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GATE ME 2023 Set 1
All 65 solved GATE ME 2023 Set 1 questions in exam order. Open a question, commit to an answer, and learn from the step-by-step solution. One question at a time.
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General Aptitude (GA)
101
Q1MCQ1 markEasyHe did not manage to fix the car himself, so he _______ in the garage.Think it through. Then check your answer.Question
He did not manage to fix the car himself, so he _______ in the garage.Correct answer
(A) got it fixed
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The sentence is in the past tense as indicated by "did not manage". The causative structure "get + object + past participle" is used when someone else performs an action for the subject. Therefore, "got it fixed" is the grammatically correct choice to complete the sentence.2
Q2MCQ1 markEasyPlanting : Seed : : Raising : _____ (By word meaning)Think it through. Then check your answer.Question
Planting : Seed : : Raising : _____
(By word meaning)Correct answer
(A) Child
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The analogy follows the relationship of 'Action : Object of growth'. One plants a seed to nurture its growth into a plant. Similarly, one raises a child to nurture their growth into an adult.3
Q3MCQ1 markMediumA certain country has 504 universities and 25951 colleges. These are categorised into Grades I, II, and III as shown in the given pie charts. What is the percentage, correct to…Think it through. Then check your answer.Question
A certain country has 504 universities and 25951 colleges. These are categorised into Grades I, II, and III as shown in the given pie charts. What is the percentage, correct to one decimal place, of higher education institutions (colleges and universities) that fall into Grade III?
Correct answer
(A) 22.7
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1.Calculate the total number of institutions:Total =2.Calculate the number of Grade III Universities:Grade III Universities =3.Calculate the number of Grade III Colleges:Grade III Colleges =4.Calculate the total number of Grade III institutions:Total Grade III =5.Calculate the percentage:Percentage = Rounding to one decimal place, we get .4
Q4MCQ1 markMediumThe minute-hand and second-hand of a clock cross each other ______ times between 09:15:00 AM and 09:45:00 AM on a day.Think it through. Then check your answer.Question
The minute-hand and second-hand of a clock cross each other ______ times between 09:15:00 AM and 09:45:00 AM on a day.Correct answer
(A) 30
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Let's calculate the angular speeds of the minute and second hands.Speed of the minute hand, .Speed of the second hand, .Let be the time in minutes measured from 09:00:00 AM. The time interval in question is from to .The total angle covered by the minute hand from the 12 o'clock position is .
The total angle covered by the second hand from the 12 o'clock position is .The hands cross each other when their total angles covered differ by a multiple of . Let this multiple be .
We need to find the number of integer values of for which lies in the interval .For the lower bound:
For the upper bound:
So, the integer values that can take are .
To find the number of these integer values, we calculate:
Number of values = (Last value) - (First value) + 1
Number of values = .Therefore, the minute-hand and second-hand cross each other 30 times between 09:15:00 AM and 09:45:00 AM.5
Q5MCQ1 markMediumThe symbols O, *, Δ, and □ are to be filled, one in each box, as shown below. [figure] The rules for filling in the four symbols are as follows. 1) Every row and every column must…Think it through. Then check your answer.Question
The symbols O, *, Δ, and □ are to be filled, one in each box, as shown below.The rules for filling in the four symbols are as follows.
1) Every row and every column must contain each of the four symbols.
2) Every 2×2 square delineated by bold lines must contain each of the four symbols.Which symbol will occupy the box marked with ‘?’ in the partially filled figure?Correct answer
(B)
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Let's analyze the constraints on the symbol in the cell marked with '?' based on the provided rules and the partially filled grid.The grid can be interpreted from the image as follows (let G(row, col) be the cell content):- G(1,3) = Δ
- G(2,2) = O
- G(2,3) =
- G(3,1) =
- G(3,4) = □
- G(4,2) = Δ
- G(4,3) = O
- From Column 3, which contains Δ, *, and O, the missing symbol is □. So, G(3,3) must be □.
- Now, consider the Bottom-Right 2x2 square (cells G(3,3), G(3,4), G(4,3), G(4,4)). We have G(3,4)=□ and G(4,3)=O. Our deduction gives G(3,3)=□. This means the 2x2 square contains two □ symbols, which violates Rule 2.
1.Row Constraint: The '?' is in Row 1, which contains Δ. So, ? ≠ Δ.2.Column Constraint: The '?' is in Column 1, which contains at G(3,1). So, ? ≠ .3.2x2 Square Constraint: The '?' is in the top-left 2x2 square, which contains O at G(2,2). So, ? ≠ O.4.Following this direct logic, the only remaining symbol is □. This contradicts the official answer key.The official answer is '*', which can only be reached if one of the premises above is incorrect (i.e., there is a typo in the grid diagram). For instance, if the symbol at G(3,1) was not '*' but '□', the logic would lead to '?' being '*'. Given the ambiguity, the question is considered flawed, but the intended answer was B.6
Q6MCQ2 marksMediumIn a recently held parent-teacher meeting, the teachers had very few complaints about Ravi. After all, Ravi was a hardworking and kind student. Incidentally, almost all of Ravi’s…Think it through. Then check your answer.Question
In a recently held parent-teacher meeting, the teachers had very few complaints about Ravi. After all, Ravi was a hardworking and kind student. Incidentally, almost all of Ravi’s friends at school were hardworking and kind too. But the teachers drew attention to Ravi’s complete lack of interest in sports. The teachers believed that, along with some of his friends who showed similar disinterest in sports, Ravi needed to engage in some sports for his overall development. Based only on the information provided above, which one of the following statements can be logically inferred with certainty?Correct answer
(D) Some of Ravi’s friends are hardworking and kind.
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The passage states that "almost all of Ravi’s friends at school were hardworking and kind too."- (A) cannot be inferred with certainty because "almost all" implies there could be exceptions.
- (B) cannot be inferred because the passage provides no information about people who are not Ravi's friends.
- (C) cannot be inferred because the passage only mentions that "some of his friends" showed a disinterest in sports, not all of them.
- (D) is a certain inference because if "almost all" friends are hardworking and kind, it logically follows that at least "some" of them are.
7
Q7MCQ2 marksMediumConsider the following inequalities where and are positive integers. The value of is _______.Think it through. Then check your answer.Question
Consider the following inequalities where and are positive integers.
The value of is _______.Correct answer
(A) 2
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Given and are positive integers ().
From the second inequality: .
If , then . Since is a positive integer, .
If , then , which makes impossible for positive .
So, the only possible pair is .
Now, check this pair in the first inequality: . Since , the condition is satisfied.
The value of .8
Q8MCQ2 marksEasyWhich one of the sentence sequences in the given options creates a coherent narrative? (i) I could not bring myself to knock. (ii) There was a murmur of unfamiliar voices coming…Think it through. Then check your answer.Question
Which one of the sentence sequences in the given options creates a coherent narrative?(i) I could not bring myself to knock.
(ii) There was a murmur of unfamiliar voices coming from the big drawing room and the door was firmly shut.
(iii) The passage was dark for a bit, but then it suddenly opened into a bright kitchen.
