The PYQ practice room
GATE CE 2023 Set 1
All 65 solved GATE CE 2023 Set 1 questions in exam order. Open a question, commit to an answer, and learn from the step-by-step solution. One question at a time.
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65
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100
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General Aptitude (GA)
101
Q1MCQ1 markEasy“I have not yet decided what I will do this evening; I ______ visit a friend.”Think it through. Then check your answer.Question
“I have not yet decided what I will do this evening; I ______ visit a friend.”Correct answer
(C) might
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The sentence expresses a lack of certainty or a possibility regarding a future action. The modal verb 'might' is used to indicate that something is possible but not certain. 'Mite' is a noun referring to a small creature or a tiny amount. 'Would' implies a conditional or a more definite intention. 'Didn't' is the past tense negative and does not fit the future context of 'this evening'.2
Q2MCQ1 markEasyEject : Insert : : Advance : _______ (By word meaning)Think it through. Then check your answer.Question
Eject : Insert : : Advance : _______
(By word meaning)Correct answer
(C) Retreat
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The relationship between the first pair of words is antonymous: 'Eject' (to force out) is the opposite of 'Insert' (to put in). Therefore, we need to find the antonym of 'Advance' (to move forward). The antonym of 'Advance' is 'Retreat' (to move back).3
Q3MCQ1 markMediumIn the given figure, PQRSTV is a regular hexagon with each side of length 5 cm. A circle is drawn with its centre at V such that it passes through P. What is the area (in )…Think it through. Then check your answer.Question
In the given figure, PQRSTV is a regular hexagon with each side of length 5 cm. A circle is drawn with its centre at V such that it passes through P. What is the area (in ) of the shaded region? (The diagram is representative)📷 Figure: A regular hexagon PQRSTV with a circle centered at V passing through P. The sector PVT inside the hexagon is shaded.Correct answer
(A) (25π)/(3)
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1.In a regular hexagon, the interior angle at each vertex is given by .2.The circle is centered at vertex and passes through vertex . Since and are adjacent vertices in the hexagon, the radius of the circle is equal to the side length of the hexagon, cm.3.The shaded region is the sector of the circle that lies inside the hexagon. The central angle of this sector is the interior angle of the hexagon at vertex , which is .4.The area of a sector is given by . Substituting the values: Area .4
Q4MCQ1 markMediumA duck named Donald Duck says “All ducks always lie.” Based only on the information above, which one of the following statements can be logically inferred with certainty?Think it through. Then check your answer.Question
A duck named Donald Duck says “All ducks always lie.”Based only on the information above, which one of the following statements can be logically inferred with certainty?Correct answer
(D) Donald Duck’s statement is false.
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If the statement "All ducks always lie" were true, then Donald Duck (being a duck) would be lying, which is a contradiction. Therefore, the statement must be false. If the statement is false, it means not all ducks always lie. This doesn't mean Donald Duck always lies or always tells the truth; it just means the specific statement he made is false.5
Q5MCQ1 markMediumA line of symmetry is defined as a line that divides a figure into two parts in a way such that each part is a mirror image of the other part about that line. The figure below…Think it through. Then check your answer.Question
A line of symmetry is defined as a line that divides a figure into two parts in a way such that each part is a mirror image of the other part about that line.The figure below consists of 20 unit squares arranged as shown. In addition to the given black squares, upto 5 more may be coloured black. Which one among the following options depicts the minimum number of boxes that must be coloured black to achieve two lines of symmetry? (The figure is representative)
Correct answer
(B) c, d, i
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To achieve two lines of symmetry (horizontal and vertical), the pattern must be symmetric about both axes.1.Vertical Symmetry (between columns 2 and 3): The square 'i' at (4,2) must be black to match the black square at (4,3).2.Horizontal Symmetry (about row 3): The square 'd' at (2,3) must be black to match the black square at (4,3). The square 'c' at (2,2) must be black to match square 'i' at (4,2) (which we already determined must be black).Thus, coloring c, d, and i black is the minimum requirement to satisfy both symmetries.6
Q6MCQ2 marksEasyBased only on the truth of the statement ‘Some humans are intelligent’, which one of the following options can be logically inferred with certainty?Think it through. Then check your answer.Question
Based only on the truth of the statement ‘Some humans are intelligent’, which one of the following options can be logically inferred with certainty?Correct answer
(D) Some intelligent beings are humans.
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The statement 'Some humans are intelligent' is a particular affirmative proposition (I-type). In categorical logic, 'Some A are B' is logically equivalent to 'Some B are A' through conversion. Therefore, 'Some intelligent beings are humans' is a certain inference.7
Q7MCQ2 marksMediumWhich one of the options can be inferred about the mean, median, and mode for the given probability distribution (i.e. probability mass function), , of a variable ?…Think it through. Then check your answer.Question
Which one of the options can be inferred about the mean, median, and mode for the given probability distribution (i.e. probability mass function), , of a variable ?
Correct answer
(A) mean = median ≠ mode
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The given probability distribution is symmetric about the vertical axis at . For any symmetric distribution, the mean and median are equal and located at the center of symmetry. Thus, . The mode is the value of at which the probability mass function attains its maximum value. In this bimodal distribution, there are two peaks of equal height at and . Therefore, the modes are . Since the modes are not equal to the mean and median, the correct relationship is .8
Q8MCQ2 marksMediumThe James Webb telescope, recently launched in space, is giving humankind unprecedented access to the depths of time by imaging very old stars formed almost 13 billion years ago.…Think it through. Then check your answer.Question
The James Webb telescope, recently launched in space, is giving humankind unprecedented access to the depths of time by imaging very old stars formed almost 13 billion years ago. Astrophysicists and cosmologists believe that this odyssey in space may even shed light on the existence of dark matter. Dark matter is supposed to interact only via the gravitational interaction and not through the electromagnetic-, the weak- or the strong-interaction. This may justify the epithet “dark” in dark matter.Based on the above paragraph, which one of the following statements is FALSE?Correct answer
(D) If dark matter was known to interact via the strong-interaction, then the epithet “dark” would be justified.
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The passage states that the epithet "dark" is justified because dark matter is supposed to interact only via gravitational interaction and not through electromagnetic, weak, or strong interactions. If dark matter were known to interact via the strong interaction, the premise that it interacts only via gravity would be false, and the specific justification provided in the text for the name "dark" (lack of interaction with other forces) would no longer hold. Therefore, statement (D) is logically inconsistent with the paragraph's reasoning.9
Q9MCQ2 marksMediumLet , , and . Consider the following numbers: Which one of the following inequalities is CORRECT?Think it through. Then check your answer.Question
Let , , and . Consider the following numbers:Which one of the following inequalities is CORRECT?Correct answer
(A) _c a < _b a < ₐ b < ₐ c
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Given , , and , we have .
