GATE EC 2018 Set 1 — Question 19

MCQ+1 / -0.33EasyCanonical SOP & POSCombinational LogicDigital Circuits

Digital Circuits → Combinational Logic → Canonical SOP & POS

Last updated 5 September 2026

Question

A

Your answer

Choose one option, then check your answer.

F = (A + B + C) \cdot (A + \bar{B} + C) \cdot (\bar{A} + B + C)

F = (\bar{A} + \bar{B} + \bar{C}) \cdot (\bar{A} + B + \bar{C}) \cdot (A + \bar{B} + \bar{C})

F = (A + B + \bar{C}) \cdot (A + \bar{B} + \bar{C}) \cdot (\bar{A} + B + \bar{C}) \cdot (\bar{A} + \bar{B} + C) \cdot (\bar{A} + \bar{B} + \bar{C})

F = (\bar{A} + \bar{B} + C) \cdot (\bar{A} + B + C) \cdot (A + \bar{B} + C) \cdot (A + B + \bar{C}) \cdot (A + B + C)

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F = \bar{A}\bar{B}\bar{C} + \bar{A}B\bar{C} + A\bar{B}\bar{C}

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F = \bar{A}\bar{B}\bar{C} + \bar{A}B\bar{C} + A\bar{B}\bar{C}

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