(iv) I decided I would rather wander down the passage.Correct answer
(C) (ii), (i), (iv), (iii)
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The narrative logic follows a sequence of observation, reaction, decision, and result:1.Observation (ii): The narrator hears voices behind a shut door.2.Reaction (i): Because of the shut door and unfamiliar voices, the narrator feels hesitant to knock.3.Decision (iv): Instead of knocking, the narrator chooses to explore the passage.4.Result (iii): The narrator describes the experience of walking through the passage and finding the kitchen.Thus, the sequence (ii), (i), (iv), (iii) is the most coherent.9
Q9MCQ2 marksMediumHow many pairs of sets are possible among the subsets of that satisfy the condition that is a subset of ?Think it through. Then check your answer.Question
How many pairs of sets are possible among the subsets of that satisfy the condition that is a subset of ?Correct answer
(A) 729
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Let the universal set be with .
For any element , there are three mutually exclusive possibilities for its membership in and such that :1. and2. and3. and(The case and is impossible because ).
Since there are elements and each element has 3 independent choices, the total number of pairs is .
For , the number of pairs is .10
Q10MCQ2 marksMediumAn opaque pyramid (shown below), with a square base and isosceles faces, is suspended in the path of a parallel beam of light, such that its shadow is cast on a screen oriented…Think it through. Then check your answer.Question
An opaque pyramid (shown below), with a square base and isosceles faces, is suspended in the path of a parallel beam of light, such that its shadow is cast on a screen oriented perpendicular to the direction of the light beam. The pyramid can be reoriented in any direction within the light beam. Under these conditions, which one of the shadows P, Q, R, and S is NOT possible?
Correct answer
(B) Q
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A square pyramid can produce various shadow shapes depending on its orientation relative to the parallel light beam:1.A square (S) is formed when the light is perpendicular to the base.2.A triangle is formed when the light is parallel to the base and perpendicular to two opposite edges.3.A kite or diamond (R) can be formed by tilting the pyramid.4.A pentagon (P) can be formed if the light beam intersects the base and all four triangular faces.Shape Q, which is a non-symmetric quadrilateral with non-parallel sides in that specific configuration, cannot be formed by the parallel projection of a regular square pyramid.
Mechanical Engineering (ME)
5511
Q11MCQ1 markEasyA machine produces a defective component with a probability of . The number of defective components in a packed box containing components produced by the machine…Think it through. Then check your answer.Question
A machine produces a defective component with a probability of . The number of defective components in a packed box containing components produced by the machine follows a Poisson distribution. The mean and the variance of the distribution areCorrect answer
(A) 3 and 3, respectively
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For a binomial distribution with large and small , it can be approximated by a Poisson distribution where the parameter .
Given:
Mean () of Poisson distribution = .A key property of the Poisson distribution is that its mean is equal to its variance.
Variance () = .Therefore, the mean and variance are and , respectively.12
Q12MCQ1 markEasyThe figure shows the plot of a function over the interval . Which one of the options given CORRECTLY identifies the function? [figure] ]Think it through. Then check your answer.Question
The figure shows the plot of a function over the interval . Which one of the options given CORRECTLY identifies the function?]
Correct answer
(B) 2 - x
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We can identify the correct function by testing key points from the provided graph:- At , .
- At , .
- At , .
- At , .
- At , .
- (Matches)
- (Matches)
- (Matches)
- (Matches)
- (Matches)
13
Q13MCQ1 markEasyWith reference to the Economic Order Quantity (EOQ) model, which one of the options given is correct? [figure]Think it through. Then check your answer.Question
With reference to the Economic Order Quantity (EOQ) model, which one of the options given is correct?
Correct answer
(A) Curve P1: Total cost, Curve P2: Holding cost, Curve P3: Setup cost, and Curve P4: Production cost.
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In the Economic Order Quantity (EOQ) model, the total cost is the sum of ordering cost, holding cost, and unit cost.1.Total Cost (Curve P1): . It is a U-shaped curve representing the sum of all costs.2.Holding Cost (Curve P2): . It is a linear function of starting from the origin, as holding cost increases with inventory level.3.Setup/Ordering Cost (Curve P3): . It is a rectangular hyperbola, as ordering cost per unit decreases with larger order quantities.4.Production/Unit Cost (Curve P4): . It is a constant value independent of order quantity, represented by a horizontal line.Therefore, Option (A) correctly identifies all curves.14
Q14MCQ1 markEasyWhich one of the options given represents the feasible region of the linear programming model: …Think it through. Then check your answer.Question
Which one of the options given represents the feasible region of the linear programming model:
Correct answer
(B) Region Q
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To find the feasible region, we plot the boundary lines for each constraint and determine the half-plane satisfied by the inequality:1.Constraint 1: . This is the region to the left of the vertical line .2.Constraint 2: . This is the region below the horizontal line .3.Constraint 3: . The line has intercepts at and . The inequality represents the region above and to the right of this line.4.Constraint 4: . The line has intercepts at and . The inequality represents the region below and to the left of this line.Intersection Analysis:- The intersection of , , and forms a triangular region.
- Vertices of this triangle:
- Intersection of and :
- Intersection of and :
- Intersection of and :
- All these points satisfy , making that constraint redundant for this specific intersection.
- Comparing this with the provided graph, the region bounded by these vertices is labeled as Region Q.
15
Q15MCQ1 markMediumA cuboidal part has to be accurately positioned first, arresting six degrees of freedom and then clamped in a fixture, to be used for machining. Locating pins in the form of…Think it through. Then check your answer.Question
A cuboidal part has to be accurately positioned first, arresting six degrees of freedom and then clamped in a fixture, to be used for machining. Locating pins in the form of cylinders with hemi-spherical tips are to be placed on the fixture for positioning. Four different configurations of locating pins are proposed as shown. Which one of the options given is correct?
Correct answer
(A) Configuration P1 arrests 6 degrees of freedom, while Configurations P2 and P4 are over-constrained and Configuration P3 is under-constrained.
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The 3-2-1 principle of location is used to arrest all 6 degrees of freedom (3 translations and 3 rotations) of a cuboidal part:- 3 pins on the primary datum surface arrest 3 DOF (1 translation along the normal axis, 2 rotations about the axes in the plane).
- 2 pins on the secondary datum surface arrest 2 DOF (1 translation, 1 rotation).
- 1 pin on the tertiary datum surface arrests the final 1 DOF (1 translation).
- Configuration P1: Uses exactly 3 pins on the bottom, 2 on the side, and 1 on the back. This follows the 3-2-1 principle and arrests exactly 6 DOF.
- Configuration P2: Uses 3 pins on the bottom, 3 on the side, and 1 on the back (7 pins total). It is over-constrained.
- Configuration P3: Uses 2 pins on each of the three faces (6 pins total). While it has 6 pins, it does not provide a stable 3-point contact for a primary plane, making it under-constrained/unstable for precise location.
- Configuration P4: Uses 3 pins on each of the three faces (9 pins total). It is highly over-constrained.