Using the change of base formula :1.Compare and : and . Since , we have , so . Since , both values are between 0 and 1.2.Compare and : and . Since , both values are greater than 1, and .Combining these results, the order is: . This matches option (A).10
Q10MCQ2 marksMediumA square of side length 4 cm is given. The boundary of the shaded region is defined by one semi-circle on the top and two circular arcs at the bottom, each of radius 2 cm, as…Think it through. Then check your answer.Question
A square of side length 4 cm is given. The boundary of the shaded region is defined by one semi-circle on the top and two circular arcs at the bottom, each of radius 2 cm, as shown.The area of the shaded region is _______ .Correct answer
(A) 8
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Area of the square = . The shaded region consists of the four corners. By symmetry and the properties of the circular arcs, the total area of the shaded region is exactly half the area of the square. Area = .
Civil Engineering (CE) Set 1
5511
Q11MCQ1 markMediumFor the integral which of the following statements is TRUE?Think it through. Then check your answer.Question
For the integral which of the following statements is TRUE?Correct answer
(D) The integral does not converge
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The integrand is undefined at , which lies within the interval . The integral is improper and must be split: . Evaluating the second part: . Since the integral diverges, it does not converge.12
Q12MCQ1 markMediumA hanger is made of two bars of different sizes. Each bar has a square cross-section. The hanger is loaded by three-point loads in the mid vertical plane as shown in the figure.…Think it through. Then check your answer.Question
A hanger is made of two bars of different sizes. Each bar has a square cross-section. The hanger is loaded by three-point loads in the mid vertical plane as shown in the figure. Ignore the self-weight of the hanger. What is the maximum tensile stress in anywhere in the hanger without considering stress concentration effects?Correct answer
(B) 25.0
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1.Area of upper bar () = .2.Area of lower bar () = .3.Internal force in lower bar () = 50 kN = 50,000 N.4.Stress in lower bar () = .5.Internal force in upper bar () = kN = 250,000 N.6.Stress in upper bar () = .7.Maximum tensile stress = .13
Q13MCQ1 markEasyCreep of concrete under compression is defined as the ________.Think it through. Then check your answer.Question
Creep of concrete under compression is defined as the ________.Correct answer
(A) increase in the magnitude of strain under constant stress
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Creep is defined as the time-dependent increase in strain under a sustained constant load (stress). It is a long-term deformation that occurs even when the stress level is kept constant.14
Q14MCQ1 markMediumA singly reinforced concrete beam of balanced section is made of M20 grade concrete and Fe415 grade steel bars. The magnitudes of the maximum compressive strain in concrete and…Think it through. Then check your answer.Question
A singly reinforced concrete beam of balanced section is made of M20 grade concrete and Fe415 grade steel bars. The magnitudes of the maximum compressive strain in concrete and the tensile strain in the bars at ultimate state under flexure, as per IS 456: 2000 are ________, respectively. (round off to four decimal places)Correct answer
(A) 0.0035 and 0.0038
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According to IS 456:2000, Clause 38.1:1.The maximum strain in concrete at the outermost compression fiber is taken as in bending.2.The maximum strain in the tension reinforcement in the section at failure shall not be less than .For Fe415 steel ( MPa) and MPa:
Minimum tensile strain .
Rounding to four decimal places, we get and .15
Q15MCQ1 markEasyIn cement concrete mix design, with the increase in water-cement ratio, which one of the following statements is TRUE?Think it through. Then check your answer.Question
In cement concrete mix design, with the increase in water-cement ratio, which one of the following statements is TRUE?Correct answer
(A) Compressive strength decreases but workability increases
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According to Abrams' water-cement ratio law, the strength of concrete is inversely proportional to the water-cement ratio (provided the mix is workable). However, increasing the water content (and thus the w/c ratio) increases the fluidity and lubrication between particles, which increases the workability of the mix.16
Q16MCQ1 markEasyThe specific gravity of a soil is 2.60. The soil is at 50% degree of saturation with a water content of 15%. The void ratio of the soil is _______.Think it through. Then check your answer.Question
The specific gravity of a soil is 2.60. The soil is at 50% degree of saturation with a water content of 15%. The void ratio of the soil is _______.Correct answer
(B) 0.78
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Given:
Specific gravity,
Degree of saturation,
Water content, Using the fundamental relation in soil mechanics:Substituting the given values:Thus, the void ratio of the soil is 0.78.17
Q17MCQ1 markHardA group of 9 friction piles are arranged in a square grid maintaining equal spacing in all directions. Each pile is of diameter 300 mm and length 7 m. Assume that the soil is…Think it through. Then check your answer.Question
A group of 9 friction piles are arranged in a square grid maintaining equal spacing in all directions. Each pile is of diameter 300 mm and length 7 m. Assume that the soil is cohesionless with effective friction angle . What is the center-to-center spacing of the piles (in m) for the pile group efficiency of 60%?- A.0.582
- B.0.486
- C.0.391
- D.0.677
Answer checking is unavailable for this question. You can review the published solution without a score.
Correct answer
(MTA)
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The efficiency of a pile group () can be calculated using the Converse-Labarre formula:Where:- (number of rows in a grid for 9 piles)
- (number of columns)
- (60% efficiency)
- in degrees, where is diameter and is spacing.
- A.
