The PYQ practice room
GATE CE 2020 Set 2
All 65 solved GATE CE 2020 Set 2 questions in exam order. Open a question, commit to an answer, and learn from the step-by-step solution. One question at a time.
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65
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100
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General Aptitude (GA)
101
Q1MCQ1 markEasyRescue teams deployed ____ disaster hit areas combat ____ a lot of difficulties to save the people.Think it through. Then check your answer.Question
Rescue teams deployed ____ disaster hit areas combat ____ a lot of difficulties to save the people.Correct answer
(B) in, with
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The correct prepositions are 'in' for the location (disaster hit areas) and 'with' to indicate the struggle against difficulties. Thus, the sentence is: 'Rescue teams deployed in disaster hit areas combat with a lot of difficulties to save the people.'2
Q2MCQ1 markEasySelect the most appropriate word that can replace the underlined word without changing the meaning of the sentence: Now-a-days, most children have a tendency to belittle…Think it through. Then check your answer.Question
Select the most appropriate word that can replace the underlined word without changing the meaning of the sentence:Now-a-days, most children have a tendency to belittle the legitimate concerns of their parents.Correct answer
(A) disparage
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The word 'belittle' means to represent something as being of little worth or to speak slightingly of. 'Disparage' is a direct synonym meaning to regard or represent as being of little worth. 'Applaud' is an antonym, 'reduce' means to make smaller, and 'begrudge' means to envy or give reluctantly.3
Q3MCQ1 markEasySelect the word that fits the analogy: Partial : Impartial :: Popular : ______Think it through. Then check your answer.Question
Select the word that fits the analogy:Partial : Impartial :: Popular : ______Correct answer
(D) Unpopular
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The analogy is based on antonyms formed by adding a prefix. 'Partial' becomes 'Impartial' by adding 'Im-'. Similarly, the standard antonym of 'Popular' is formed by adding the prefix 'Un-', resulting in 'Unpopular'.4
Q4MCQ1 markEasyAfter the inauguration of the new building, the Head of the Department (HoD) collated faculty preferences for office space. P wanted a room adjacent to the lab. Q wanted to be…Think it through. Then check your answer.Question
After the inauguration of the new building, the Head of the Department (HoD) collated faculty preferences for office space. P wanted a room adjacent to the lab. Q wanted to be close to the lift. R wanted a view of the playground and S wanted a corner office.Assuming that everyone was satisfied, which among the following shows a possible allocation?Correct answer
(C) [figure]
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Based on the faculty preferences:1.P wants to be adjacent to the lab.2.Q wants to be close to the lift.3.R wants a view of the playground (top row).4.S wants a corner office.Evaluating the options:- Option (A): Q is in the top row while the LIFT is in the middle row on the opposite side; they are not close.
- Option (B): P is in the top row, which is not adjacent to the LAB at the bottom.
- Option (C): P is adjacent to the LAB, Q is directly above the LIFT, R is in the top row (playground view), and S is in the top-left corner office. All conditions are satisfied.
- Option (D): S is not in a corner office; it is situated between HoD and R.
5
Q5MCQ1 markEasyIf for each , then is equal to ________.Think it through. Then check your answer.Question
If for each , then is equal to ________.Correct answer
(C) (f(x))³
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Given .
First, find the nested functions:
Now, calculate the required ratio:
Check the options in terms of :
(A)
(B)
(C)
(D) The result matches Option (C).6
Q6MCQ2 marksEasyNominal interest rate is defined as the amount paid by the borrower to the lender for using the borrowed amount for a specific period of time. Real interest rate calculated on the…Think it through. Then check your answer.Question
Nominal interest rate is defined as the amount paid by the borrower to the lender for using the borrowed amount for a specific period of time. Real interest rate calculated on the basis of actual value (inflation-adjusted), is approximately equal to the difference between nominal rate and expected rate of inflation in the economy.Which of the following assertions is best supported by the above information?Correct answer
(A) Under high inflation, real interest rate is low and borrowers get benefited.
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The relationship provided is: Real Interest Rate Nominal Interest Rate - Inflation Rate.1.When inflation is high, the difference (Nominal - Inflation) decreases, leading to a lower real interest rate.2.A lower real interest rate means the borrower is effectively paying back less in terms of actual purchasing power than what was originally borrowed, which benefits the borrower.3.Conversely, a high real interest rate (which occurs when inflation is low relative to the nominal rate) benefits the lender as the value of the repaid money is higher.Assertion (A) correctly identifies that high inflation leads to a low real interest rate, which benefits the borrower.7
Q7MCQ2 marksMediumFor the year 2019, which of the previous year's calendar can be used?Think it through. Then check your answer.Question
For the year 2019, which of the previous year's calendar can be used?Correct answer
(C) 2013
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A calendar repeats when the number of odd days between the years is a multiple of 7 and both years are of the same type (leap or non-leap).Counting odd days from 2013 to 2019:- 2013: 1 odd day
- 2014: 1 odd day
- 2015: 1 odd day
- 2016: 2 odd days (Leap year)
- 2017: 1 odd day
- 2018: 1 odd day
8
Q8MCQ2 marksMediumThe ratio of 'the sum of the odd positive integers from 1 to 100' to 'the sum of the even positive integers from 150 to 200' is ______.Think it through. Then check your answer.Question
The ratio of 'the sum of the odd positive integers from 1 to 100' to 'the sum of the even positive integers from 150 to 200' is ______.Correct answer
(C) 50: 91
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1.Sum of odd positive integers from 1 to 100:These are . This is an Arithmetic Progression (AP) with , , and .
Sum .2.Sum of even positive integers from 150 to 200:These are . This is an AP with , , and .
Number of terms : .
Sum .3.Ratio:Ratio .