16
Q16MCQ1 markEasyThe effective stiffness of a cantilever beam of length and flexural rigidity subjected to a transverse tip load is [figure]Think it through. Then check your answer.Question
The effective stiffness of a cantilever beam of length and flexural rigidity subjected to a transverse tip load is
Correct answer
(A) (3EI)/(L³)
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The deflection at the free end of a cantilever beam of length and flexural rigidity under a tip load is given by:The effective stiffness is defined as the load per unit deflection:Therefore, the correct option is (A).17
Q17MCQ1 markMediumThe options show frames consisting of rigid bars connected by pin joints. Which one of the frames is non-rigid?Think it through. Then check your answer.Question
The options show frames consisting of rigid bars connected by pin joints. Which one of the frames is non-rigid?Correct answer
(C) [figure]
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A frame is considered rigid if it cannot change its shape without changing the length of its members. For a 2D truss with joints and members, a necessary condition for rigidity is . However, the members must also be arranged such that no part of the frame forms a mechanism.1.Option (A): , . . Since and the panels are triangulated, it is rigid.2.Option (B): , . . Since and the panels are triangulated, it is rigid.3.Option (C): , . . Although , the middle panel is a rectangle with four pin joints and no diagonal member. This panel can undergo shear deformation (parallelogram mechanism), making the entire frame non-rigid.4.Option (D): , . . Since and every panel is triangulated, it is a rigid and statically determinate truss.Therefore, frame (C) is non-rigid.18
Q18MCQ1 markEasyThe S-N curve from a fatigue test for steel is shown. Which one of the options gives the endurance limit? [figure]Think it through. Then check your answer.Question
The S-N curve from a fatigue test for steel is shown. Which one of the options gives the endurance limit?
Correct answer
(D) S₄
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The endurance limit () is the stress level below which a material can withstand an infinite number of cycles without failure. On an S-N curve for ferrous materials like steel, this is represented by the horizontal asymptotic portion of the curve. In the provided figure, the curve becomes horizontal at the stress level . Thus, is the endurance limit.19
Q19MCQ1 markMediumAir (density = , kinematic viscosity = ) flows over a flat plate with a free-stream velocity of . The wall…Think it through. Then check your answer.Question
Air (density = , kinematic viscosity = ) flows over a flat plate with a free-stream velocity of . The wall shear stress at a location from the leading edge is . What is the wall shear stress at a location from the leading edge?Correct answer
(D) τ_w / √(2)
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For laminar flow over a flat plate, the wall shear stress is given by the Blasius solution: . Since , we have .
Given at , we need to find at .20
Q20MCQ1 markMediumConsider an isentropic flow of air (ratio of specific heats = ) through a duct as shown in the figure. The variations in the flow across the cross-section are negligible. The…Think it through. Then check your answer.Question
Consider an isentropic flow of air (ratio of specific heats = ) through a duct as shown in the figure. The variations in the flow across the cross-section are negligible. The flow conditions at Location 1 are given as follows: , , The duct cross-sectional area at Location 2 is given by , where denotes the duct cross-sectional area at Location 1. Which one of the given statements about the velocity and pressure at Location 2 is TRUE?
Correct answer
(C) u₂ u₁, P₂ < P₁
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First, determine the Mach number at Location 1. The speed of sound is .
The Mach number . Since , the flow is supersonic.
For supersonic flow in a diverging duct (), the area-velocity relation implies that , so .
From the isentropic relation or Bernoulli's equation for compressible flow, an increase in velocity leads to a decrease in pressure, so .21
Q21MCQ1 markEasyConsider incompressible laminar flow of a constant property Newtonian fluid in an isothermal circular tube. The flow is steady with fully-developed temperature and velocity…Think it through. Then check your answer.Question
Consider incompressible laminar flow of a constant property Newtonian fluid in an isothermal circular tube. The flow is steady with fully-developed temperature and velocity profiles. The Nusselt number for this flow depends onCorrect answer
(A) neither the Reynolds number nor the Prandtl number
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For fully developed laminar flow in a circular tube with constant surface temperature (isothermal), the Nusselt number is a constant value: . It does not depend on the Reynolds number () or the Prandtl number ().22
Q22MCQ1 markMediumA heat engine extracts heat () from a thermal reservoir at a temperature of and rejects heat () to a thermal reservoir at a temperature of…Think it through. Then check your answer.Question
A heat engine extracts heat () from a thermal reservoir at a temperature of and rejects heat () to a thermal reservoir at a temperature of , while producing work (). Which one of the combinations of [] given is allowed?Correct answer
(B) Q_H = 2000 J, Q_L = 750 J, W = 1250 J
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For a heat engine to be allowed, it must satisfy both the First and Second Laws of Thermodynamics.1.First Law of Thermodynamics:2.Second Law of Thermodynamics (Carnot's Theorem): The efficiency must be less than or equal to the reversible efficiency .Given and , the maximum possible efficiency is:Checking the options:- (A): . Since , it violates the First Law.
- (B): . First Law is satisfied. Efficiency . Since , the Second Law is also satisfied. This combination is allowed.
- (C): . First Law is satisfied. Efficiency . Since , it violates the Second Law.
- (D): . Since , it violates the First Law.
23
Q23MSQ1 markEasyTwo surfaces P and Q are to be joined together. In which of the given joining operation(s), there is no melting of the two surfaces P and Q for creating the joint?Think it through. Then check your answer.Question
Two surfaces P and Q are to be joined together. In which of the given joining operation(s), there is no melting of the two surfaces P and Q for creating the joint?Correct answer
(B) Brazing; (C) Adhesive bonding
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Joining processes can be classified based on whether the base metals melt:- Arc welding: Uses an electric arc to melt both the base metal and the filler metal to form a pool that solidifies into a joint.
- Brazing: A joining process where a filler metal is melted and distributed between two or more close-fitting parts by capillary action. The base metal itself is not melted.
- Adhesive bonding: Uses a non-metallic substance (adhesive) to join surfaces. No melting of the base surfaces occurs.
- Spot welding: A type of resistance welding where heat is generated by electrical resistance at the interface, causing localized melting (a nugget) of the base metals.
24
Q24MSQ1 markMediumA beam is undergoing pure bending as shown in the figure. The stress ()-strain () curve for the material is also given. The yield stress of the material is…Think it through. Then check your answer.Question
A beam is undergoing pure bending as shown in the figure. The stress ()-strain () curve for the material is also given. The yield stress of the material is . Which of the option(s) given represent(s) the bending stress distribution at cross-section AA after plastic yielding?