18
Q18MCQ1 markMediumA possible slope failure is shown in the figure. Three soil samples are taken from different locations (I, II and III) of the potential failure plane. Which is the most…Think it through. Then check your answer.Question
A possible slope failure is shown in the figure. Three soil samples are taken from different locations (I, II and III) of the potential failure plane. Which is the most appropriate shear strength test for each of the sample to identify the failure mechanism? Identify the correct combination from the following options:P: Triaxial compression test
Q: Triaxial extension test
R: Direct shear or shear box test
S: Vane shear test
Correct answer
(A) I-Q, II-R, III-P
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The appropriate shear strength test depends on the stress state at different points along the failure surface:1.Location I (Active Zone/Top of Slope): The soil is being stretched horizontally as it moves downward. This state of stress, where the horizontal stress decreases, is best simulated by a Triaxial extension test (Q).2.Location II (Middle of Failure Plane): The failure is primarily due to sliding along a relatively flat portion of the failure surface. This is best simulated by a Direct shear or shear box test (R).3.Location III (Passive Zone/Toe of Slope): The soil at the toe is being compressed by the weight of the sliding mass above it. This state of stress is best simulated by a Triaxial compression test (P).Therefore, the correct combination is I-Q, II-R, III-P.19
Q19MCQ1 markMediumWhen a supercritical stream enters a mild-sloped (M) channel section, the type of flow profile would become ________.Think it through. Then check your answer.Question
When a supercritical stream enters a mild-sloped (M) channel section, the type of flow profile would become ________.Correct answer
(C) M₃
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In a mild-sloped channel (), the normal depth () is greater than the critical depth (). When a supercritical stream () enters this section, the flow depth is less than both and . This places the flow in Zone 3. The profile formed in Zone 3 of a mild slope is the profile. Eventually, the flow will transition to subcritical via a hydraulic jump to reach the downstream depth.20
Q20MCQ1 markEasyWhich one of the following statements is TRUE for Greenhouse Gas (GHG) in the atmosphere?Think it through. Then check your answer.Question
Which one of the following statements is TRUE for Greenhouse Gas (GHG) in the atmosphere?Correct answer
(D) GHG allows the incoming short wavelength solar radiation to pass through to the earth surface, and absorbs the long wavelength radiation coming from the earth surface
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Greenhouse gases (GHGs) like , , and water vapor are relatively transparent to incoming short-wavelength solar radiation, allowing it to reach and warm the Earth's surface. However, they are effective at absorbing long-wavelength (infrared) thermal radiation emitted back from the Earth's surface, trapping heat in the atmosphere.21
Q21MCQ1 markMediumand are the slopes of the approach and departure grades of a vertical curve, respectively. Given and Statement 1: …Think it through. Then check your answer.Question
and are the slopes of the approach and departure grades of a vertical curve, respectively.Given and
Statement 1: followed by results in a sag vertical curve.
Statement 2: followed by results in a sag vertical curve.
Statement 3: followed by results in a crest vertical curve.Which option amongst the following is true?Correct answer
(A) Statement 1 and Statement 3 are correct; Statement 2 is wrong
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The type of vertical curve is determined by the algebraic difference in grades . If , it is a sag curve; if , it is a crest curve.
Given :1.Statement 1: followed by . Since both are positive and , then . . This is a sag curve. (Correct)2.Statement 2: followed by . Here and are negative. Since , is more negative than (e.g., ). . This is a crest curve. (Statement 2 is wrong)3.Statement 3: followed by . . This is a crest curve. (Correct)Therefore, Statements 1 and 3 are correct, and Statement 2 is wrong.22
Q22MCQ1 markMediumThe direct and reversed zenith angles observed by a theodolite are and , respectively. What is the vertical collimation correction?Think it through. Then check your answer.Question
The direct and reversed zenith angles observed by a theodolite are and , respectively. What is the vertical collimation correction?Correct answer
(D) +0³⁰' 00''
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In an ideal theodolite, the sum of the direct () and reversed () zenith angles should be .
Given:
Observed sum .
The vertical collimation error () is calculated as:
.
The vertical collimation correction () is the negative of the error:
.23
Q23MCQ1 markEasyA student is scanning his certificate at to convert it to raster. What is the percentage reduction in…Think it through. Then check your answer.Question
A student is scanning his certificate at to convert it to raster. What is the percentage reduction in number of pixels if the same certificate is scanned at ?Correct answer
(C) 75
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1.Calculate the total number of pixels at :pixels.2.Calculate the total number of pixels at :pixels.3.Calculate the reduction in pixels:pixels.4.Calculate the percentage reduction:.24
Q24MSQ1 markMediumIf is an arbitrary real matrix, then which of the following matrices will have non-negative eigenvalues?Think it through. Then check your answer.Question
If is an arbitrary real matrix, then which of the following matrices will have non-negative eigenvalues?Correct answer
(B) MM^T; (C) M^TM
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A real matrix has non-negative eigenvalues if it is positive semi-definite (PSD).
For any real matrix , the product of the matrix and its transpose ( and ) results in a symmetric positive semi-definite matrix.Proof for :
For any non-zero vector , the quadratic form is:
.
Since the quadratic form is always non-negative, is positive semi-definite, and all its eigenvalues are real and non-negative. The same logic applies to . and do not necessarily have non-negative eigenvalues unless itself has specific properties (e.g., if is symmetric). For an arbitrary real matrix, can have negative or complex eigenvalues.25
Q25MSQ1 markMediumThe following function is defined over the interval : If it is expressed as a Fourier series,…Think it through. Then check your answer.Question
The following function is defined over the interval :If it is expressed as a Fourier series,which options amongst the following are true?Correct answer
(B) aₙ, n = 1, 2, …, ∞ depend on q; (C) bₙ, n = 1, 2, …, ∞ depend on p
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The function is defined on .1.The term is an even function.2.The term is an odd function.In a Fourier series:- The sine coefficients are given by . Since is an odd function, the integral of (even odd) is zero, and the integral of (odd odd) is non-zero. Thus, depends only on the odd part of , which is . Therefore, depends on .
- The cosine coefficients are given by . Since is an even function, the integral of (even even) is non-zero, and the integral of (odd even) is zero. Thus, depends only on the even part of , which is . Therefore, depends on .
26
Q26MSQ1 markMediumConsider the following three structures: | Structure | Description | | :--- | :--- | | Structure I | Beam with hinge support at A, roller at C, guided roller at E, and…Think it through. Then check your answer.Question
Consider the following three structures:Structure Description Structure I Beam with hinge support at A, roller at C, guided roller at E, and internal hinges at B and D Structure II Pin-jointed truss, with hinge support at A, and rollers at B and D Structure III Pin-jointed truss, with hinge support at A and roller at C Which of the following statements is/are TRUE?