Dividing by 5: .9
Q9MCQ2 marksEasyIn a school of 1000 students, 300 students play chess and 600 students play football. If 50 students play both chess and football, the number of students who play neither is…Think it through. Then check your answer.Question
In a school of 1000 students, 300 students play chess and 600 students play football. If 50 students play both chess and football, the number of students who play neither is ______.Correct answer
(B) 150
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Let be the set of all students, be the set of students playing chess, and be the set of students playing football.
Given:
The number of students playing at least one game is:
.The number of students who play neither is:
.10
Q10MCQ2 marksMediumThe monthly distribution of 9 Watt LED bulbs sold by two firms X and Y from January to June 2018 is shown in the pie-chart and the corresponding table. If the total number of LED…Think it through. Then check your answer.Question
The monthly distribution of 9 Watt LED bulbs sold by two firms X and Y from January to June 2018 is shown in the pie-chart and the corresponding table. If the total number of LED bulbs sold by two firms during April-June 2018 is 50000, then the number of LED bulbs sold by the firm Y during April-June 2018 is ________.Percentage of 9 Watt LED bulbs sold by the firms X and Y from January 2018 to June, 2018
Month Ratio of LED bulbs sold by two firms (X : Y) January 7 : 8 February 2 : 3 March 2 : 1 April 3 : 2 May 1 : 4 June 9 : 11 - A.11250
- B.9750
- C.8750
- D.8250
Answer checking is unavailable for this question. You can review the published solution without a score.
Correct answer
(MTA)
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The question provides a pie chart for the monthly distribution of LED bulbs sold from January to June 2018 and a table for the ratio of bulbs sold by firms X and Y.From the pie chart, the percentages of bulbs sold in the months of April, May, and June are:- April:
- May:
- June:
Now, calculate the bulbs sold by firm Y in these months using the given ratios :- April ():
- May ():
- June ():
Substituting : .None of the options match this result. However, if we assume the "total number of bulbs" () refers to the entire period from January to June ():
Total bulbs sold by Y = .This matches option (B). Due to the ambiguity in the problem statement (whether refers to the April-June total or the Jan-June total), the question was marked as Marks to All (MTA) in the official answer key.- A.
CE2: Civil Engineering
5511
Q11MCQ1 markEasyThe ordinary differential equation isThink it through. Then check your answer.Question
The ordinary differential equation isCorrect answer
(B) linear and nonhomogeneous
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The differential equation is of the form . Here , , , and . Since the dependent variable and its derivatives appear linearly (power 1, no products), it is a linear ODE. Since , it is nonhomogeneous.12
Q12MCQ1 markEasyThe value of isThink it through. Then check your answer.Question
The value of isCorrect answer
(C) 3
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To find the limit as , we divide the numerator and denominator by :As , and . Thus:13
Q13MCQ1 markMediumThe integral is estimated numerically using three alternative methods namely the rectangular, trapezoidal and Simpson's rules with a…Think it through. Then check your answer.Question
The integralis estimated numerically using three alternative methods namely the rectangular, trapezoidal and Simpson's rules with a common step size. In this context, which one of the following statements is TRUE?Correct answer
(D) Only Simpson's rule of estimation will give zero error.
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Simpson's 1/3 rule is mathematically exact for polynomials of degree up to 3. The given integrand is a cubic polynomial (degree 3). Therefore, Simpson's rule will yield the exact value of the integral, resulting in zero error. The rectangular rule is exact for degree 0, and the trapezoidal rule is exact for degree 1; both will have non-zero errors for a cubic polynomial.14
Q14MCQ1 markMediumThe following partial differential equation is defined for …Think it through. Then check your answer.Question
The following partial differential equation is defined for The set of auxiliary conditions necessary to solve the equation uniquely, isCorrect answer
(D) one initial condition and two boundary conditions
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The given equation is a parabolic partial differential equation (analogous to the 1D heat conduction equation). It is first-order with respect to the time-like variable and second-order with respect to the space-like variable . To obtain a unique solution, we require:1.One initial condition for the first-order derivative in (e.g., ).2.Two boundary conditions for the second-order derivative in (e.g., and ).15
Q15MCQ1 markEasyThe ratio of the plastic moment capacity of a beam section to its yield moment capacity is termed asThink it through. Then check your answer.Question
The ratio of the plastic moment capacity of a beam section to its yield moment capacity is termed asCorrect answer
(C) shape factor
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The Shape Factor () of a cross-section is defined as the ratio of its plastic moment capacity () to its yield moment capacity (). It is a measure of the reserve strength of the section beyond the elastic limit.16
Q16MCQ1 markEasyThe state of stress represented by Mohr's circle shown in the figure is [figure]Think it through. Then check your answer.Question
The state of stress represented by Mohr's circle shown in the figure is
Correct answer
(D) pure shear
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In the given Mohr's circle, the center is at the origin . For a circle centered at the origin, the average normal stress is zero: . This state of stress, where principal stresses are equal in magnitude but opposite in sign, represents pure shear. On a plane at to the principal planes, the normal stress is zero and the shear stress is maximum (equal to the radius of the circle).17
Q17MCQ1 markMediumA weightless cantilever beam of span is loaded as shown in the figure. For the entire span of the beam, the material properties are identical and the cross section is…Think it through. Then check your answer.Question
A weightless cantilever beam of span is loaded as shown in the figure. For the entire span of the beam, the material properties are identical and the cross section is rectangular with constant width.From the flexure-critical perspective, the most economical longitudinal profile of the beam to carry the given loads amongst the options given below, is
Correct answer
(C) [figure]
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The bending moment at any section from the free end is given by . At the free end (), . At the fixed end (), . The bending moment diagram is a trapezoid. For a rectangular section with constant width , the required depth is determined by the section modulus . Since , we have . The required depth profile is parabolic, starting from a non-zero value at the free end. Among the given options, (C) provides the most economical linear approximation of this profile, as it accounts for the non-zero moment at the free end and the increase towards the support.18
Q18MCQ1 markEasyAs per IS 456:2000, the pH value of water for concrete mix shall NOT be less thanThink it through. Then check your answer.Question
As per IS 456:2000, the pH value of water for concrete mix shall NOT be less thanCorrect answer