Correct answer
(C) [figure]; (D) [figure]
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In pure bending, the strain distribution across the cross-section remains linear. For an elastic-perfectly plastic material:1.Initial Yielding: When the strain at the outermost fibers reaches the yield strain , the stress reaches .2.Elastic-Plastic State: As the bending moment increases further, more fibers from the outside inward reach the yield strain. Because the material is perfectly plastic, the stress in these yielded fibers remains constant at . This results in a trapezoidal stress distribution, as shown in option (D).3.Fully Plastic State: In the limit, as the moment approaches the plastic moment , the entire cross-section (except the neutral axis) yields. The stress distribution becomes rectangular (constant in tension and compression), as shown in option (C).Options (A) and (B) show linear distributions with maximum stresses less than , which represent purely elastic states before yielding begins.25
Q25MSQ1 markMediumIn a metal casting process to manufacture parts, both patterns and moulds provide shape by dictating where the material should or should not go. Which of the option(s) given…Think it through. Then check your answer.Question
In a metal casting process to manufacture parts, both patterns and moulds provide shape by dictating where the material should or should not go. Which of the option(s) given correctly describe(s) the mould and the pattern?Correct answer
(A) Mould walls indicate boundaries within which the molten part material is allowed, while pattern walls indicate boundaries of regions where mould material is not allowed.; (B) Moulds can be used to make patterns.; (D) Patterns can be used to make moulds.
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In a metal casting process:- A mould is a container that has a cavity of the desired shape. Its walls define the boundaries within which the molten metal is allowed to flow and solidify.
- A pattern is a replica of the object to be cast. It is used to create the mould cavity. Its walls define the boundaries of the regions where the mould material (like sand) is excluded during the packing process.
- Option (A) is correct as it accurately describes these roles.
- Option (B) is correct because in certain processes like investment casting, a master mould is used to produce wax patterns.
- Option (D) is correct as it is the standard definition of a pattern in sand casting.
- Option (C) is incorrect because it swaps the definitions of pattern and mould.
26
Q26MSQ1 markMediumThe principal stresses at a point P in a solid are MPa, MPa and . The yield stress of the material is MPa. Which prediction(s) about material failure at P…Think it through. Then check your answer.Question
The principal stresses at a point P in a solid are MPa, MPa and . The yield stress of the material is MPa. Which prediction(s) about material failure at P is/are CORRECT?Correct answer
(B) Maximum shear stress theory predicts that the material fails; (C) Maximum normal stress theory predicts that the material does not fail
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Given principal stresses: MPa, MPa, MPa.
Yield stress of the material: MPa.We need to check the predictions of material failure using two common theories:1. Maximum Normal Stress Theory (Rankine's Theory):
According to this theory, failure occurs if the maximum principal stress (in magnitude) exceeds the yield strength of the material. MPa
MPa
MPaThe maximum absolute principal stress is MPa.
Since , the material does not fail according to the Maximum Normal Stress Theory.Therefore, option (A) is incorrect, and option (C) is correct.2. Maximum Shear Stress Theory (Tresca's Theory):
According to this theory, failure occurs if the maximum shear stress in the material exceeds half the yield strength in uniaxial tension (which is the yield shear strength, ).The maximum shear stress is given by:
Let's calculate the three possible shear stresses:
MPa
MPa
MPaSo, MPa.Now, calculate the yield shear strength:
MPa.Since , the material fails according to the Maximum Shear Stress Theory.Therefore, option (B) is correct, and option (D) is incorrect.Combining the results, the correct predictions are that the material fails by Maximum Shear Stress Theory and does not fail by Maximum Normal Stress Theory.The final answer is27
Q27MSQ1 markMediumWhich of the plot(s) shown is/are valid Mohr’s circle representations of a plane stress state in a material? (The center of each circle is indicated by .) [figure]Think it through. Then check your answer.Question
Which of the plot(s) shown is/are valid Mohr’s circle representations of a plane stress state in a material? (The center of each circle is indicated by .)
Correct answer
(A) M1; (C) M3
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For a plane stress state, the center of the Mohr's circle must always lie on the horizontal axis (the normal stress -axis). The coordinates of the center are given by , where . Since the shear stress at the center of the circle must be zero, the center cannot be offset vertically from the -axis.- In M1, the center is on the -axis. This is a valid representation.
- In M2, the center is located above the -axis. This is invalid.
- In M3, the center is on the -axis. This is a valid representation.
- In M4, the center is located above the -axis. This is invalid.
28
Q28MSQ1 markMediumConsider a laterally insulated rod of length and constant thermal conductivity. Assuming one-dimensional heat conduction in the rod, which of the following steady-state…29
Q29NAT1 markMediumTwo meshing spur gears 1 and 2 with diametral pitch of 8 teeth per mm and an angular velocity ratio , have their centers 30 mm apart. The number of…Think it through. Then check your answer.Question
Two meshing spur gears 1 and 2 with diametral pitch of 8 teeth per mm and an angular velocity ratio , have their centers 30 mm apart. The number of teeth on the driver (gear 1) is _______ .Correct answer
95.999 to 96.001
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Given:
Diametral pitch, teeth/mm
Velocity ratio, (since )
Center distance, mmThe center distance for meshing gears is given by:Since the velocity ratio is 4, the pitch circle diameters are related by:Substituting in the center distance equation:The number of teeth on the driver (gear 1) is:30
Q30NAT1 markEasyThe figure shows a block of mass attached to a pair of identical linear springs, each having a spring constant . The block oscillates on a…Think it through. Then check your answer.Question
The figure shows a block of mass attached to a pair of identical linear springs, each having a spring constant . The block oscillates on a frictionless horizontal surface. Assuming free vibrations, the time taken by the block to complete ten oscillations is _________ seconds. (Rounded off to two decimal places)Take .
Correct answer
6.27 to 6.29
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Given:
Mass of the block,
Spring constant of each spring,
Number of oscillations, The two springs are connected in parallel as they share the same displacement. Therefore, the equivalent spring constant () is:The natural frequency of the system is:The time period for one oscillation is:The time taken for ten oscillations is:Thus, the time taken is seconds.31
Q31NAT1 markMediumA vector field is defined over a conical region having height , base radius and axis along , as…Think it through. Then check your answer.Question
A vector fieldis defined over a conical region having height , base radius and axis along , as shown in the figure. The base of the cone lies in the - plane and is centered at the origin. If denotes the unit outward normal to the curved surface of the cone, the value of the integralequals _________ . (Answer in integer)Correct answer
0.001 to 0.001
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According to the Gauss Divergence Theorem, the total outward flux of a vector field through a closed surface is equal to the volume integral of the divergence of over the region enclosed by the surface:First, calculate the divergence of :Since the divergence is zero everywhere, the total flux through the closed surface (consisting of the curved surface and the base ) is zero:On the base , the surface lies in the - plane () and the outward unit normal is .Thus, the flux through the base is:Substituting this back into the total flux equation:The value of the integral is 0.32
Q32NAT1 markMediumA linear transformation maps a point in the plane to the point according to the rule Then, the disc…Think it through. Then check your answer.Question
A linear transformation maps a point in the plane to the point according to the ruleThen, the disc gets transformed to a region with an area equal to
_________ . (Rounded off to two decimals)Use .Correct answer
18.8 to 18.9
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The given linear transformation is:This can be represented in matrix form as:Let . The determinant of is:The area of a region transformed by a linear transformation is given by:The original region is the disc , which has a radius . Its area is:Using :The transformed area is 18.84.33
Q33NAT1 markMediumThe value of that makes the complex-valued function analytic, where , is _________. (Answer in integer)Think it through. Then check your answer.Question
The value of that makes the complex-valued functionanalytic, where , is _________.(Answer in integer)Correct answer
1.999 to 2.001
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Let . From the given expression:So, and .