Correct answer
(A) Structure I is unstable; (B) Structure II is unstable; (C) Structure III is unstable
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To determine the stability of each structure, we analyze them individually:1.Structure I: This is a beam with internal hinges at and . The segment is supported by a hinge at and a roller at . However, there is an internal hinge at . Since , , and are collinear, this segment forms a mechanism (it can 'fold' at ). Therefore, Structure I is unstable.2.Structure II: This is a pin-jointed truss with a hinge at and rollers at and . The rollers at and are on vertical walls, meaning their reactions are horizontal. The line of action of the reaction at (vertical line ) passes through . The line of action of the reaction at (horizontal line ) also passes through . Since all external reactions (except those at ) pass through the hinge at , they provide no resistance to a moment about . The structure can rotate freely about , making it a mechanism. Therefore, Structure II is unstable.3.Structure III: This is a pin-jointed truss consisting of two panels. The left panel () is a rectangle with four joints and four members but no diagonal member. For a truss panel to be stable, it must be triangulated (). For this panel, and , so . The panel can undergo shear deformation as a mechanism. Therefore, Structure III is unstable.Since all three structures are unstable, options (A), (B), and (C) are correct.27
Q27MSQ1 markMediumIdentify the waterborne diseases caused by viral pathogens:Think it through. Then check your answer.Question
Identify the waterborne diseases caused by viral pathogens:Correct answer
(A) Acute anterior poliomyelitis; (C) Infectious hepatitis
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Waterborne diseases are classified by the type of pathogen that causes them:- Viral pathogens: Acute anterior poliomyelitis (caused by Poliovirus) and Infectious hepatitis (caused by Hepatitis A or E viruses).
- Bacterial pathogens: Cholera (caused by Vibrio cholerae) and Typhoid fever (caused by Salmonella typhi).
28
Q28MSQ1 markHardWhich of the following statements is/are TRUE for the Refuse-Derived Fuel (RDF) in the context of Municipal Solid Waste (MSW) management?Think it through. Then check your answer.Question
Which of the following statements is/are TRUE for the Refuse-Derived Fuel (RDF) in the context of Municipal Solid Waste (MSW) management?Correct answer
(B) RDF can be made in the powdered form
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Refuse-Derived Fuel (RDF) is produced from the combustible components of municipal solid waste (MSW).
(A) FALSE: RDF is a concentrated fuel, so its HHV is significantly higher than that of unprocessed MSW.
(B) TRUE: RDF can be processed into various forms including fluff, pellets, or powder (densified RDF).
(C) FALSE: The organic/combustible fraction (paper, plastic, wood) is converted to RDF, while inorganics (glass, metal) are removed.
(D) FALSE: RDF can be co-fired with other fuels like coal or oil in industrial boilers or power plants.29
Q29NAT1 markEasyThe probabilities of occurrences of two independent events A and B are 0.5 and 0.8, respectively. What is the probability of occurrence of at least A or B (rounded off to one…Think it through. Then check your answer.Question
The probabilities of occurrences of two independent events A and B are 0.5 and 0.8, respectively. What is the probability of occurrence of at least A or B (rounded off to one decimal place)? ______________________Correct answer
0.9 to 0.9
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Given:
Since A and B are independent events, the probability of their intersection is:
The probability of occurrence of at least A or B is given by the union of the two events:
Thus, the probability is 0.9.30
Q30NAT1 markMediumIn the differential equation , is a positive constant. If at , and at , the value of is…Think it through. Then check your answer.Question
In the differential equation , is a positive constant. If at , and at , the value of is _______________(rounded off to three decimal places).Correct answer
0.445 to 0.447
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The given differential equation is:This is a separable differential equation:Integrating both sides:Using the first boundary condition: at
So, the equation becomes:Using the second boundary condition: at
Rounding off to three decimal places, .31
Q31NAT1 markMediumConsider the fillet-welded lap joint shown in the figure (not to scale). The length of the weld shown is the effective length. The welded surfaces meet at right angle. The weld…Think it through. Then check your answer.Question
Consider the fillet-welded lap joint shown in the figure (not to scale). The length of the weld shown is the effective length. The welded surfaces meet at right angle. The weld size is 8 mm, and the permissible stress in the weld is 120 MPa. What is the safe load (in kN, rounded off to one decimal place) that can be transmitted by this welded joint?
Correct answer
134 to 136
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Given:
Weld size, mm
Permissible stress, MPa
Effective length of weld, mmFor welded surfaces meeting at a right angle (), the throat thickness is given by:
For ,
mmThe safe load that can be transmitted is:
N
kNRounding off to one decimal place, the safe load is 134.4 kN.32
Q32NAT1 markEasyA drained direct shear test was carried out on a sandy soil. Under a normal stress of 50 kPa, the test specimen failed at a shear stress of 35 kPa. The angle of internal friction…Think it through. Then check your answer.Question
A drained direct shear test was carried out on a sandy soil. Under a normal stress of 50 kPa, the test specimen failed at a shear stress of 35 kPa. The angle of internal friction of the sample is ______ degree (round off to the nearest integer).Correct answer
35 to 35
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For sandy soil (cohesionless soil), the cohesion .