(D) 6.0
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According to IS 456:2000, Clause 5.4.2, the pH value of water used for mixing and curing concrete shall generally be not less than 6.19
Q19MCQ1 markEasyThe traffic starts discharging from an approach at an intersection with the signal turning green. The constant headway considered from the fourth or fifth headway position is…Think it through. Then check your answer.Question
The traffic starts discharging from an approach at an intersection with the signal turning green. The constant headway considered from the fourth or fifth headway position is referred to asCorrect answer
(D) saturation headway
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Saturation headway is the constant average headway achieved by a queue of vehicles discharging from an intersection after the initial startup lost time (usually after the 4th or 5th vehicle). It represents the minimum average time between successive vehicles under saturated flow conditions.20
Q20MCQ1 markEasySoil deposit formed due to transportation by wind is termed asThink it through. Then check your answer.Question
Soil deposit formed due to transportation by wind is termed asCorrect answer
(A) aeolian deposit
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Soil deposits are classified based on their mode of transportation and deposition:1.Aeolian deposits: Transported and deposited by wind (e.g., loess, sand dunes).2.Alluvial deposits: Transported and deposited by running water (rivers).3.Estuarine deposits: Deposited in estuaries where rivers meet the sea.4.Lacustrine deposits: Deposited in freshwater lakes.Therefore, wind-transported soil is termed an aeolian deposit.21
Q21MCQ1 markEasyA sample of dry sand, when poured into a capacity cylinder which is partially filled with water, displaces of water. The density…Think it through. Then check your answer.Question
A sample of dry sand, when poured into a capacity cylinder which is partially filled with water, displaces of water. The density of water is . The specific gravity of the sand isCorrect answer
(B) 2.66
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Specific gravity () is the ratio of the weight of a given volume of solids to the weight of an equivalent volume of water at a standard temperature.Given:- Weight of dry sand solids () =
- Volume of water displaced = Volume of solids () =
- Density of water () =
22
Q22MCQ1 markEasyMuskingum method is used inThink it through. Then check your answer.Question
Muskingum method is used inCorrect answer
(B) hydrologic channel routing
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Flood routing is the process of determining the flood hydrograph at a section of a river by utilizing the data of flood hydrograph at an upstream section.- Hydrologic routing uses the principle of continuity and a storage-discharge relationship. The Muskingum method is a popular hydrologic routing method specifically used for channel routing, where storage is a function of both inflow and outflow.
- Reservoir routing typically uses the Modified Pul's method (Level-pool routing).
23
Q23MCQ1 markEasySuperpassage is a canal cross-drainage structure in whichThink it through. Then check your answer.Question
Superpassage is a canal cross-drainage structure in whichCorrect answer
(C) canal water flows with free surface below a natural stream
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In a superpassage, the natural stream (drain) is taken over the canal. The canal water flows with a free surface below the natural stream. If the canal water were to flow under pressure (full) below the stream, it would be called a siphon superpassage.24
Q24MCQ1 markMediumA triangular direct runoff hydrograph due to a storm has a time base of 90 hours. The peak flow of occurs at 20 hours from the start of the storm. The…Think it through. Then check your answer.Question
A triangular direct runoff hydrograph due to a storm has a time base of 90 hours. The peak flow of occurs at 20 hours from the start of the storm. The area of catchment is . The rainfall excess of the storm (in cm), isCorrect answer
(B) 3.24
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1.Calculate the volume of runoff ():The volume of runoff is the area under the Direct Runoff Hydrograph (DRH).2.Calculate rainfall excess ():Rainfall excess is the volume of runoff divided by the catchment area.3.Convert to cm:25
Q25MCQ1 markMediumThe velocity components in the and directions for an incompressible flow are given as and , respectively. The equation of the streamline isThink it through. Then check your answer.Question
The velocity components in the and directions for an incompressible flow are given as and , respectively. The equation of the streamline isCorrect answer
(C) (-5 + 6x)(9 + 6y) = constant
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The differential equation for a streamline in 2D flow is:Substitute the given velocity components:Integrate both sides:Multiply by 6:Taking the exponential of both sides:26
Q26MCQ1 markEasyThe relationship between oxygen consumption and equivalent biodegradable organic removal (i.e., BOD) in a closed container with respect to time is shown in the figure [figure]…Think it through. Then check your answer.Question
The relationship between oxygen consumption and equivalent biodegradable organic removal (i.e., BOD) in a closed container with respect to time is shown in the figureAssume that the rate of oxygen consumption is directly proportional to the amount of degradable organic matter and is expressed as , where, (in mg/litre) is the oxygen equivalent of the organics remaining at time and (in ) is the degradation rate constant. is the oxygen equivalent of organic matter at time, .In the above context, the correct expression is
Correct answer
(B) BODₜ = L₀ - Lₜ
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The amount of oxygen consumed up to time (BOD exerted, ) is equal to the initial ultimate BOD () minus the amount of biodegradable organic matter remaining at time (). From the first-order kinetics given, . Therefore, . Option (B) correctly states the fundamental relationship .27
Q27MCQ1 markMediumA gas contains two types of suspended particles having average sizes of and . Amongst the options given below, the most suitable pollution control strategy for…Think it through. Then check your answer.Question
A gas contains two types of suspended particles having average sizes of and . Amongst the options given below, the most suitable pollution control strategy for removal of these particles isCorrect answer
(A) settling chamber followed by bag filter
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Gravity settling chambers are effective for removing coarse particles (typically ). Bag filters (fabric filters) are highly efficient for removing fine particles (down to sub-micron levels, including ). In industrial air pollution control, coarse removal stages always precede fine removal stages to prevent overloading and damage to the high-efficiency equipment. Thus, a settling chamber followed by a bag filter is the most suitable strategy.28
Q28NAT1 markEasyA fair (unbiased) coin is tossed 15 times. The probability of getting exactly 8 Heads (round off to three decimal places), is ___________.Think it through. Then check your answer.Question
A fair (unbiased) coin is tossed 15 times. The probability of getting exactly 8 Heads (round off to three decimal places), is ___________.Correct answer
0.19 to 0.2
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This follows a binomial distribution .
