: Calculate the ratio of friction energy to total energy:
Total energy per unit time (Total Power),
Friction energy per unit time (Friction Power),
Where is the chip velocity, given by .Ratio
Ratio Rounding to two decimal places, the ratio is . This value falls within the official range of to .
Uncut chip thickness, mm
Chip thickness, mm
Cutting speed, m/min
Rake angle,
Cutting force, N
Thrust force, NStep 1: Calculate the chip thickness ratio ():
Step 2: Calculate the friction force () acting on the rake face:
NStep 3: Calculate the ratio of friction energy to total energy:
Total energy per unit time (Total Power),
Friction energy per unit time (Friction Power),
Where is the chip velocity, given by .Ratio
Ratio Rounding to two decimal places, the ratio is . This value falls within the official range of to .
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