The shear strength equation is:
Given:
Normal stress, kPa
Shear stress at failure, kPa
Rounding off to the nearest integer, .33
Q33NAT1 markMediumA canal supplies water to an area growing wheat over 100 hectares. The duration between the first and last watering is 120 days, and the total depth of water required by the crop…Think it through. Then check your answer.Question
A canal supplies water to an area growing wheat over 100 hectares. The duration between the first and last watering is 120 days, and the total depth of water required by the crop is 35 cm. The most intense watering is required over a period of 30 days and requires a total depth of water equal to 12 cm. Assuming precipitation to be negligible and neglecting all losses, the minimum discharge (in m/s, rounded off to three decimal places) in the canal to satisfy the crop requirement is __________________.Correct answer
0.045 to 0.047
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We need to find the discharge required for both the total period and the most intense (core) period. The canal must be designed for the maximum of these two requirements.Case 1: Total period
Area, ha
Base period, days
Total depth (Delta), cm = m
Duty, ha/cumec
Discharge, m/sCase 2: Most intense (core) period
Area, ha
Core period, days
Core depth, cm = m
Duty, ha/cumec
Discharge, m/sThe minimum discharge required to satisfy the crop requirement is the maximum of and :
m/sRounding off to three decimal places, m/s.34
Q34NAT1 markMediumThe ordinates of a one-hour unit hydrograph for a catchment are given below: | t (hour) | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | |---|---|---|---|---|---|---|---|---| | Q () | 0 |…Think it through. Then check your answer.Question
The ordinates of a one-hour unit hydrograph for a catchment are given below:Using the principle of superposition, a -hour unit hydrograph for the catchment was derived from this one-hour unit hydrograph. The ordinates of the -hour unit hydrograph were obtained as at and at . The value of (in integer) is ________.t (hour) 0 1 2 3 4 5 6 7 Q () 0 9 21 18 12 5 2 0 Correct answer
3 to 3
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A -hour unit hydrograph (UH) can be derived from a 1-hour UH using the principle of superposition. The ordinate of a -hour UH at time , , is given by:where is the ordinate of the 1-hour UH.Given :Since , for , only the first term exists:Verification at :This matches the given value. Thus, .35
Q35NAT1 markEasyFor a horizontal curve, the radius of a circular curve is obtained as with the design speed as . If the allowable jerk is , what…Think it through. Then check your answer.Question
For a horizontal curve, the radius of a circular curve is obtained as with the design speed as . If the allowable jerk is , what is the minimum length (in m, in integer) of the transition curve?___________________Correct answer
15 to 15
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The minimum length of a transition curve () based on the rate of change of centrifugal acceleration (jerk, ) is given by the formula:where:
(design speed)
(radius of circular curve)
(allowable jerk)Substituting the values:The minimum length of the transition curve is .36
Q36MCQ2 marksMediumA function , that is smooth and convex-shaped between interval is shown in the figure. This function is observed at odd number of regularly spaced points. If…Think it through. Then check your answer.Question
A function , that is smooth and convex-shaped between interval is shown in the figure. This function is observed at odd number of regularly spaced points. If the area under the function is computed numerically, then ________.Correct answer
(A) the numerical value of the area obtained using the trapezoidal rule will be less than the actual
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The figure shows a function that is concave down (hill-shaped). In numerical integration using the trapezoidal rule, the curve is approximated by straight-line segments (chords) connecting the observed points. For a concave-down function, these chords always lie below the actual curve. Consequently, the area of the trapezoids formed under these chords will be less than the actual area under the smooth curve. Therefore, the numerical value obtained using the trapezoidal rule will be less than the actual area.37
Q37MCQ2 marksMediumConsider a doubly reinforced RCC beam with the option of using either Fe250 plain bars or Fe500 deformed bars in the compression zone. The modulus of elasticity of steel is…Think it through. Then check your answer.Question
Consider a doubly reinforced RCC beam with the option of using either Fe250 plain bars or Fe500 deformed bars in the compression zone. The modulus of elasticity of steel is . As per IS456:2000, in which type(s) of the bars, the stress in the compression steel () can reach the design strength () at the limit state of collapse?Correct answer
(A) Fe250 plain bars only
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In the limit state of collapse, the maximum strain in concrete at the extreme compression fiber is . The strain in compression steel is limited by this value.
For Fe250, the yield strain is . Since , Fe250 can reach its design strength .
For Fe500, the yield strain is . Since , Fe500 cannot reach its design strength in the compression zone.38
Q38MCQ2 marksMediumConsider the horizontal axis passing through the centroid of the steel beam cross-section shown in the figure. What is the shape factor (rounded off to one decimal place) for the…Think it through. Then check your answer.Question
Consider the horizontal axis passing through the centroid of the steel beam cross-section shown in the figure. What is the shape factor (rounded off to one decimal place) for the cross-section?
Correct answer
(B) 1.7
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The cross-section is a cross shape composed of five squares of side .
Total Area .
Due to symmetry, the centroidal axis (X-X) passes through the center of the middle square. 1. Moment of Inertia ():
The section can be seen as a central vertical rectangle () and two side squares ().Elastic Section Modulus .2. Plastic Section Modulus ():
for the area above the equal area axis. Upper half area . It consists of:- Top square: Area , distance from centroidal axis to its own centroid .
- Upper half of middle horizontal bar: Area , distance from centroidal axis to its own centroid .
39
Q39MCQ2 marksHardConsider the pin-jointed truss shown in the figure (not to scale). All members have the same axial rigidity, . Members , , and have the same length . Angles…Think it through. Then check your answer.Question
Consider the pin-jointed truss shown in the figure (not to scale). All members have the same axial rigidity, . Members , , and have the same length . Angles , , are all . Angles , , are all . The joint carries a vertical load . The vertical deflection of joint is . What is the value of ?
Correct answer
(B) 4.5
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Using the unit load method, the vertical deflection at is . Since , .1. Geometry:- .
- From the given angles, are vertical and are horizontal.
- In : , .
- In : , .
- In : , .
- Horizontal members: , .
- At joint : (Compression), (Tension).
- At joint : (Tension), .
- At joint : (Compression), .
- At joint : (Tension), .
- At joint : (Compression), .
40
Q40MCQ2 marksEasyWith reference to the compaction test conducted on soils, which of the following is INCORRECT?Think it through. Then check your answer.Question
With reference to the compaction test conducted on soils, which of the following is INCORRECT?Correct answer
(D) Compaction curve crosses the zero-air-voids curve
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The zero-air-voids (ZAV) curve represents the theoretical maximum dry unit weight for a given moisture content when there is no air in the soil (100% saturation). The compaction curve always lies to the left of and below the ZAV curve. It can never cross it because that would imply a degree of saturation greater than 100%, which is physically impossible.41
Q41MCQ2 marksMediumConsider that a force is acting on the surface of a half-space (Boussinesq’s problem). The expression for the vertical stress () at any point (), within the…Think it through. Then check your answer.Question
Consider that a force is acting on the surface of a half-space (Boussinesq’s problem). The expression for the vertical stress () at any point (), within the half-space is given as,where, is the radial distance, and is the depth with downward direction taken as positive. At any given , there is a variation of along , and at a specific , the value of will be maximum. What is the locus of the maximum ?Correct answer
(A) z² = (3)/(2) r²
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To find the maximum for a given , we differentiate with respect to and set it to zero.Dividing by :42
Q42MCQ2 marksHardA square footing of size is placed below the ground surface on a cohesionless homogeneous soil stratum. Considering that the…Think it through. Then check your answer.Question
A square footing of size is placed below the ground surface on a cohesionless homogeneous soil stratum. Considering that the groundwater table is located at the base of the footing, the unit weights of soil above and below the groundwater table are and , respectively, and the bearing capacity factor is , the net ultimate bearing capacity of the soil is estimated as (unit weight of water ).Earlier, a plate load test was carried out with a circular plate of diameter in the same foundation pit during a dry season, when the water table was located beyond the plate influence zone. Using Terzaghi’s bearing capacity formulation, what is the ultimate bearing capacity (in kPa) of the plate?Correct answer
(A) 110.16
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1.For the square footing:The net ultimate bearing capacity for a cohesionless soil () is:
Given: , , , .
.
.
.2.For the circular plate:Diameter . The test is in the same pit, so relative to the pit base.
Dry season: use bulk unit weight .