Given:
(number of tosses)
(number of successes/heads)
(probability of head for a fair coin)
Rounding to three decimal places, the probability is 0.196.29
Q29NAT1 markEasyThe maximum applied load on a cylindrical concrete specimen of diameter and length tested as per the split tensile strength test guidelines of IS…Think it through. Then check your answer.Question
The maximum applied load on a cylindrical concrete specimen of diameter and length tested as per the split tensile strength test guidelines of IS 5816:1999 is . The split tensile strength (in MPa, round off to one decimal place) of the specimen is ________.Correct answer
2 to 2.4
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The split tensile strength of a cylindrical specimen is calculated using the formula:Where:- is the maximum applied load
- is the diameter of the specimen
- is the length of the specimen
30
Q30NAT1 markEasyFor an axle load of on a road, the Vehicle Damage Factor (round off to two decimal places), in terms of the standard axle load of , is ________.Think it through. Then check your answer.Question
For an axle load of on a road, the Vehicle Damage Factor (round off to two decimal places), in terms of the standard axle load of , is ________.Correct answer
12.3 to 12.4
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The Vehicle Damage Factor (VDF) is calculated using the fourth-power law:Where:- is the axle load
- is the standard axle load
31
Q31NAT1 markMediumtraffic count at a road section was observed to be vehicles on a Tuesday in the month of July. If daily adjustment factor for Tuesday is and monthly…Think it through. Then check your answer.Question
traffic count at a road section was observed to be vehicles on a Tuesday in the month of July. If daily adjustment factor for Tuesday is and monthly adjustment factor for July is , the Annual Average Daily Traffic (in veh/day, round off to the nearest integer) is ________.Correct answer
1021 to 1024
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The Annual Average Daily Traffic (AADT) is calculated by multiplying the observed traffic count by the daily and monthly adjustment factors:Given:- Traffic Count
- Daily Adjustment Factor (Tuesday)
- Monthly Adjustment Factor (July)
32
Q32NAT1 markMediumA soil has dry unit weight of , specific gravity of and degree of saturation of . Considering the unit weight of water as ,…Think it through. Then check your answer.Question
A soil has dry unit weight of , specific gravity of and degree of saturation of . Considering the unit weight of water as , the water content of the soil (in , round off to two decimal places) is ________________.Correct answer
19 to 19.5
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Given:
Dry unit weight
Specific gravity
Degree of saturation
Unit weight of water Step 1: Find the void ratio using the dry unit weight formula:Step 2: Find the water content using the relation :Rounding off to two decimal places, the water content is .33
Q33NAT1 markMediumA one-dimensional consolidation test is carried out on a standard thick clay sample. The oedometer's deflection gauge indicates a reading of , just…Think it through. Then check your answer.Question
A one-dimensional consolidation test is carried out on a standard thick clay sample. The oedometer's deflection gauge indicates a reading of , just before removal of the load, without allowing any swelling. The void ratio is at this stage. The initial void ratio (round off to two decimal places) of the standard specimen is ________________.Correct answer
0.78 to 0.88
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Given:
Initial thickness
Settlement
Final void ratio Step 1: Use the consolidation formula relating change in thickness to change in void ratio:Step 2: Substitute the values and solve for :Rounding off to two decimal places, the initial void ratio is .34
Q34NAT1 markEasyVelocity distribution in a boundary layer is given by , where is the velocity at vertical coordinate…Think it through. Then check your answer.Question
Velocity distribution in a boundary layer is given by , where is the velocity at vertical coordinate , is the free stream velocity and is the boundary layer thickness. The values of and are and , respectively. The velocity gradient (in , round off to two decimal places) at , is ________________.Correct answer
0.45 to 0.49
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Given:
Velocity distribution:
Step 1: Differentiate with respect to :Step 2: Evaluate the gradient at :Rounding off to two decimal places, the velocity gradient is .35
Q35NAT1 markMediumTwo identically sized primary settling tanks receive water for Type-I settling (discrete particles in dilute suspension) under laminar flow conditions. The Surface Overflow Rate…Think it through. Then check your answer.Question
Two identically sized primary settling tanks receive water for Type-I settling (discrete particles in dilute suspension) under laminar flow conditions. The Surface Overflow Rate (SOR) maintained in the two tanks are and . The lowest diameters of the particles, which shall be settled out completely under SORs of and are designated as and , respectively. The ratio, (round off to two decimal places), is ________.Correct answer
1.4 to 1.42
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For Type-I settling under laminar flow conditions, the settling velocity is given by Stokes' Law: . For 100% removal, the settling velocity must be at least equal to the Surface Overflow Rate (SOR). The lowest diameter that is completely removed corresponds to . Thus, , which implies . The ratio is calculated as:Rounding to two decimal places, we get 1.41.36
Q36MCQ2 marksEasyAn ordinary differential equation is given below The general solution of the above equation (with constants and ), isThink it through. Then check your answer.Question
An ordinary differential equation is given belowThe general solution of the above equation (with constants and ), isCorrect answer
(B) y(x) = C₁ e^((x)/(3)) + C₂ e^(-(x)/(2))
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The given differential equation is . The characteristic (auxiliary) equation is:Solving for using the quadratic formula:The roots are and .
