GATE ME 2023 Set 1 — Question 52
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Engineering Materials → Structure & Properties → Binary Phase Diagrams & Lever Rule
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Question
A steel sample with 1.5 wt.% carbon (no other alloying elements present) is slowly cooled from 1100 °C to just below the eutectoid temperature (723 °C). In the relevant part of the iron–cementite phase diagram, the eutectoid point is at 0.8 wt.% C and 723 °C, the maximum solubility of carbon in ferrite () at 723 °C is 0.035 wt.% C, and cementite (Fe C) contains 6.7 wt.% C. The ratio of the pro-eutectoid cementite content to the total cementite content in the microstructure that develops just below the eutectoid temperature is ______.(Rounded off to two decimal places)
Correct answer
0.53 to 0.55
Solution
The 1.5 wt.% C steel is hyper-eutectoid, so pro-eutectoid cementite forms between the line and 723 °C.Pro-eutectoid cementite (lever rule just above 723 °C, between austenite at 0.8% C and Fe C at 6.7% C):Total cementite (lever rule just below 723 °C, between ferrite at 0.035% C and Fe C at 6.7% C):Ratio:Answer: 0.54
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