Terzaghi's formula for a circular plate ():
.43
Q43MCQ2 marksMediumA very wide rectangular channel carries a discharge () of per meter width. Its bed slope changes from to at a point , as shown in…Think it through. Then check your answer.Question
A very wide rectangular channel carries a discharge () of per meter width. Its bed slope changes from to at a point , as shown in the figure (not to scale). The Manning’s roughness coefficient of the channel is . What water surface profile(s) exist(s) near the point ?
Correct answer
(A) M₂ and S₂
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1.Calculate critical depth ():2.Calculate normal depth for the first slope ():
Since , the first slope is a Mild () slope.3.Calculate normal depth for the second slope ():
Since , the second slope is a Steep () slope.4.Profile transition:At the break in slope from mild to steep, the flow passes through critical depth (). On the mild slope, the depth drops from towards , forming an profile. On the steep slope, the depth drops from towards , forming an profile. Thus, both and profiles exist near point .44
Q44MCQ2 marksMediumA jet of water having a velocity of strikes a series of plates fixed radially on a wheel revolving in the same direction as the jet at . What is the…Think it through. Then check your answer.Question
A jet of water having a velocity of strikes a series of plates fixed radially on a wheel revolving in the same direction as the jet at . What is the percentage efficiency of the plates? (round off to one decimal place)Correct answer
(A) 37.5
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For a series of flat plates mounted on a wheel, the efficiency () is given by the formula:Where:
Substituting the values:The efficiency is .45
Q45MCQ2 marksEasyIn the following table, identify the correct set of associations between the entries in Column-1 and Column-2. | Column-1 | Column-2 | | :--- | :--- | | P: Reverse Osmosis | I:…Think it through. Then check your answer.Question
In the following table, identify the correct set of associations between the entries in Column-1 and Column-2.Column-1 Column-2 P: Reverse Osmosis I: Ponding Q: Trickling Filter II: Freundlich Isotherm R: Coagulation III: Concentration Polarization S: Adsorption IV: Charge Neutralization Correct answer
(D) P-III, Q-I, R-IV
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The correct associations are:- P: Reverse Osmosis matches with III: Concentration Polarization. This is a phenomenon where solute accumulates at the membrane surface, increasing osmotic pressure.
- Q: Trickling Filter matches with I: Ponding. Ponding occurs when the biological growth (slime layer) becomes too thick, clogging the filter media.
- R: Coagulation matches with IV: Charge Neutralization. Coagulants are added to neutralize the negative surface charges of colloidal particles so they can aggregate.
- S: Adsorption matches with II: Freundlich Isotherm. This is a mathematical model used to describe the relationship between the amount of adsorbate on an adsorbent and the concentration of the adsorbate in the liquid phase.
46
Q46MCQ2 marksMediumA plot of speed-density relationship (linear) of two roads (Road A and Road B) is shown in the figure. [figure] If the capacity of Road A is and the capacity of Road B is…Think it through. Then check your answer.Question
A plot of speed-density relationship (linear) of two roads (Road A and Road B) is shown in the figure.If the capacity of Road A is and the capacity of Road B is , what is ?
Correct answer
(C) (k_A u_A)/(k_B u_B)
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For a linear speed-density relationship , the capacity (maximum flow) is given by .
For Road A: and , so .
For Road B: and , so .
The ratio is .47
Q47MSQ2 marksMediumFor the matrix which of the following statements is/are TRUE?Think it through. Then check your answer.Question
For the matrix
which of the following statements is/are TRUE?Correct answer
(A) The eigenvalues of [A]^T are same as the eigenvalues of [A]; (B) The eigenvalues of [A]⁻¹ are the reciprocals of the eigenvalues of [A]; (D) The eigenvectors of [A]⁻¹ are same as the eigenvectors of [A]
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Statement (A): The characteristic equation is the same for and because . Thus, eigenvalues are identical. TRUE.
Statement (B): If , then , which implies . Since , is invertible and eigenvalues of are reciprocals of eigenvalues of . TRUE.
Statement (C): Eigenvectors of and are the same only if is a symmetric matrix. Here is not symmetric, so eigenvectors are generally different. FALSE.
Statement (D): As shown in (B), . The eigenvector remains the same for both and . TRUE.48
Q48MSQ2 marksHardFor the function , which of the following statements is/are TRUE?Think it through. Then check your answer.Question
For the function , which of the following statements is/are TRUE?Correct answer
(A) The function is continuous at all x
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(A) is continuous everywhere and is continuous everywhere. Their product is continuous at all . TRUE.
(B) is not differentiable at (where ). At these points, the left-hand and right-hand derivatives of differ. FALSE.
(C) . The function is not periodic. FALSE.
(D) As , . Since oscillates between 0 and 1, is not bounded. FALSE.49
Q49MSQ2 marksMediumConsider the beam shown in the figure (not to scale), on a hinge support at end A and a roller support at end B. The beam has a constant flexural rigidity, and is subjected to the…Think it through. Then check your answer.Question
Consider the beam shown in the figure (not to scale), on a hinge support at end A and a roller support at end B. The beam has a constant flexural rigidity, and is subjected to the external moments of magnitude at one-third spans, as shown in the figure. Which of the following statements is/are TRUE?
Correct answer
(A) Support reactions are zero; (B) Shear force is zero everywhere
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1.Support Reactions: Let and be the vertical reactions at A and B. Taking moments about A:From vertical equilibrium: . Thus, support reactions are zero. Statement (A) is true.2.Shear Force: Since there are no vertical loads and the support reactions are zero, the shear force is zero throughout the entire span of the beam. Statement (B) is true.3.Bending Moment:- For :
- For :
- For :
4.Deflection: In the middle span (), the bending moment is non-zero (). According to the Euler-Bernoulli beam theory, . Since , there is curvature, and consequently, the beam will deflect. Statement (D) is false.50
Q50MSQ2 marksMediumWhich of the following statements is/are TRUE in relation to the Maximum Mixing Depth (or Height) ‘’ in the atmosphere?Think it through. Then check your answer.Question
Which of the following statements is/are TRUE in relation to the Maximum Mixing Depth (or Height) ‘’ in the atmosphere?Correct answer
(B) Ventilation coefficient depends on Dₘₐₓ; (D) Vertical dispersion of pollutants occurs up to Dₘₐₓ
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Statement (B) is correct because the ventilation coefficient is defined as the product of the maximum mixing depth () and the average wind speed within that depth. Statement (D) is correct because represents the upper limit of the mixing layer, which is the region where vertical dispersion of pollutants is most significant. Statement (A) is incorrect as is determined by the intersection of the environmental lapse rate and the dry adiabatic lapse rate, not just the height of unstable air. Statement (C) is incorrect because a smaller restricts the volume available for dispersion, thereby increasing the air pollution potential.51
Q51MSQ2 marksMediumWhich of the following options match the test reporting conventions with the given material tests in the table? | Test reporting convention | Material test | | :--- | :--- | | (P)…Think it through. Then check your answer.Question
Which of the following options match the test reporting conventions with the given material tests in the table?Test reporting convention Material test (P) Reported as ratio (I) Solubility of bitumen (Q) Reported as percentage (II) Softening point of bitumen (R) Reported in temperature (III) Los Angeles abrasion test (S) Reported in length (IV) Flash point of bitumen (V) Ductility of bitumen (VI) Specific gravity of bitumen (VII) Thin film oven test Correct answer
(B) (P) - (VI); (Q) - (III); (R) - (IV); (S) - (V); (C) (P) - (VI); (Q) - (I); (R) - (II); (S) - (V)
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The correct associations are:- (P) Reported as ratio: Specific gravity of bitumen (VI).