The general solution is :This matches option (B).37
Q37MCQ2 marksMediumA matrix is given below The eigenvalues of areThink it through. Then check your answer.Question
A matrix is given belowThe eigenvalues of areCorrect answer
(D) 1, 2, 5, 7
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The matrix is a block upper triangular matrix of the form , where:
and .
The eigenvalues of are the union of the eigenvalues of and .
For : . Eigenvalues are .
For : . Eigenvalues are .
The eigenvalues of are .38
Q38MCQ2 marksMediumA prismatic linearly elastic bar of length , cross-sectional area , and made up of a material with Young's modulus , is subjected to axial tensile force as shown in the…Think it through. Then check your answer.Question
A prismatic linearly elastic bar of length , cross-sectional area , and made up of a material with Young's modulus , is subjected to axial tensile force as shown in the figures. When the bar is subjected to axial tensile forces and , the strain energies stored in the bar are and , respectively.If is the strain energy stored in the same bar when subjected to an axial tensile force , the correct relationship is
Correct answer
(D) U U₁ + U₂
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The strain energy in a linearly elastic bar is given by .
For the first two cases:
For the third case, the force is :
Since and are both tensile forces (positive), the term .
Therefore, .39
Q39MCQ2 marksMediumThe planar structure RST shown in the figure is roller-supported at S and pin-supported at R. Members RS and ST have uniform flexural rigidity () and S is a rigid joint.…Think it through. Then check your answer.Question
The planar structure RST shown in the figure is roller-supported at S and pin-supported at R. Members RS and ST have uniform flexural rigidity () and S is a rigid joint. Consider only bending deformation and neglect effects of self-weight and axial stiffening.When the structure is subjected to a concentrated horizontal load at the end T, the magnitude of rotation at the support R, is
Correct answer
(B) (PL²)/(12EI)
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The horizontal load at T creates a clockwise moment at joint S:
Member RS is a beam of length , pinned at R and rigid at S. The moment is applied at joint S. According to the slope-deflection equations or standard beam formulas, the rotation at the pinned end R due to a moment applied at the other end S is:
Substituting :40
Q40MCQ2 marksHardJoints I, J, K, L, Q and M of the frame shown in the figure (not drawn to the scale) are pins. Continuous members IQ and LJ are connected through a pin at N. Continuous members…Think it through. Then check your answer.Question
Joints I, J, K, L, Q and M of the frame shown in the figure (not drawn to the scale) are pins. Continuous members IQ and LJ are connected through a pin at N. Continuous members JM and KQ are connected through a pin at P. The frame has hinge supports at joints R and S. The loads acting at joints I, J and K are along the negative Y direction and the loads acting at joints L and M are along the positive X direction.The magnitude of the horizontal component of reaction (in kN) at S, is
Correct answer
(C) 15
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1.Equilibrium of the entire frame:2.Analysis of the frame:By analyzing the internal forces or using the method of sections for this specific truss-like frame, the horizontal reaction at S is found to be in the negative X direction. Thus, the magnitude is .41
Q41MCQ2 marksMediumThe flow-density relationship of traffic on a highway is shown in the figure [figure] The correct representation of speed-density relationship of the traffic on this highway isThink it through. Then check your answer.Question
The flow-density relationship of traffic on a highway is shown in the figureThe correct representation of speed-density relationship of the traffic on this highway is
Correct answer
(C) [figure]
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The relationship between flow (), density (), and speed () is given by .1.From the given flow-density () diagram, for the first part (increasing linear through the origin), the relationship is . Substituting , we get (constant). This corresponds to a horizontal line in the speed-density () plot.2.For the second part (decreasing linear), the relationship is , where is the jam density. Substituting , we get . This is a non-linear (hyperbolic) relationship where speed decreases as density increases.Option (C) correctly shows a constant speed followed by a non-linear decrease, matching these derivations.42
Q42MCQ2 marksEasyGroup-I gives a list of test methods for evaluating properties of aggregates. Group-II gives the list of properties to be evaluated. | Group-I: Test methods | Group-II: Properties…Think it through. Then check your answer.Question
Group-I gives a list of test methods for evaluating properties of aggregates. Group-II gives the list of properties to be evaluated.The correct match of test methods under Group-I to properties under Group-II, isGroup-I: Test methods Group-II: Properties P. Soundness test 1. Strength Q. Crushing test 2. Resistance to weathering R. Los Angeles abrasion test 3. Adhesion S. Stripping value test 4. Hardness Correct answer
(B) P-2; Q-1; R-4; S-3
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The matching of aggregate tests to the properties they evaluate is as follows:- Soundness test (P): Evaluates the resistance of aggregates to weathering action (durability) due to cycles of wetting/drying or freezing/thawing. (Matches 2)
- Crushing test (Q): Evaluates the compressive strength of aggregates under a gradually applied load. (Matches 1)
- Los Angeles abrasion test (R): Evaluates the hardness or resistance of aggregates to surface wear and attrition. (Matches 4)
- Stripping value test (S): Evaluates the adhesion of bituminous binder to the aggregate surface in the presence of water. (Matches 3)
43
Q43MCQ2 marksEasyFor the hottest month of the year at the proposed airport site, the monthly mean of the average daily temperature is . The monthly mean of the maximum daily…Think it through. Then check your answer.Question
For the hottest month of the year at the proposed airport site, the monthly mean of the average daily temperature is . The monthly mean of the maximum daily temperature is for the same month of the year. From the given information, the calculated Airport Reference Temperature (in ), isCorrect answer
(C) 42
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The Airport Reference Temperature () is calculated using the standard formula:where:- is the monthly mean of the average daily temperature for the hottest month.
- is the monthly mean of the maximum daily temperature for the same month.
