GATE EE 2014 Set 1 — Question 61
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Analog & Digital Electronics → Frequency Response & Root Locus → Bode Plots
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Question
In the figure shown, assume the op-amp to be ideal. Which of the alternatives gives the correct Bode plots for the transfer function ?
Correct answer
(A) [figure]
Solution
Step 1 - the input RC network. The resistor and capacitor form a voltage divider feeding the non-inverting input:Step 2 - the op-amp stage. The output is fed back to the inverting input through , and there is no resistor from the inverting input to ground. An ideal op-amp draws no input current, so no current flows through and there is no drop across it: . With (virtual short), the stage is a voltage follower with gain 1, so , whatever the value of .Step 3 - transfer function.so the corner frequency is .Step 4 - Bode plots. This is a first-order low-pass response:
- Magnitude: 0 dB for rad/s, corner at rad/s, then dB/decade.
- Phase: , going from at low frequency through at rad/s to at high frequency.
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