- (Q) Reported as percentage: Solubility of bitumen (I), Los Angeles abrasion test (III), and Thin film oven test (VII) (loss in weight).
- (R) Reported in temperature: Softening point of bitumen (II) and Flash point of bitumen (IV).
- (S) Reported in length: Ductility of bitumen (V) (measured in cm).
52
Q52NAT2 marksHardThe differential equation, is solved by employing a backward difference scheme within the finite difference framework. The value of at the…Think it through. Then check your answer.Question
The differential equation,is solved by employing a backward difference scheme within the finite difference framework. The value of at the time-step, for some , is . The corresponding time is s. Each time step is s long. Then, the value of is ________________(round off to three decimal places).Correct answer
-0.152
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The backward difference scheme for the given differential equation is:Given:
s
s
sSubstituting the values into the finite difference equation:Solving the quadratic equation for :Taking the positive root:The value of is:Rounding to three decimal places, we get .53
Q53NAT2 marksHardThe infinitesimal element shown in the figure (not to scale) represents the state of stress at a point in a body. What is the magnitude of the maximum principal stress (in…Think it through. Then check your answer.Question
The infinitesimal element shown in the figure (not to scale) represents the state of stress at a point in a body. What is the magnitude of the maximum principal stress (in N/mm, in integer) at the point? ____________________________
Correct answer
7 to 7
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From the figure, the stresses on the horizontal plane are:
N/mm (tension)
N/mmOn a plane inclined at , the stresses are:
N/mm
N/mmUsing the stress transformation equations:For :Substituting in (1):The principal stresses are:The magnitude of the maximum principal stress is 7.54
Q54NAT2 marksMediumAn idealised bridge truss is shown in the figure. The force in Member is [figure] kN (round off to one decimal place).Think it through. Then check your answer.Question
An idealised bridge truss is shown in the figure. The force in Member iskN (round off to one decimal place).
Correct answer
13.5 to 14.5
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1.Calculate Reactions: The truss is symmetric and carries five vertical loads of each at nodes . Total vertical load . Due to symmetry, the vertical reactions at supports and are .2.Method of Sections: Pass a vertical section through members , , and . Consider the equilibrium of the left portion of the truss.3.Vertical Equilibrium: The external vertical forces on the left portion are the reaction (upward) and the loads at and ( each, downward). Let be the force in member . The vertical component of this force must balance the net external vertical force:where is the angle member makes with the horizontal. Given the panel width is and height is , .4.Solve for Force:Rounding to one decimal place, the force is . Since the vertical component of the internal force must act downwards to balance the net upward external force, the member is in tension.55
Q55NAT2 marksMediumThe cross-section of a girder is shown in the figure (not to scale). The section is symmetric about a vertical axis (Y-Y). The moment of inertia of the section about the…Think it through. Then check your answer.Question
The cross-section of a girder is shown in the figure (not to scale). The section is symmetric about a vertical axis (Y-Y). The moment of inertia of the section about the horizontal axis (X-X) passing through the centroid is _______ (round off to nearest integer).
Correct answer
464000 to 472000
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1.Identify the components of the cross-section:- Top flange:
- Web:
- Total Area
- For the top flange:
- For the web:
- Total
56
Q56NAT2 marksMediumA soil having the average properties, bulk unit weight = ; angle of internal friction = and cohesion = , is being formed on a rock…Think it through. Then check your answer.Question
A soil having the average properties, bulk unit weight = ; angle of internal friction = and cohesion = , is being formed on a rock slope existing at an inclination of with the horizontal. The critical height (in m) of the soil formation up to which it would be stable without any failure is _______ (round off to one decimal place).[Assume the soil is being formed parallel to the rock bedding plane and there is no ground water effect.]Correct answer
4.8 to 5.2
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1.Given Data:- Bulk unit weight,
- Cohesion,
- Angle of internal friction,
- Slope inclination,
The factor of safety against sliding for an infinite slope is given by:
3.Critical Height ():At critical height, the factor of safety is equal to 1.
4.Solve for :57
Q57NAT2 marksMediumA smooth vertical retaining wall supporting layered soils is shown in figure. According to Rankine’s earth pressure theory, the lateral active earth pressure acting at the base of…Think it through. Then check your answer.Question
A smooth vertical retaining wall supporting layered soils is shown in figure. According to Rankine’s earth pressure theory, the lateral active earth pressure acting at the base of the wall is _______ (round off to one decimal place).