44
Q44MCQ2 marksMediumPermeability tests were carried out on the samples collected from two different layers as shown in the figure (not drawn to the scale). The relevant horizontal () and…Think it through. Then check your answer.Question
Permeability tests were carried out on the samples collected from two different layers as shown in the figure (not drawn to the scale). The relevant horizontal () and vertical () coefficients of permeability are indicated for each layer.The ratio of the equivalent horizontal to vertical coefficients of permeability, is
Correct answer
(A) 37.29
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To find the ratio of equivalent horizontal to vertical coefficients of permeability, we first calculate each:1.Equivalent Horizontal Permeability ():Given: , , , .2.Equivalent Vertical Permeability ():Given: , .3.Ratio:The closest option is 37.29.45
Q45MCQ2 marksHardA high slope of dry clay soil (unit weight = ), with a slope angle of and the circular slip surface, is shown in the figure (*not drawn…Think it through. Then check your answer.Question
A high slope of dry clay soil (unit weight = ), with a slope angle of and the circular slip surface, is shown in the figure (not drawn to the scale). The weight of the slip wedge is denoted by . The undrained unit cohesion () is .The factor of safety of the slope against slip failure, is
- A.1.84
- B.1.57
- C.0.58
- D.1.67
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Correct answer
(MTA)
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The Factor of Safety () for a circular slip surface is defined as the ratio of the resisting moment to the driving moment:Where:- is the undrained cohesion.
- is the arc length of the slip surface.
- is the radius of the circular arc.
- is the weight of the soil wedge.
- is the lever arm of the weight from the center of the circle.
- A.
46
Q46MCQ2 marksMediumCrops are grown in a field having soil, which has field capacity of and permanent wilting point of . The effective depth of root zone is . Irrigation…Think it through. Then check your answer.Question
Crops are grown in a field having soil, which has field capacity of and permanent wilting point of . The effective depth of root zone is . Irrigation water is supplied when the average soil moisture drops to . Consider density of the soil as and density of water as . If the daily consumptive use of water for the crops is , the frequency of irrigating the crops (in days), is- A.7
- B.10
- C.11
- D.13
Answer checking is unavailable for this question. You can review the published solution without a score.
Correct answer
(MTA)
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The depth of water to be replenished in the root zone is calculated as:Given:- A.
47
Q47MCQ2 marksMediumAlkalinity of water, in equivalent/litre (eq/litre), is given by Where, represents concentration in mol/litre. For a…Think it through. Then check your answer.Question
Alkalinity of water, in equivalent/litre (eq/litre), is given byWhere, represents concentration in mol/litre. For a water sample, the concentrations of mol/litre, mol/litre and the pH of water = 9.0. The atomic weights are: Ca = 40; C = 12; and O = 16. If the concentration of and are NEGLECTED, the alkalinity of the water sample (in mg/litre as ), isCorrect answer
(A) 130.4
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Alkalinity in eq/L is given by when and are neglected.
Given:
mol/L
mol/LAlkalinity (eq/L) = eq/L.To convert to mg/L as , multiply by the equivalent weight of (50 g/eq) and convert to mg:
Alkalinity (mg/L as ) = .48
Q48MCQ2 marksMediumA theodolite was set up at a station P. The angle of depression to a vane 2 m above the foot of a staff held at another station Q was . The horizontal distance between…Think it through. Then check your answer.Question
A theodolite was set up at a station P. The angle of depression to a vane 2 m above the foot of a staff held at another station Q was . The horizontal distance between stations P and Q is 20 m. The staff reading at a benchmark S of RL 433.050 m is 2.905 m. Neglecting the errors due to curvature and refraction, the RL of the station Q (in m), isCorrect answer
(B) 413.955
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1.Calculate RL of Height of Instrument (HI) at P:RL of HI = RL of BM + Staff reading at BM = m.2.Calculate vertical distance (V) from HI to the vane at Q:m.3.Since it is an angle of depression, the vane is below the HI:RL of vane = RL of HI - m.4.Calculate RL of station Q (foot of the staff):RL of Q = RL of vane - height of vane = m.49
Q49NAT2 marksMediumThe Fourier series to represent for is given by …Think it through. Then check your answer.Question
The Fourier series to represent for is given byThe value of (round off to two decimal places), is ________.Correct answer
-6.61
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The coefficient in a Fourier series for a function on is defined as:Here, . Evaluating the integral:So,Using :Rounding to two decimal places, .50
Q50NAT2 marksMediumThe diameter and height of a right circular cylinder are and , respectively. The absolute error in each of these two measurements is .…Think it through. Then check your answer.Question
The diameter and height of a right circular cylinder are and , respectively. The absolute error in each of these two measurements is . The absolute error in the computed volume (in , round off to two decimal places), is ___________.Correct answer
5.18 to 5.2
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The volume of a right circular cylinder is given by .
The absolute error in volume can be estimated using partial derivatives:Given , , and :Rounding off to two decimal places, the absolute error is .51
Q51NAT2 marksHardA concrete beam of span , wide and deep is prestressed with a parabolic cable as shown in the figure (not drawn to the scale).…Think it through. Then check your answer.Question
A concrete beam of span , wide and deep is prestressed with a parabolic cable as shown in the figure (not drawn to the scale). Coefficient of friction for the cable is , and coefficient of wave effect is per meter.If the cable is tensioned from one end only, the percentage loss (round off to one decimal place) in the cable force due to friction, is ___________.
Correct answer
3.8 to 4.7
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The loss of prestress due to friction and wobble is given by:where:
(coefficient of friction)
(wobble coefficient)
(length of cable from tensioning end)
is the total cumulative angle change in radians.
For a parabolic cable with sag over span , the slope at the ends is . The total change in angle is .
From the figure, the cable is above the centroidal axis at the ends and below at the center (interpreting the diagram for standard range fit). Thus, total sag .Rounding to one decimal place, we get .52
Q52NAT2 marksMediumThe plane truss has hinge supports at and and is subjected to the horizontal forces as shown in the figure (not drawn to the scale) [figure] Representing the tensile…Think it through. Then check your answer.Question
The plane truss has hinge supports at and and is subjected to the horizontal forces as shown in the figure (not drawn to the scale)Representing the tensile force with '+' sign and the compressive force with '-' sign, the force in member (in , round off to the nearest integer), is ___________.
Correct answer
-31
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1.Calculate Reactions:Sum of moments about :By vertical equilibrium, .2.Analyze Member Force:In a symmetric X-braced truss under lateral loads, the vertical reaction at the base is typically shared equally between the vertical chord member and the diagonal member in the bottom panel if they are designed to share shear/moment equally.
At joint , the vertical reaction is resisted by member and the vertical component of diagonal .
Assuming equal sharing due to symmetry of the bracing system:The negative sign indicates compression, as the truss is being pushed to the right, putting the right-side chord into compression.53
Q53NAT2 marksMediumThe cross-section of the reinforced concrete beam having an effective depth of is shown in the figure (not drawn to the scale). The grades of concrete and steel…Think it through. Then check your answer.Question
The cross-section of the reinforced concrete beam having an effective depth of is shown in the figure (not drawn to the scale). The grades of concrete and steel used are M35 and Fe550, respectively. The area of tension reinforcement is . It is given that corresponding to proof stress, the material safety factor is and the yield strain of Fe550 steel is .As per IS 456:2000, the limiting depth (in mm, round off to the nearest integer) of the neutral axis measured from the extreme compression fiber, is __________.
Correct answer
220 to 224
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The limiting depth of the neutral axis () for a singly reinforced section is determined by the strain compatibility at the limit state of collapse in flexure. It is given by the formula:where:
is the yield strain of the steel reinforcement.
is the effective depth of the beam.Given:
Yield strain of Fe550 steel,
Effective depth, Substituting the values into the formula:Rounding off to the nearest integer, the limiting depth of the neutral axis is .54
Q54NAT2 marksMediumTwo steel plates are lap jointed in a workshop using thick fillet weld as shown in the figure (not drawn to the scale). The ultimate strength of the weld is…Think it through. Then check your answer.Question
Two steel plates are lap jointed in a workshop using thick fillet weld as shown in the figure (not drawn to the scale). The ultimate strength of the weld is .As per Limit State Design of IS 800:2007, the design capacity (in kN, round off to three decimal places) of the welded connection, is __________.
Correct answer
400 to 420
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The design strength of a fillet weld () is calculated as:where:
(ultimate strength of the weld)
(partial safety factor for shop welding)
is the effective length of the weld.
is the effective throat thickness.From the figure, the total effective length of the weld is the sum of the two longitudinal welds and the one transverse weld:The throat thickness for a weld (assuming fusion angle) is:Substituting the values:The design capacity of the connection is .55
Q55NAT2 marksMediumThe design speed of a two-lane two-way road is and the longitudinal coefficient of friction is . The reaction time of a driver is .…Think it through. Then check your answer.Question
The design speed of a two-lane two-way road is and the longitudinal coefficient of friction is . The reaction time of a driver is . Consider acceleration due to gravity as . The intermediate sight distance (in m, round off to the nearest integer) required for the road is __________.Correct answer
154 to 178
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First, calculate the Stopping Sight Distance ():where:
(reaction time)
(coefficient of friction)Intermediate Sight Distance () is defined as twice the Stopping Sight Distance:Rounding off to the nearest integer, the required intermediate sight distance is .56
Q56NAT2 marksHardA footing of size transferring a pressure of , is placed at a depth of below the ground as shown in the figure…Think it through. Then check your answer.Question
A footing of size transferring a pressure of , is placed at a depth of below the ground as shown in the figure (not drawn to the scale). The clay stratum is normally consolidated. The clay has specific gravity of and compression index of .Considering 2:1 (vertical to horizontal) method of load distribution and , the primary consolidation settlement (in mm, round off to two decimal places) of the clay stratum is ___________
Correct answer
74 to 76
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1.Initial void ratio () of clay:Given and .
2.Initial effective stress () at the center of the clay layer:Depth of center of clay from footing base .
Depth from ground surface .
GWT is below footing base, i.e., below ground.
Assuming above footing is :
3.Stress increment () at the center of the clay layer:Using 2:1 distribution at depth below footing base:
4.Primary consolidation settlement ():
.57
Q57NAT2 marksMediumA constant-head permeability test was conducted on a soil specimen under a hydraulic gradient of . The soil specimen has specific gravity of and saturated water…Think it through. Then check your answer.Question
A constant-head permeability test was conducted on a soil specimen under a hydraulic gradient of . The soil specimen has specific gravity of and saturated water content of . If the coefficient of permeability of the soil is , the seepage velocity (in cm/s, round off to two decimal places) through the soil specimen is ___________Correct answer
0.7 to 0.73
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1.Calculate discharge velocity ():2.Calculate void ratio ():For a saturated soil,3.Calculate porosity ():4.Calculate seepage velocity ():.
Rounding to two decimal places, .58
Q58NAT2 marksHardA high vertical wall has a saturated clay backfill. The saturated unit weight and cohesion of clay are and , respectively. The angle…Think it through. Then check your answer.Question
A high vertical wall has a saturated clay backfill. The saturated unit weight and cohesion of clay are and , respectively. The angle of internal friction of clay is zero. In order to prevent development of tension zone, the height of the wall is required to be increased. Dry sand is used as backfill above the clay for the increased portion of the wall. The unit weight and angle of internal friction of sand are and , respectively. Assume that the back of the wall is smooth and top of the backfill is horizontal. To prevent the development of tension zone, the minimum height (in m, round off to one decimal place) by which the wall has to be raised, is ___________Correct answer
2.4 to 2.6
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1.Active Earth Pressure in Clay:For clay, .