For to be analytic, it must satisfy the Cauchy-Riemann equations:
1)
2) Calculating the partial derivatives:From (1): .Check the second condition:From (2): .Thus, makes the function analytic.34
Q34NAT1 markMediumThe braking system shown in the figure uses a belt to slow down a pulley rotating in the clockwise direction by the application of a force P. The belt wraps around the pulley…Think it through. Then check your answer.Question
The braking system shown in the figure uses a belt to slow down a pulley rotating in the clockwise direction by the application of a force P. The belt wraps around the pulley over an angle degrees. The coefficient of friction between the belt and the pulley is 0.3. The influence of centrifugal forces on the belt is negligible.During braking, the ratio of the tensions to in the belt is equal to __________. (Rounded off to two decimal places)Take .
Correct answer
4.05 to 4.15
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Given:- Coefficient of friction,
- Angle of wrap,
- Pulley rotation: Clockwise
35
Q35NAT1 markMediumConsider a counter-flow heat exchanger with the inlet temperatures of two fluids (1 and 2) being K and K. The heat capacity rates of the two…36
Q36MCQ2 marksEasyWhich one of the options given is the inverse Laplace transform of ? denotes the unit-step function.Think it through. Then check your answer.Question
Which one of the options given is the inverse Laplace transform of ? denotes the unit-step function.Correct answer
(A) (-1 + (1)/(2) e^(-t) + (1)/(2) e^t) u(t)
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Let .
Using partial fraction decomposition:Solving for coefficients:
Taking the inverse Laplace transform:This matches option (A).37
Q37MCQ2 marksHardA spherical ball weighing 2 kg is dropped from a height of 4.9 m onto an immovable rigid block as shown in the figure. If the collision is perfectly elastic, what is the momentum…Think it through. Then check your answer.Question
A spherical ball weighing 2 kg is dropped from a height of 4.9 m onto an immovable rigid block as shown in the figure. If the collision is perfectly elastic, what is the momentum vector of the ball (in kg m/s) just after impact?Take the acceleration due to gravity to be . Options have been rounded off to one decimal place.
Correct answer
(C) 17.0 i + 9.8 j
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1.Velocity of the ball just before impact: . The velocity vector is .2.Momentum just before impact: .3.The surface is inclined at to the horizontal. The unit normal vector to the surface (pointing outwards) is .4.For a perfectly elastic collision with an immovable object, the momentum after impact is given by:5.Calculate the dot product: .6.Substitute back:.38
Q38MCQ2 marksHardThe figure shows a wheel rolling without slipping on a horizontal plane with angular velocity . A rigid bar PQ is pinned to the wheel at P while the end Q slides on the…Think it through. Then check your answer.Question
The figure shows a wheel rolling without slipping on a horizontal plane with angular velocity . A rigid bar PQ is pinned to the wheel at P while the end Q slides on the floor.What is the angular velocity of the bar PQ?
Correct answer
(D) ω₂ = 0.25ω₁
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1.Let the contact point of the wheel with the floor be R. Since it rolls without slipping, R is the instantaneous center of rotation (ICR) of the wheel. .2.Velocity of point P: . From the diagram, P is at relative to R at . So ..3.Velocity of point Q: Since Q slides on the floor, .4.Kinematics of bar PQ: .From the diagram, . Let .
.5.Equating the components: .39
Q39MCQ2 marksMediumA beam of length is loaded in the -plane by a uniformly distributed load, and by a concentrated tip load parallel to the -axis, as shown in the figure. The resulting…Think it through. Then check your answer.Question
A beam of length is loaded in the -plane by a uniformly distributed load, and by a concentrated tip load parallel to the -axis, as shown in the figure. The resulting bending moment distributions about the and the axes are denoted by and , respectively.Which one of the options given depicts qualitatively CORRECT variations of and along the length of the beam?
Correct answer
(B) [figure]
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1.Identify the loads and their planes:- The uniformly distributed load acts in the -plane (downwards in the direction). This load creates a bending moment about the -axis ().
- The concentrated tip load acts parallel to the -axis (in the direction). This load creates a bending moment about the -axis ().
- For a cantilever beam with a UDL , the bending moment at a distance from the fixed end is given by .
- This is a second-order (parabolic) variation.
- At , . At , . The curve is concave downwards.
- For a cantilever beam with a tip load in the -direction, the bending moment at a distance from the fixed end is given by (using standard sign conventions for internal moments).
- This is a first-order (linear) variation.
- At , . At , .
- must be linear and must be parabolic. This matches the qualitative shapes in Option B, where is a triangle (linear) and is a parabola.
40
Q40MCQ2 marksHardThe figure shows a thin-walled open-top cylindrical vessel of radius and wall thickness . The vessel is held along the brim and contains a constant-density liquid to height…Think it through. Then check your answer.Question
The figure shows a thin-walled open-top cylindrical vessel of radius and wall thickness . The vessel is held along the brim and contains a constant-density liquid to height from the base. Neglect atmospheric pressure, the weight of the vessel and bending stresses in the vessel walls. Which one of the plots depicts qualitatively CORRECT dependence of the magnitudes of axial wall stress () and circumferential wall stress () on ?
Correct answer
(A) [figure]
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1.Circumferential (Hoop) Stress (): The pressure at a depth from the free surface (brim) is . The hoop stress is given by . This is a linear function of that is zero at the brim () and maximum at the base ().2.Axial Stress (): Since the vessel is held at the brim, the wall at any depth must support the total weight of the liquid and the base below it. The total weight of the liquid is . Neglecting the vessel's weight, the axial force in the wall is constant throughout its height: . The axial stress is . This is constant with respect to .3.Intersection: Setting gives .Thus, plot (A) correctly depicts a constant and a linearly increasing that intersect at .41
Q41MCQ2 marksMediumWhich one of the following statements is FALSE?Think it through. Then check your answer.Question
Which one of the following statements is FALSE?Correct answer
(B) For a real gas going through an adiabatic reversible process, the process equation is given by PV^γ = constant, where P is the pressure, V is the volume and γ is the ratio of the specific heats of the gas at constant pressure and constant volume.
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(A) is TRUE: For an ideal gas, enthalpy . Since internal energy is a function of temperature only, is also a function of temperature only and independent of pressure.
(B) is FALSE: The relation is derived specifically for an ideal gas undergoing a reversible adiabatic process. It does not generally hold for real gases.
(C) is TRUE: is simply the ideal gas law rearranged. This equation of state holds at every point for an ideal gas regardless of the process.
(D) is TRUE: Real gases approach ideal behavior in the limit of low density, which occurs at very low pressures or very high temperatures.42
Q42MCQ2 marksMediumConsider a fully adiabatic piston-cylinder arrangement as shown in the figure. The piston is massless and cross-sectional area of the cylinder is . The fluid inside the…Think it through. Then check your answer.Question
Consider a fully adiabatic piston-cylinder arrangement as shown in the figure. The piston is massless and cross-sectional area of the cylinder is . The fluid inside the cylinder is air (considered as a perfect gas), with being the ratio of the specific heat at constant pressure to the specific heat at constant volume for air. The piston is initially located at a position . The initial pressure of the air inside the cylinder is , where is the atmospheric pressure. The stop is instantaneously removed and the piston moves to the position , where the equilibrium pressure of air inside the cylinder is . What is the work done by the piston on the atmosphere during this process?
Correct answer
(B) P₀ A(L₂ - L₁)
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The work done by the piston on the atmosphere is the work done against the constant external atmospheric pressure .
The volume change of the atmosphere is .
Since the atmospheric pressure is constant, the work done on the atmosphere is:Note: Option D represents the work done by the gas inside the cylinder, not the work done on the atmosphere.43
Q43MCQ2 marksMediumA cylindrical rod of length and diameter is placed inside a cubic enclosure of side length . denotes the inner surface of the cube. The view-factor isThink it through. Then check your answer.Question
A cylindrical rod of length and diameter is placed inside a cubic enclosure of side length . denotes the inner surface of the cube. The view-factor isCorrect answer
(D) 1 - ((π dh + π d²/2))/(6L²)
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Let be the surface area of the cylindrical rod and be the inner surface area of the cubic enclosure.
From the summation rule for the enclosure (surface 2): , where is the required view factor .
Using the reciprocity theorem:
Since the rod is completely enclosed by the cube, all radiation leaving the rod must strike the inner surface of the cube, so .
Therefore, .44
Q44MCQ2 marksHardIn an ideal orthogonal cutting experiment (see figure), the cutting speed is , the rake angle of the tool , and the shear angle, , is…Think it through. Then check your answer.Question
In an ideal orthogonal cutting experiment (see figure), the cutting speed is , the rake angle of the tool , and the shear angle, , is known to be . Applying the ideal orthogonal cutting model, consider two shear planes and close to each other. As they approach the thin shear zone (shown as a thick line in the figure), plane gets sheared with respect to (point shears to , and shears to ). Assuming that the perpendicular distance between and is , what is the value of shear strain rate (in ) that the material undergoes at the shear zone?Correct answer
(B) 5.20 × 10⁴
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The shear strain rate is given by the ratio of shear velocity to the shear zone thickness :The shear velocity in orthogonal cutting is related to the cutting speed by:Given:
Calculating :Calculating :Rounding to two decimal places, we get .45
Q45MCQ2 marksMediumA CNC machine has one of its linear positioning axes as shown in the figure, consisting of a motor rotating a lead screw, which in turn moves a nut horizontally on which a table…Think it through. Then check your answer.Question
A CNC machine has one of its linear positioning axes as shown in the figure, consisting of a motor rotating a lead screw, which in turn moves a nut horizontally on which a table is mounted. The motor moves in discrete rotational steps of steps per revolution. The pitch of the screw is and the total horizontal traverse length of the table is . What is the total number of controllable locations at which the table can be positioned on this axis?Correct answer
(C) 1000
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The resolution or Basic Length Unit (BLU) of the system is the distance moved per step:The total number of controllable locations (discrete steps) over the traverse length is:Alternatively, calculate the total revolutions and multiply by steps per revolution:46
Q46MSQ2 marksHardCylindrical bars P and Q have identical lengths and radii, but are composed of different linear elastic materials. The Young’s modulus and coefficient of thermal expansion of Q…Think it through. Then check your answer.Question
Cylindrical bars P and Q have identical lengths and radii, but are composed of different linear elastic materials. The Young’s modulus and coefficient of thermal expansion of Q are twice the corresponding values of P. Assume the bars to be perfectly bonded at the interface, and their weights to be negligible.The bars are held between rigid supports as shown in the figure and the temperature is raised by . Assume that the stress in each bar is homogeneous and uniaxial. Denote the magnitudes of stress in P and Q by and , respectively.Which of the statement(s) given is/are CORRECT?
Correct answer
(A) The interface between P and Q moves to the left after heating; (D) σ₁ = σ₂
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1.Stress Equality: Since the bars are in series between two rigid supports, the axial force must be the same in both bars. Given they have identical radii (and thus identical cross-sectional areas ), the stress must be equal in both bars. Therefore, . (Option D is correct).2.Interface Displacement: Let be the length of each bar. Let and be the Young's modulus and thermal expansion coefficient for bar P. Then for bar Q, and .Total deformation is zero: .
.Let be the displacement of the interface to the right. Then :
.
Since is negative, the interface moves to the left. (Option A is correct).47
Q47MSQ2 marksMediumA very large metal plate of thickness and thermal conductivity is cooled by a stream of air at temperature with a heat transfer coefficient ,…Think it through. Then check your answer.Question
A very large metal plate of thickness and thermal conductivity is cooled by a stream of air at temperature with a heat transfer coefficient , as shown in the figure. The centerline temperature of the plate is . In which of the following case(s) can the lumped parameter model be used to study the heat transfer in the metal plate?
Correct answer
(A) h = 10 Wm⁻²K⁻¹, k = 100 Wm⁻¹K⁻¹, d = 1 mm, T_P = 350 K; (C) h = 100 Wm⁻²K⁻¹, k = 1000 Wm⁻¹K⁻¹, d = 1 mm, T_P = 325 K
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The lumped parameter model is valid when the Biot number . For a large plate of thickness cooled from both sides, the characteristic length is .
.- Case (A): . (Valid)
- Case (B): . (Invalid)
- Case (C): . (Valid)
- Case (D): . (Invalid)
48
Q48NAT2 marksEasyThe smallest perimeter that a rectangle with area of 4 square units can have is ______ units.Think it through. Then check your answer.Question
The smallest perimeter that a rectangle with area of 4 square units can have is ______ units.Correct answer
7.999 to 8.001
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Let the sides of the rectangle be and .
Area .
Perimeter .
To find the minimum perimeter, differentiate with respect to and set to zero:
.
Then . The rectangle is a square.
Smallest perimeter units.49
Q49NAT2 marksMediumConsider the second-order linear ordinary differential equation with the initial conditions…Think it through. Then check your answer.Question
Consider the second-order linear ordinary differential equationwith the initial conditionsThe value of at equals _________.Correct answer
8.999 to 9.001
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The given equation is a Cauchy-Euler equation of the form .
Substituting , we get the characteristic equation:
The general solution is .
Using the initial conditions:
1)
2)
Solving the system of equations:
Thus, the specific solution is .
At :
.50
Q50NAT2 marksMediumThe initial value problem is solved numerically using the forward Euler’s method with a constant and positive time step of .…Think it through. Then check your answer.Question
The initial value problemis solved numerically using the forward Euler’s method with a constant and positive time step of .
Let represent the numerical solution obtained after steps. The condition is satisfied if and only if does not exceed _____________.Correct answer
0.999 to 1.001
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The forward Euler method for the ODE is given by:
Here, . Substituting this into the Euler formula:
The condition for stability (non-increasing solution magnitude) is , which implies:
Subtracting 1 from all sides:
Dividing by -2 (and reversing the inequalities):
Since is a positive time step, the condition is . Thus, must not exceed 1.51
Q51NAT2 marksMediumThe atomic radius of a hypothetical face-centered cubic (FCC) metal is nm. The atomic weight of the metal is 24.092 g/mol. Taking Avogadro’s number to be…Think it through. Then check your answer.Question
The atomic radius of a hypothetical face-centered cubic (FCC) metal is nm. The atomic weight of the metal is 24.092 g/mol. Taking Avogadro’s number to be atoms/mol, the density of the metal is ________ kg/m.Correct answer
2490 to 2510
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For a face-centered cubic (FCC) crystal structure:1.The number of atoms per unit cell is .2.The relationship between the lattice parameter and the atomic radius is given by:Given nm, we calculate :3.The density is calculated using the formula:Where:52
Q52NAT2 marksHardA steel sample with 1.5 wt.% carbon (no other alloying elements present) is slowly cooled from 1100 °C to just below the eutectoid temperature (723 °C). A part of the…Think it through. Then check your answer.Question
A steel sample with 1.5 wt.% carbon (no other alloying elements present) is slowly cooled from 1100 °C to just below the eutectoid temperature (723 °C). A part of the iron-cementite phase diagram is shown in the figure. The ratio of the pro-eutectoid cementite content to the total cementite content in the microstructure that develops just below the eutectoid temperature is ______.(Rounded off to two decimal places)
Correct answer
0.53 to 0.55
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The given steel sample has 1.5 wt.% carbon, which is a hypereutectoid steel since its carbon content is greater than the eutectoid composition of 0.8 wt.% C.When this steel is slowly cooled, it undergoes the following transformations:1.Above the Acm line (the line separating the phase from the + Fe3C phase), the steel is entirely in the austenite () phase.2.As it cools and crosses the Acm line, pro-eutectoid cementite (Fe3C) starts to precipitate at the austenite grain boundaries.3.At the eutectoid temperature (723 °C), the remaining austenite transforms into pearlite, which is a mixture of ferrite () and eutectoid cementite.We need to find the ratio of the mass fraction of pro-eutectoid cementite to the total cementite. We will use the lever rule on the provided phase diagram.From the diagram:- Overall carbon composition, wt.%
- Carbon composition of ferrite () at 723°C, wt.%
- Carbon composition of austenite () at 723°C, wt.%
- Carbon composition of cementite (Fe3C), wt.%
This is calculated just below the eutectoid temperature (723 °C), where the phases are ferrite () and cementite (Fe3C).
Using the lever rule:W_{\text{total_cem}} = \frac{C_0 - C_\alpha}{C_{\text{Fe}_3\text{C}} - C_\alpha} = \frac{1.5 - 0.035}{6.7 - 0.035} = \frac{1.465}{6.665} \approx 0.2198 Step 2: Calculate the mass fraction of pro-eutectoid cementite (W_{\text{pro_cem}})
This is the cementite that forms above the eutectoid temperature. We calculate its mass fraction by applying the lever rule just above 723 °C, where the phases are austenite () and pro-eutectoid cementite (Fe3C).W_{\text{pro_cem}} = \frac{C_0 - C_\gamma}{C_{\text{Fe}_3\text{C}} - C_\gamma} = \frac{1.5 - 0.8}{6.7 - 0.8} = \frac{0.7}{5.9} \approx 0.1186 Step 3: Calculate the required ratio
The ratio of pro-eutectoid cementite to total cementite is:\text{Ratio} = \frac{W_{\text{pro_cem}}}{W_{\text{total_cem}}} = \frac{0.1186}{0.2198} \approx 0.53958 Rounding off to two decimal places, the ratio is 0.54.The official answer range is 0.53 to 0.55.53
Q53NAT2 marksHardA part, produced in high volumes, is dimensioned as shown. The machining process making this part is known to be statistically in control based on sampling data. The sampling data…Think it through. Then check your answer.Question
A part, produced in high volumes, is dimensioned as shown. The machining process making this part is known to be statistically in control based on sampling data. The sampling data shows that D1 follows a normal distribution with a mean of 20 mm and a standard deviation of 0.3 mm, while D2 follows a normal distribution with a mean of 35 mm and a standard deviation of 0.4 mm. An inspection of dimension C is carried out in a sufficiently large number of parts.To be considered under six-sigma process control, the upper limit of dimension C should be __________ mm.(Rounded off to one decimal place)
Correct answer
16.4 to 16.6
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Let D1 and D2 be the two dimensions which are independent and follow a normal distribution.
Given:
Mean of D1, mm
Standard deviation of D1, mm
Mean of D2, mm
Standard deviation of D2, mmThe dimension C is given by the difference between D2 and D1:
Since D1 and D2 are independent normal random variables, their difference C also follows a normal distribution.The mean of C is the difference of the means of D2 and D1:
mmThe variance of C is the sum of the variances of D1 and D2 (since they are independent):
mmThe standard deviation of C is the square root of its variance:
mmThe question asks for the upper limit of dimension C to be considered under six-sigma process control. In statistical process control, the control limits are typically set at from the mean. The term "six-sigma" refers to the overall quality level where the process variation () is contained within the specification limits, but the control limits for monitoring the process are set at .The upper control limit (UCL) for dimension C is given by:
Substituting the calculated values:
mmRounding to one decimal place, the upper limit is 16.5 mm.54
Q54NAT2 marksHardA coordinate measuring machine (CMM) is used to determine the distance between Surface and Surface of an approximately cuboidal shaped part. Surface is declared as…Think it through. Then check your answer.Question
A coordinate measuring machine (CMM) is used to determine the distance between Surface and Surface of an approximately cuboidal shaped part. Surface is declared as the datum as per the engineering drawing used for manufacturing this part. The CMM is used to measure four points on Surface , and four points on Surface as shown. A regression procedure is used to fit the necessary planes.The distance between the two fitted planes is ___________ mm.(Answer in integer)
Correct answer
4.999 to 5.001
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1.Analyze the coordinates of the points on Surface (Datum):2.Analyze the coordinates of the points on Surface :
4.The distance between the plane and is mm.55
Q55NAT2 marksHardA solid part (see figure) of polymer material is to be fabricated by additive manufacturing (AM) in square-shaped layers starting from the bottom of the part working upwards. The…Think it through. Then check your answer.Question
A solid part (see figure) of polymer material is to be fabricated by additive manufacturing (AM) in square-shaped layers starting from the bottom of the part working upwards. The nozzle diameter of the AM machine is mm and the nozzle follows a linear serpentine path parallel to the sides of the square layers with a feed rate of mm/min. Ignore any tool path motions other than those involved in adding material, and any other delays between layers or the serpentine scan lines. The time taken to fabricate this part is ___________ minutes.
Answer checking is unavailable for this question. You can review the published solution without a score.
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The total volume of the part is the sum of the volumes of the three blocks:
.The nozzle diameter is mm. Assuming the layer thickness is equal to the nozzle diameter ( mm), the cross-sectional area of the deposited bead is .The feed rate is mm/min.
The volumetric flow rate of material deposition is .The total time taken is:
.56
Q56NAT2 marksHardAn optical flat is used to measure the height difference between a reference slip gauge A and a slip gauge B. Upon viewing via the optical flat using a monochromatic light of…Think it through. Then check your answer.Question
An optical flat is used to measure the height difference between a reference slip gauge A and a slip gauge B. Upon viewing via the optical flat using a monochromatic light of wavelength , 12 fringes were observed over a length of of gauge B. If the gauges are placed apart, the height difference of the gauges is ______________ .
Correct answer
8.999 to 9.001
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Given:
Wavelength
Number of fringes
Length over which fringes are observed
Distance between gauges The height difference over the width is given by:
.By similar triangles, the total height difference between the gauges at distance is:
.57
Q57NAT2 marksMediumIgnoring the small elastic region, the true stress () – true strain () variation of a material beyond yielding follows the equation …Think it through. Then check your answer.Question
Ignoring the small elastic region, the true stress () – true strain () variation of a material beyond yielding follows the equation MPa. The engineering ultimate tensile strength value of this material is ________ MPa. (Rounded off to one decimal place)Correct answer
206 to 207
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Given the true stress-true strain relationship: , where MPa and .At the point of ultimate tensile strength (where necking begins), the condition for instability in tension is:For the power law , the derivative is:Setting the derivative equal to the true stress:Thus, the true strain at the ultimate tensile strength (UTS) is .The true stress at UTS is:The relationship between engineering stress () and true stress () is given by:where is the engineering strain. Since true strain , we have . Substituting this into the stress relationship:At the ultimate tensile strength point:Performing the calculation:Rounding to one decimal place, the engineering ultimate tensile strength is 206.5 MPa.58
Q58NAT2 marksMediumThe area moment of inertia about the -axis of a linearly tapered section shown in the figure is _____________ . (Answer in integer) [figure]Think it through. Then check your answer.Question
The area moment of inertia about the -axis of a linearly tapered section shown in the figure is _____________ .(Answer in integer)
Correct answer
3023.999 to 3024.001
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The height of the section varies linearly from m at to m at m.
The area moment of inertia about the -axis is given by:
.59
Q59NAT2 marksMediumA cylindrical bar has a length and cross section area . The bar is made of a linear elastic material with a density …Think it through. Then check your answer.Question
A cylindrical bar has a length and cross section area . The bar is made of a linear elastic material with a density and Young’s modulus . The bar is suspended as shown in the figure and is in a state of uniaxial tension due to its self-weight.The elastic strain energy stored in the bar equals _________ J. (Rounded off to two decimal places)Take the acceleration due to gravity as .
Correct answer
2 to 2.16
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Consider an element of length at a distance from the free end of the bar.
The weight of the portion of the bar below this element is .
The strain energy stored in this element is .
The total elastic strain energy stored in the bar is obtained by integrating from to :Given:
Substituting the values:Rounding off to two decimal places, the strain energy is .60
Q60NAT2 marksMediumA cylindrical transmission shaft of length and diameter is made of a linear elastic material with a shear modulus of . While…Think it through. Then check your answer.Question
A cylindrical transmission shaft of length and diameter is made of a linear elastic material with a shear modulus of . While operating at , the angle of twist across its length is found to be .The power transmitted by the shaft at this speed is _______ kW. (Rounded off to two decimal places)Take .Correct answer
237 to 240
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From the torsion equation:Where:
Calculating Torque ():Power () is given by:Given :Rounding off to two decimal places, the power is .61
Q61NAT2 marksMediumConsider a mixture of two ideal gases, X and Y, with molar masses and , respectively, in a container.…Think it through. Then check your answer.Question
Consider a mixture of two ideal gases, X and Y, with molar masses and , respectively, in a container. The total pressure in the container is , the total volume of the container is and the temperature of the contents of the container is . If the mass of gas-X in the container is , then the mass of gas-Y in the container is ____ kg. (Rounded off to one decimal place)Assume that the universal gas constant is .Correct answer
3.9 to 4.1
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Given:- Molar mass of X,
- Molar mass of Y,
- Total pressure,
- Total volume,
- Temperature,
- Universal gas constant,
- Mass of X,
62
Q62NAT2 marksMediumThe velocity field of a certain two-dimensional flow is given by where . The coordinates and are in…Think it through. Then check your answer.Question
The velocity field of a certain two-dimensional flow is given bywhere . The coordinates and are in meters. Assume gravitational effects to be negligible.If the density of the fluid is and the pressure at the origin is , the pressure at the location is _____________ kPa.(Answer in integer)Correct answer
83.999 to 84.001
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The velocity components are and . The flow is steady and incompressible. We check for irrotationality:Since the flow is irrotational, we can apply Bernoulli's equation between the origin and the point :At the origin :
At the point :
Given , Substituting into Bernoulli's equation:63
Q63NAT2 marksHardConsider a unidirectional fluid flow with the velocity field given by where . If the spatially homogeneous density field…Think it through. Then check your answer.Question
Consider a unidirectional fluid flow with the velocity field given bywhere . If the spatially homogeneous density field varies with time asthe value of is ______________. (Rounded off to two decimal places)Assume all quantities to be dimensionless.Correct answer
1.1 to 1.2
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For a compressible fluid flow, the continuity equation is:Given that the density field is spatially homogeneous, , so . The equation simplifies to:Rearranging for the velocity gradient:Given , we find the time derivative:Substituting these into the gradient expression:Integrating with respect to :Using the boundary condition :Thus, the velocity field is:To find , substitute and :Rounding to two decimal places, .64
Q64NAT2 marksHardThe figure shows two fluids held by a hinged gate. The atmospheric pressure is . The moment per unit width about the base of the hinge is ________…Think it through. Then check your answer.Question
The figure shows two fluids held by a hinged gate. The atmospheric pressure is . The moment per unit width about the base of the hinge is ________ . (Rounded off to one decimal place)Take the acceleration due to gravity to be .Correct answer
55.9 to 58.5
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To find the moment per unit width about the base of the hinge, we integrate the gauge pressure distribution over the gate. The atmospheric pressure acts on both sides and cancels out.Let be the depth from the top of the first fluid.
For (Fluid 1: ):
For (Fluid 2: ):
The moment per unit width about the hinge (at ) is given by:
Substituting , , and :
Let , then . When ; when . Also .
Total moment .65
Q65NAT2 marksMediumAn explosion at time releases energy at the origin in a space filled with a gas of density . Subsequently, a hemispherical blast wave propagates radially…Think it through. Then check your answer.Question
An explosion at time releases energy at the origin in a space filled with a gas of density . Subsequently, a hemispherical blast wave propagates radially outwards as shown in the figure.Let denote the radius of the front of the hemispherical blast wave. The radius follows the relationship , where is a dimensionless constant. The value of exponent is __________.(Rounded off to one decimal place)Correct answer
0.39 to 0.41
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We use dimensional analysis to find the exponent . The dimensions of the variables are:- Radius
- Time
- Energy
- Density
Equating the exponents for , , and :
1) For :
2) For :
3) For : Thus, the value of exponent is .