Correct answer
34 to 37
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1.Given Data:- Surcharge,
- Layer 1: , , ,
- Layer 2: , , ,
3.Calculate Vertical Effective Stress () at the base ():4.Calculate Lateral Active Earth Pressure () at the base:5.Final Answer: Rounding to one decimal place, the lateral active earth pressure is , which falls within the range of 34.0 to 37.0.58
Q58NAT2 marksHardA vertical trench is excavated in a clayey soil deposit having a surcharge load of 30 kPa. A fluid of unit weight 12 kN/m is poured in the trench to prevent collapse as the…Think it through. Then check your answer.Question
A vertical trench is excavated in a clayey soil deposit having a surcharge load of 30 kPa. A fluid of unit weight 12 kN/m is poured in the trench to prevent collapse as the excavation proceeds. Assume that the fluid is not seeping through the soil deposit. If the undrained cohesion of the clay deposit is 20 kPa and saturated unit weight is 18 kN/m, what is the maximum depth of unsupported excavation (in m, rounded off to two decimal places)?Correct answer
3.3 to 3.35
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For a vertical trench in clay with surcharge and fluid pressure:
Active earth pressure
Fluid pressure
For stability, the total active force must be balanced by the total fluid force at the critical depth :Equating :Given: kPa, kPa, kN/m, kN/m.59
Q59NAT2 marksHardA 12-hour storm occurs over a catchment and results in a direct runoff depth of 100 mm. The time-distribution of the rainfall intensity is shown in the figure (not to scale). The…Think it through. Then check your answer.Question
A 12-hour storm occurs over a catchment and results in a direct runoff depth of 100 mm. The time-distribution of the rainfall intensity is shown in the figure (not to scale). The -index of the storm is (in mm, rounded off to two decimal places) ____________________________.
Answer checking is unavailable for this question. You can review the published solution without a score.
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Total Runoff mm.
Total Rainfall mm.
Runoff for .
Let the times where be and .
From the graph:
Runoff is the area of the trapezoid above :Solving for :60
Q60NAT2 marksMediumA hydraulic jump occurs in a wide horizontal, frictionless, rectangular channel, with a pre-jump depth of and a post-jump depth of .…Think it through. Then check your answer.Question
A hydraulic jump occurs in a wide horizontal, frictionless, rectangular channel, with a pre-jump depth of and a post-jump depth of . The value of may be taken as . The values of the specific force at the pre-jump and post-jump sections are same and are equal to (in , rounded off to two decimal places) _____________ .Correct answer
0.6 to 0.64
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The specific force () for a rectangular channel is defined as the sum of the pressure force and the momentum flux per unit weight of the fluid:where is the discharge, is the acceleration due to gravity, is the cross-sectional area, and is the depth of the centroid of the area from the free surface.For a rectangular channel of width and depth :61
Q61NAT2 marksMediumIn Horton’s equation fitted to the infiltration data for a soil, the initial infiltration capacity is mm/h; final infiltration capacity is mm/h; and the exponential decay…Think it through. Then check your answer.Question
In Horton’s equation fitted to the infiltration data for a soil, the initial infiltration capacity is mm/h; final infiltration capacity is mm/h; and the exponential decay constant is /h. Assuming that the infiltration takes place at capacity rates, the total infiltration depth (in mm) from a uniform storm of duration h is _______________________. (round off to one decimal place)Correct answer
69.7 to 70.1
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Horton's infiltration equation is given by:where:
= infiltration capacity at time
= initial infiltration capacity = mm/h
= final infiltration capacity = mm/h
= decay constant = /hThe total infiltration depth () for a duration h is the integral of the infiltration capacity over time:Substituting the given values:Rounding off to one decimal place, the total infiltration depth is mm.62
Q62NAT2 marksMediumThe composition and energy content of a representative solid waste sample are given in the table. If the moisture content of the waste is 26%, the energy content of the solid…Think it through. Then check your answer.Question
The composition and energy content of a representative solid waste sample are given in the table. If the moisture content of the waste is 26%, the energy content of the solid waste on dry-weight basis is ___________ MJ/kg (round off to one decimal place).Component Percent by mass Energy content as-discarded basis (MJ/kg) Food waste 20 4.5 Paper 45 16.0 Cardboard 5 14.0 Plastics 10 32.0 Others 20 8.0 Correct answer
18 to 19
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1.Calculate the total energy content on an as-discarded basis ():The total energy is the weighted sum of the energy contents of each component based on their mass percentages:
2.Convert to dry-weight basis ():The relationship between as-discarded energy and dry-basis energy is given by:
Given moisture content = 26% = 0.26:
3.Rounding:Rounding to one decimal place, we get .63
Q63NAT2 marksMediumA flocculator tank has a volume of m. The temperature of water in the tank is C, and the average velocity gradient maintained in the tank is /s. The…Think it through. Then check your answer.Question
A flocculator tank has a volume of m. The temperature of water in the tank is C, and the average velocity gradient maintained in the tank is /s. The temperature of water is reduced to C, but all other operating conditions including the power input are maintained as the same. The decrease in the average velocity gradient (in %) due to the reduction in water temperature is ________ (round off to nearest integer).[Consider dynamic viscosity of water at C and C as N-s/m and N-s/m, respectively]Correct answer
12 to 15
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The power input () in a flocculator is given by the formula:where:
= average velocity gradient
= dynamic viscosity of water
= volume of the tankGiven that the power input () and volume () are maintained as the same at both temperatures:Substituting the given values:
(at C)
(at C)The percentage decrease in the average velocity gradient is:Rounding off to the nearest integer, we get .64
Q64NAT2 marksMediumThe wastewater inflow to an activated sludge plant is , and the plant is to be operated with a food to microorganism ratio of . The…Think it through. Then check your answer.Question
The wastewater inflow to an activated sludge plant is , and the plant is to be operated with a food to microorganism ratio of . The concentration of influent biodegradable organic matter of the wastewater to the plant (after primary settling) is , and the mixed liquor volatile suspended solids concentration to be maintained in the plant is . Assuming that complete removal of biodegradable organic matter in the tank, the volume of aeration tank (in , in integer) required for the plant is _______.Correct answer
16200 to 16200
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Given:- Wastewater inflow,
- Food to microorganism ratio,
- Influent biodegradable organic matter,
- Mixed liquor volatile suspended solids,
65
Q65NAT2 marksMediumTrigonometric levelling was carried out from two stations P and Q to find the reduced level (R. L.) of the top of hillock, as shown in the table. The distance between Stations P…Think it through. Then check your answer.Question
Trigonometric levelling was carried out from two stations P and Q to find the reduced level (R. L.) of the top of hillock, as shown in the table. The distance between Stations P and Q is 55 m. Assume Stations P and Q, and the hillock are in the same vertical plane. The R. L. of the top of the hillock (in m) is _______________________ (round off to three decimal places).Station Vertical angle of the top of hillock Staff reading on benchmark R. L. of benchmark P 2.340 m 100.000 m Q 1.660 m Correct answer
137.5 to 137.73
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1.Calculate Height of Instrument (HI) at each station:- Let be the horizontal distance from station P to the hillock.
- The distance from station Q to the hillock is (assuming Q is further away based on the smaller angle).
- Let be the height of the hillock top above the line of sight at P:
- Let be the height of the hillock top above the line of sight at Q: