GATE CE 2017 Set 2 — Question 39
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Structural Engineering → Torsion, Stress Transformation & Columns → Torsion of Circular Shafts
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Question
A hollow circular shaft has an outer diameter of 100 mm and inner diameter of 50 mm. If the allowable shear stress is 125 MPa, the maximum torque (in kN-m) that the shaft can resist is
Correct answer
20 to 25
Solution
The maximum torque that a hollow circular shaft can resist is given by the torsion formula:Where:
is the polar moment of inertia:
mm (outer diameter)
mm (inner diameter)
MPa (allowable shear stress)
mm (outer radius)Calculating :
mmCalculating :
N-mm
kN-m.The maximum torque is approximately 23.01 kN-m.
is the polar moment of inertia:
mm (outer diameter)
mm (inner diameter)
MPa (allowable shear stress)
mm (outer radius)Calculating :
mmCalculating :
N-mm
kN-m.The maximum torque is approximately 23.01 kN-m.
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