GATE CE 2016 Set 1 — Question 45

MCQ+2 / -0.67MediumDesign of BeamsRC Fundamentals & BeamsStructural Engineering

Structural Engineering → RC Fundamentals & Beams → Design of Beams

Last updated 5 September 2026

Question

\text{mm}^2

A_{st,min} = \frac{0.85bd}{f_y} = \frac{0.85 \times 250 \times 400}{415} \approx 204.82 \text{ mm}^2 \approx 205 \text{ mm}^2

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A_{st,min} = \frac{0.85bd}{f_y} = \frac{0.85 \times 250 \times 400}{415} \approx 204.82 \text{ mm}^2 \approx 205 \text{ mm}^2

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