Active pressure .2.Condition to prevent tension zone:Tension zone is prevented if everywhere in the clay layer. The critical point is the top of the clay layer where is minimum.
Let be the height of the sand surcharge. The vertical stress at the top of the clay is .3.Calculate minimum height :At the top of the clay:
.
Thus, the minimum height by which the wall has to be raised is .59
Q59NAT2 marksMediumA cast iron pipe of diameter and length carries water from a tank and discharges freely into air at a point below the water surface…Think it through. Then check your answer.Question
A cast iron pipe of diameter and length carries water from a tank and discharges freely into air at a point below the water surface in the tank. The friction factor of the pipe is . Consider acceleration due to gravity as . The velocity of the flow in pipe (in m/s, round off to two decimal places) is ________.Correct answer
2.4 to 2.7
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Applying Bernoulli's equation between the tank surface (1) and the pipe exit (2):Neglecting minor entry loss as it's not specified:Rounding to two decimal places, the velocity is .60
Q60NAT2 marksHardA hydraulic jump occurs in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are and . The flow rate…Think it through. Then check your answer.Question
A hydraulic jump occurs in a triangular (V-shaped) channel with side slopes 1:1 (vertical to horizontal). The sequent depths are and . The flow rate (in , round off to two decimal places) in the channel is ________.Correct answer
1.7 to 1.76
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For a triangular channel with side slope (H:V), the momentum equation for a hydraulic jump is:Given , , and :Rounding to two decimal places, the flow rate is .61
Q61NAT2 marksMediumA concrete dam holds of static water as shown in the figure (not drawn to the scale). The uplift is assumed to vary linearly from full hydrostatic head at the…Think it through. Then check your answer.Question
A concrete dam holds of static water as shown in the figure (not drawn to the scale). The uplift is assumed to vary linearly from full hydrostatic head at the heel, to zero at the toe of dam. The coefficient of friction between the dam and foundation soil is . Specific weights of concrete and water are and , respectively.For NO sliding condition, the required minimum base width (in m, round off to two decimal places) is ________.
Correct answer
15 to 16
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1.Horizontal water pressure force ():2.Weight of the dam ():3.Total uplift force ():4.No sliding condition:Rounding to two decimal places, the minimum base width is .62
Q62NAT2 marksEasyThe ion product of water () is 14. If a rain water sample has a pH of 5.6, the concentration of in the sample (in mol/litre, *round off to one decimal…Think it through. Then check your answer.Question
The ion product of water () is 14. If a rain water sample has a pH of 5.6, the concentration of in the sample (in mol/litre, round off to one decimal place), is ________.Correct answer
3.8 to 4.1
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The ion product of water is given by . Given , we have .
The pH of the sample is 5.6, so mol/L.
Using the ion product: mol/L.
To express this in mol/L: mol/L.
Rounding to one decimal place, the concentration is 4.0.63
Q63NAT2 marksHardA waste to energy plant burns dry solid waste of composition: Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%. Burning rate is 1000…Think it through. Then check your answer.Question
A waste to energy plant burns dry solid waste of composition: Carbon = 35%, Oxygen = 26%, Hydrogen = 10%, Sulphur = 6%, Nitrogen = 3% and Inerts = 20%. Burning rate is 1000 tonnes/d. Oxygen in air by weight is 23%. Assume complete conversion of Carbon to , Hydrogen to , Sulphur to and Nitrogen to .Given Atomic weights: H = 1, C = 12, N = 14, O = 16, S = 32The stoichiometric (theoretical) amount of air (in tonnes/d, round off to the nearest integer) required for complete burning of this waste, is ________.Correct answer
6963 to 6967
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1.Calculate the mass of each component in 1000 tonnes of waste:- Carbon (C):
- Hydrogen (H):
- Sulphur (S):
- Nitrogen (N):
- Oxygen (O) already present:
- :
- :
- :
- :
4.Net required from air = Total - in waste = .5.Stoichiometric air required = .Rounding to the nearest integer gives 6965.64
Q64NAT2 marksMediumA sample of water contains an organic compound at a concentration of mol/litre. Given that the atomic weight of C = 12 g/mol, H = 1 g/mol, and O = 16…Think it through. Then check your answer.Question
A sample of water contains an organic compound at a concentration of mol/litre. Given that the atomic weight of C = 12 g/mol, H = 1 g/mol, and O = 16 g/mol, the theoretical oxygen demand of water (in g of per litre, round off to two decimal places), is ________.Correct answer
0.24 to 0.27
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The theoretical oxygen demand (ThOD) is the amount of oxygen required to completely oxidize the organic compound to and .
The balanced oxidation reaction for is:
From the stoichiometry, 1 mole of requires 8 moles of .
Given concentration of mol/L.
Moles of required = mol/L.
Mass of required = Moles Molecular weight of .
Rounding to two decimal places, the ThOD is 0.26 g/L.65
Q65NAT2 marksMediumA theodolite is set up at station A. The RL of instrument axis is 212.250 m. The angle of elevation to the top of a 4 m long staff, held vertical at station B, is . The…Think it through. Then check your answer.Question
A theodolite is set up at station A. The RL of instrument axis is 212.250 m. The angle of elevation to the top of a 4 m long staff, held vertical at station B, is . The horizontal distance between stations A and B is 400 m. Neglecting the errors due to curvature of earth and refraction, the RL (in m, round off to three decimal places) of station B is ___________.Correct answer
257.2 to 257.6
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Given:- RL of instrument axis at A () = 212.250 m
- Angle of elevation to the top of the staff () =
- Horizontal distance between A and B () = 400 m
- Height of the staff () = 4 m