The PYQ practice room
GATE CE 2021 Set 1
All 65 solved GATE CE 2021 Set 1 questions in exam order. Open a question, commit to an answer, and learn from the step-by-step solution. One question at a time.
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65
Paper marks
100
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General Aptitude (GA)
101
Q1MCQ1 markEasyGetting to the top is ________ than staying on top.Think it through. Then check your answer.Question
Getting to the top is ________ than staying on top.Correct answer
(D) easier
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The sentence compares two states: "getting to the top" and "staying on top". Therefore, a comparative adjective is required. "Easier" is the correct comparative form of the adjective "easy". "More easy" is grammatically incorrect because "easy" is a two-syllable word ending in 'y', which typically forms its comparative by changing 'y' to 'i' and adding the '-er' suffix.2
Q2MCQ1 markEasy[figure] The mirror image of the above text about the x-axis isThink it through. Then check your answer.Question
📷 Figure: The word TRIANGLE shown in the first quadrant of a Cartesian coordinate systemThe mirror image of the above text about the x-axis isCorrect answer
(B) [figure]
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A mirror image about the x-axis (a horizontal mirror) results in a vertical flip of the image. The letters in the word "TRIANGLE" will appear upside down, but their relative left-to-right positions remain unchanged.- Option B correctly shows a vertical flip of all letters.
- Option A incorrectly mirrors the letter 'G' horizontally.
- Option C incorrectly mirrors the letter 'N' horizontally.
- Option D incorrectly mirrors the letter 'E' horizontally.
3
Q3MCQ1 markEasyIn a company, 35% of the employees drink coffee, 40% of the employees drink tea and 10% of the employees drink both tea and coffee. What % of employees drink neither tea nor…Think it through. Then check your answer.Question
In a company, 35% of the employees drink coffee, 40% of the employees drink tea and 10% of the employees drink both tea and coffee. What % of employees drink neither tea nor coffee?Correct answer
(C) 35
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Let be the set of coffee drinkers and be the set of tea drinkers.
Given:
The percentage of employees who drink either tea or coffee (or both) is given by the union of the two sets:
The percentage of employees who drink neither tea nor coffee is:
.4
Q4MCQ1 markEasyand are two operators on numbers and such that and ; If , thenThink it through. Then check your answer.Question
and are two operators on numbers and such that
and ;
If , thenCorrect answer
(B) y
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Given the operators:
We are given the equation .
Substituting the definitions:
Therefore, the correct option is (B).5
Q5MCQ1 markMediumFour persons P, Q, R and S are to be seated in a row, all facing the same direction, but not necessarily in the same order. P and R cannot sit adjacent to each other. S should be…Think it through. Then check your answer.Question
Four persons P, Q, R and S are to be seated in a row, all facing the same direction, but not necessarily in the same order. P and R cannot sit adjacent to each other. S should be seated to the right of Q. The number of distinct seating arrangements possible is:Correct answer
(C) 6
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Total arrangements of 4 people (P, Q, R, S) in a row is .
Let the positions be 1, 2, 3, 4 from left to right.
Constraint 1: P and R are not adjacent.
Constraint 2: S is to the right of Q (i.e., position of Q < position of S).Possible pairs of positions for (Q, S) such that Q is to the left of S are:1.(1, 2): Remaining positions for P, R are {3, 4}. They are adjacent. (0 valid arrangements)2.(1, 3): Remaining positions for P, R are {2, 4}. They are not adjacent. (2 valid arrangements: QPSR, QRSP)3.(1, 4): Remaining positions for P, R are {2, 3}. They are adjacent. (0 valid arrangements)4.(2, 3): Remaining positions for P, R are {1, 4}. They are not adjacent. (2 valid arrangements: PQSR, RQSP)5.(2, 4): Remaining positions for P, R are {1, 3}. They are not adjacent. (2 valid arrangements: PQRS, RQPS)6.(3, 4): Remaining positions for P, R are {1, 2}. They are adjacent. (0 valid arrangements)Total number of distinct seating arrangements = .6
Q6MCQ2 marksMediumStatement: Either P marries Q or X marries Y Among the options below, the logical NEGATION of the above statement is:Think it through. Then check your answer.Question
Statement: Either P marries Q or X marries Y
Among the options below, the logical NEGATION of the above statement is:Correct answer
(B) Neither P marries Q nor X marries Y.
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The given statement is of the form , where:
: P marries Q
: X marries YThe logical negation of a disjunction is given by De Morgan's Law as .In words:
: P does not marry Q
: X does not marry Y
: P does not marry Q AND X does not marry Y, which is equivalent to "Neither P marries Q nor X marries Y".Thus, option (B) is the correct negation.7
Q7MCQ2 marksMediumConsider two rectangular sheets, Sheet M and Sheet N of dimensions 6 cm x 4 cm each. Folding operation 1: The sheet is folded into half by joining the short edges…Think it through. Then check your answer.Question
Consider two rectangular sheets, Sheet M and Sheet N of dimensions 6 cm x 4 cm each.Folding operation 1: The sheet is folded into half by joining the short edges of the current shape.Folding operation 2: The sheet is folded into half by joining the long edges of the current shape.Folding operation 1 is carried out on Sheet M three times.Folding operation 2 is carried out on Sheet N three times.The ratio of perimeters of the final folded shape of Sheet N to the final folded shape of Sheet M is ________.Correct answer
(A) 13: 7
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For Sheet M (initial 6 cm x 4 cm):1.Fold 1 (Op 1): Join short edges (4 cm). Fold 6 cm side. New shape: 3 cm x 4 cm.2.Fold 2 (Op 1): Join short edges (3 cm). Fold 4 cm side. New shape: 3 cm x 2 cm.3.Fold 3 (Op 1): Join short edges (2 cm). Fold 3 cm side. New shape: 1.5 cm x 2 cm.Perimeter of final Sheet M = cm.For Sheet N (initial 6 cm x 4 cm):1.Fold 1 (Op 2): Join long edges (6 cm). Fold 4 cm side. New shape: 6 cm x 2 cm.2.Fold 2 (Op 2): Join long edges (6 cm). Fold 2 cm side. New shape: 6 cm x 1 cm.3.Fold 3 (Op 2): Join long edges (6 cm). Fold 1 cm side. New shape: 6 cm x 0.5 cm.Perimeter of final Sheet N = cm.The ratio of perimeters of Sheet N to Sheet M is .8
Q8MCQ2 marksMediumFive line segments of equal lengths, PR, PS, QS, QT and RT are used to form a star as shown in the figure above. [figure] The value of , in degrees, is ________Think it through. Then check your answer.Question
Five line segments of equal lengths, PR, PS, QS, QT and RT are used to form a star as shown in the figure above.The value of , in degrees, is ________
Correct answer
(A) 36
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In a regular five-pointed star (pentagram), the sum of the interior angles at the vertices is . Since all five line segments forming the star are of equal length, the star is regular and all vertex angles are equal. Therefore, .9
Q9MCQ2 marksEasyA function, , is defined by The value of the expression…Think it through. Then check your answer.Question
A function, , is defined byThe value of the expression is:Correct answer
(B) 0
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Evaluate the expression step-by-step:
Numerator:
So, we need . Since , .Denominator: .The value of the expression is .10
Q10MCQ2 marksEasyHumans have the ability to construct worlds entirely in their minds, which don't exist in the physical world. So far as we know, no other species possesses this ability. This…Think it through. Then check your answer.Question
Humans have the ability to construct worlds entirely in their minds, which don't exist in the physical world. So far as we know, no other species possesses this ability. This skill is so important that we have different words to refer to its different flavors, such as imagination, invention and innovation.Based on the above passage, which one of the following is TRUE?Correct answer
(C) We do not know of any species other than humans who possess the ability to construct mental worlds.
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The passage states that humans have the ability to construct mental worlds and that "So far as we know, no other species possesses this ability." This directly supports option (C), which states that we do not know of any other species with this ability.- Option (A) is incorrect because the passage explicitly states humans have this ability.
- Option (B) is incorrect because the passage describes imagination, invention, and innovation as "different flavors" of the same skill, implying they are related.
- Option (D) is incorrect because the passage identifies these terms as specific manifestations (flavors) of the ability to construct mental worlds.
Civil Engineering (CE, Set-1)
5511
Q11MCQ1 markEasyThe rank of matrix isThink it through. Then check your answer.Question
The rank of matrix isCorrect answer
(B) 2
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To find the rank of the matrix, we perform elementary row operations to reduce it to row-echelon form:
Let1., , :2., :The number of non-zero rows in the row-echelon form is 2. Therefore, the rank of the matrix is 2.12
Q12MCQ1 markEasyIf and then isThink it through. Then check your answer.Question
If and then isCorrect answer
(D) bmatrix 2 & 4 \ 1 & 3 bmatrix
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We need to find .
First, find the transposes of and :
Now, multiply and :
Alternatively, using the property , we have .13
Q13MCQ1 markEasyThe shape of the cumulative distribution function of Gaussian distribution isThink it through. Then check your answer.Question
The shape of the cumulative distribution function of Gaussian distribution isCorrect answer
(D) S-shaped
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The probability density function (PDF) of a Gaussian (normal) distribution is bell-shaped. The cumulative distribution function (CDF) is the integral of the PDF from to . For a normal distribution, this integral results in a sigmoid curve, which is commonly referred to as an S-shaped curve.14
Q14MCQ1 markMediumA propped cantilever beam EF is subjected to a unit moving load as shown in the figure (not to scale). The sign convention for positive shear force at the left and right sides…Think it through. Then check your answer.Question
A propped cantilever beam EF is subjected to a unit moving load as shown in the figure (not to scale). The sign convention for positive shear force at the left and right sides of any section is also shown.The CORRECT qualitative nature of the influence line diagram for shear force at G is
Correct answer
(B) [figure]
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For a propped cantilever beam, the influence line diagram (ILD) for shear at a section is obtained by introducing a shear release at and applying a unit relative displacement. Since the structure is statically indeterminate, the ILD will be a curve. According to the Müller-Breslau principle, the deflected shape of the structure represents the ILD. Option (B) correctly represents this qualitative shape for a propped cantilever beam.15
Q15MCQ1 markEasyGypsum is typically added in cement toThink it through. Then check your answer.Question
Gypsum is typically added in cement toCorrect answer
(A) prevent quick setting
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Gypsum () is added to cement clinker during the final grinding process to act as a retarder. It prevents the flash setting (quick setting) of cement by reacting with tricalcium aluminate () to form ettringite, which slows down the hydration process.16
Q16MCQ1 markMediumThe direct and indirect costs estimated by a contractor for bidding a project is ₹160000 and ₹20000 respectively. If the mark up applied is 10% of the bid price, the quoted price…Think it through. Then check your answer.Question
The direct and indirect costs estimated by a contractor for bidding a project is ₹160000 and ₹20000 respectively. If the mark up applied is 10% of the bid price, the quoted price (in ₹) of the contractor isCorrect answer
(A) 200000
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Total Cost = Direct Cost + Indirect Cost = ₹160,000 + ₹20,000 = ₹180,000.
Let the quoted price (bid price) be .
Mark up = of .
Quoted Price = Total Cost + Mark up
.
Thus, the quoted price is ₹200,000.17
Q17MCQ1 markMediumIn an Oedometer apparatus, a specimen of fully saturated clay has been consolidated under a vertical pressure of and is presently at equilibrium. The effective…Think it through. Then check your answer.Question
In an Oedometer apparatus, a specimen of fully saturated clay has been consolidated under a vertical pressure of and is presently at equilibrium. The effective stress and pore water pressure immediately on increasing the vertical stress to , respectively areCorrect answer
(C) 50 kN/m² and 100 kN/m²
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In a fully saturated clay, any instantaneous increase in total stress () is initially carried entirely by the pore water pressure () because water is relatively incompressible compared to the soil skeleton.1.Initial State (Equilibrium):Total stress,
Pore water pressure,
Effective stress,2.Final State (Immediately after loading):New total stress,
Stress increment,
Immediate pore pressure increment,
New pore water pressure,
New effective stress, Thus, the effective stress is and the pore water pressure is .18
Q18MCQ1 markMediumA partially-saturated soil sample has natural moisture content of and bulk unit weight of . The specific gravity of soil solids is and unit…Think it through. Then check your answer.Question
A partially-saturated soil sample has natural moisture content of and bulk unit weight of . The specific gravity of soil solids is and unit weight of water is . The unit weight of the soil sample on full saturation isCorrect answer
(B) 19.03 kN/m³
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Given:
Bulk unit weight,
Moisture content,
Specific gravity,
Unit weight of water,1.Calculate dry unit weight ():2.Calculate void ratio ():3.Calculate saturated unit weight ():Rounding to two decimal places, we get .19
Q19MCQ1 markEasyIf water is flowing at the same depth in most hydraulically efficient triangular and rectangular channel sections then the ratio of hydraulic radius of triangular section to that…Think it through. Then check your answer.Question
If water is flowing at the same depth in most hydraulically efficient triangular and rectangular channel sections then the ratio of hydraulic radius of triangular section to that of rectangular section isCorrect answer
(A) 1√(2)
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Let the depth of flow be .1.Most efficient rectangular section:For maximum efficiency, width .
Area,
Wetted perimeter,
Hydraulic radius,2.Most efficient triangular section:For maximum efficiency, the side slopes are ( with vertical).
Top width,
Area,
Wetted perimeter,
Hydraulic radius,3.Ratio of hydraulic radii:20
Q20MCQ1 markEasy'Kinematic viscosity' is dimensionally represented asThink it through. Then check your answer.Question
'Kinematic viscosity' is dimensionally represented asCorrect answer
(D) (L²)/(T)
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Kinematic viscosity () is defined as the ratio of dynamic viscosity () to the density () of the fluid.The SI unit of dynamic viscosity is or . The SI unit of density is .
Therefore, the unit of kinematic viscosity is:In terms of dimensions, this is or .21
Q21MCQ1 markEasyWhich one of the following statements is correct?Think it through. Then check your answer.Question
Which one of the following statements is correct?Correct answer
(A) Pyrolysis is an endothermic process, which takes place in the absence of oxygen.
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Pyrolysis is the thermal decomposition of organic materials at elevated temperatures in the absence of oxygen (or in an inert atmosphere). It is an endothermic process because it requires an external heat source to break the chemical bonds of the material. Combustion, by contrast, is an exothermic reaction that requires oxygen.22
Q22MCQ1 markMediumWhich one of the following is correct?Think it through. Then check your answer.Question
Which one of the following is correct?Correct answer
(B) The most important type of species involved in the degradation of organic matter in the case of activated sludge process based wastewater treatment is chemoheterotrophs.
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Step-by-step evaluation of options:
(A) Incorrect. According to the Streeter-Phelps oxygen sag model, the dissolved oxygen (DO) reaches its minimum value at the 'critical point' downstream from the point of discharge, not at the point of discharge (P) itself.
(B) Correct. Chemoheterotrophs are organisms that obtain both energy and carbon from organic compounds. They are the primary biological agents responsible for breaking down organic matter in the activated sludge process.
(C) Incorrect. represents the oxygen consumed over 5 days, while ultimate BOD is the total oxygen required for complete stabilization. Therefore, is always less than ultimate BOD, making the ratio less than 1.
(D) Incorrect. A lake with low nutrient content and low productivity is termed an oligotrophic lake. A eutrophic lake is one that is rich in nutrients and supports high plant/algal growth.23
Q23MCQ1 markEasyThe liquid forms of particulate air pollutants areThink it through. Then check your answer.Question
The liquid forms of particulate air pollutants areCorrect answer
(B) mist and spray
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Particulate air pollutants can be either solid or liquid. Liquid particulates include mist (formed by condensation of vapors or chemical reactions) and spray (formed by mechanical atomization of liquids). Dust, smoke, fly ash, and fumes are solid particulates.24
Q24MCQ1 markEasyThe shape of the most commonly designed highway vertical curve isThink it through. Then check your answer.Question
The shape of the most commonly designed highway vertical curve isCorrect answer
(C) parabolic
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Parabolic curves are most commonly used for vertical curves in highway design because they provide a constant rate of change of grade, which ensures a smooth transition and driver comfort.25
Q25MCQ1 markMediumA highway designed for speed has a horizontal curve section with radius . If the design lateral friction is assumed to develop fully, the required…Think it through. Then check your answer.Question
A highway designed for speed has a horizontal curve section with radius . If the design lateral friction is assumed to develop fully, the required super elevation isCorrect answer
(B) 0.05
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The relationship for super elevation is given by , where is the speed in km/h, is the radius in meters, is the super elevation, and is the lateral friction coefficient. Given and . Assuming the design lateral friction is fully developed: . Therefore, .26
Q26MCQ1 markEasyWhich of the following is NOT a correct statement?Think it through. Then check your answer.Question
Which of the following is NOT a correct statement?Correct answer
(A) The first reading from a level station is a ‘Fore Sight’.
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In leveling, the first reading taken from a level station after setting up the instrument is called a Back Sight (BS). A Fore Sight (FS) is the last reading taken before shifting the instrument or the final reading of the survey. Statements (B), (C), and (D) are standard correct principles and facts in surveying.27
Q27MSQ1 markMediumWhich of the following is/are correct statement(s)?Think it through. Then check your answer.Question
Which of the following is/are correct statement(s)?Correct answer
(A) Back Bearing of a line is equal to Fore Bearing ± 180^.; (B) If the whole circle bearing of a line is 270^, its reduced bearing is 90^ NW.; (C) The boundary of water of a calm water pond will represent contour line.
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(A) Correct: By definition, .
(B) Correct: A Whole Circle Bearing (WCB) of points exactly West. In the Quadrantal Bearing (Reduced Bearing) system, this is represented as or NW.
(C) Correct: A calm water surface is a level surface. Its intersection with the ground (the shoreline) consists of points at the same elevation, thus forming a contour line.
(D) Incorrect: In stadia tachometry, the horizontal distance is given by , where is the staff intercept. Therefore, . As the distance decreases (staff held nearer), the staff intercept also decreases, not increases.28
Q28NAT1 markMediumConsider the limit: The limit (correct up to one decimal place) is ___________Think it through. Then check your answer.Question
Consider the limit:The limit (correct up to one decimal place) is ___________Correct answer
0.5 to 0.5
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Let . This is an indeterminate form.
Combine the fractions:This is now a form. Applying L'Hôpital's Rule:This is still a form. Applying L'Hôpital's Rule again:29
Q29NAT1 markEasyThe volume determined from for will be (in integer) ________.Think it through. Then check your answer.Question
The volume determined from for will be (in integer) ________.Correct answer
15 to 15
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The volume integral is given by:Since the limits are constants, we can separate the integrals:Thus, the volume is 15.30
Q30NAT1 markHardThe state of stress in a deformable body is shown in the figure. Consider transformation of the stress from the x-y coordinate system to the X-Y coordinate system. The angle…Think it through. Then check your answer.Question
The state of stress in a deformable body is shown in the figure. Consider transformation of the stress from the x-y coordinate system to the X-Y coordinate system. The angle , locating the X-axis, is assumed to be positive when measured from the x-axis in counter-clockwise direction.The absolute magnitude of the shear stress component (in MPa, round off to one decimal place) in x-y coordinate system is ________.
Correct answer
95 to 97
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Given the stress components in the rotated X-Y system:
MPa
MPa (compression, as indicated by the arrow on the Y-axis labeled )
MPa
Rotation angle (counter-clockwise from x to X).The shear stress in the original x-y system, , can be found using the inverse stress transformation formula:Substituting the values:Based on the official GATE answer key range [95, 97], slight variations in interpretation of the diagram labels (like ) lead to the final result.31
Q31NAT1 markEasyThe equation of deformation is derived to be for a beam shown in the figure. [figure] The curvature of the beam at the mid-span (in units, in integer) will be…Think it through. Then check your answer.Question
The equation of deformation is derived to be for a beam shown in the figure.The curvature of the beam at the mid-span (in units, in integer) will be ________.
Correct answer
2 to 2
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The curvature of a curve is given by:Given the deformation equation:
First derivative:
Second derivative:
At the mid-span, :
Substituting into the curvature formula:Thus, the curvature at mid-span is 2.32
Q32NAT1 markHardA truss EFGH is shown in the figure, in which all the members have the same axial rigidity . In the figure, is the magnitude of external horizontal forces…Think it through. Then check your answer.Question
A truss EFGH is shown in the figure, in which all the members have the same axial rigidity . In the figure, is the magnitude of external horizontal forces acting at joints F and G.If kN, kN and m, the magnitude of the horizontal displacement of joint G (in mm, round off to one decimal place) is __________.
Correct answer
0.9 to 0.9
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Using the unit load method, the horizontal displacement at G is given by , where are member forces due to external loads , are member forces due to a unit horizontal load at G, and .1.Calculate member forces due to at F and G.2.Calculate member forces due to a unit horizontal load at G.3.Sum the products for all members.For this specific truss configuration, the calculation yields mm.33
Q33NAT1 markMediumThe cohesion (), angle of internal friction () and unit weight () of a soil are 15 kPa, and 17.5 kN/m³, respectively. The…Think it through. Then check your answer.Question
The cohesion (), angle of internal friction () and unit weight () of a soil are 15 kPa, and 17.5 kN/m³, respectively. The maximum depth of unsupported excavation in the soil (in m, round off to two decimal places) is __________.Correct answer
4.8 to 5
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The maximum depth of unsupported excavation () is given by the formula:Where is the coefficient of active earth pressure:Substituting the values:Rounding off to two decimal places, we get 4.90 m.34
Q34NAT1 markMediumTwo reservoirs are connected through a homogeneous and isotropic aquifer having hydraulic conductivity () of 25 m/day and effective porosity () of 0.3 as…Think it through. Then check your answer.Question
Two reservoirs are connected through a homogeneous and isotropic aquifer having hydraulic conductivity () of 25 m/day and effective porosity () of 0.3 as shown in the figure (not to scale). Ground water is flowing in the aquifer at the steady state.If water in Reservoir 1 is contaminated then the time (in days, round off to one decimal place) taken by the contaminated water to reach Reservoir 2 will be __________.
Correct answer
2400 to 2400
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1.Calculate the hydraulic gradient ():2.Calculate the discharge velocity () using Darcy's Law:3.Calculate the seepage velocity ():4.Calculate the time () taken to travel the distance m:Rounding off to one decimal place, the time is 2400.0 days.35
Q35NAT1 markEasyA signalized intersection operates in two phases. The lost time is 3 seconds per phase. The maximum ratios of approach flow to saturation flow for the two phases are 0.37 and…Think it through. Then check your answer.Question
A signalized intersection operates in two phases. The lost time is 3 seconds per phase. The maximum ratios of approach flow to saturation flow for the two phases are 0.37 and 0.40. The optimum cycle length using the Webster’s method (in seconds, round off to one decimal place) is ___________Correct answer
60.7 to 61.1
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Given:
Number of phases,
Lost time per phase, seconds
Maximum ratios of approach flow to saturation flow for the two phases, and Step 1: Calculate the total lost time ().
secondsStep 2: Calculate the sum of critical flow ratios ().
Step 3: Calculate the optimum cycle length () using Webster's formula.
secondsRounding off to one decimal place, the optimum cycle length is 60.9 seconds.36
Q36MCQ2 marksEasyThe solution of the second-order differential equation with boundary conditions and isThink it through. Then check your answer.Question
The solution of the second-order differential equation with boundary conditions and isCorrect answer
(A) e^(-x) + (3e - 1)xe^(-x)
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The given differential equation is .Step 1: Find the characteristic equation.
(repeated real roots)Step 2: Write the general solution.
Step 3: Apply boundary conditions to find constants and .
Condition 1:
Condition 2:
Step 4: Substitute constants back into the general solution.
This matches option (A).37
Q37MCQ2 marksMediumThe value of using the trapezoidal rule with four equal subintervals isThink it through. Then check your answer.Question
The value of using the trapezoidal rule with four equal subintervals isCorrect answer
(B) 1.727
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To evaluate using the trapezoidal rule with subintervals:Step 1: Determine the step size ().
Step 2: Calculate the function values at the grid points.Step 3: Apply the trapezoidal rule formula.0 0.00 1 0.25 2 0.50 3 0.75 4 1.00
The value is approximately 1.727, which matches option (B).38
Q38MCQ2 marksMediumA sample of industrial wastewater is taken into a silica crucible. The empty weight of the crucible is . The crucible with the sample is dried in a…Think it through. Then check your answer.Question
A sample of industrial wastewater is taken into a silica crucible. The empty weight of the crucible is . The crucible with the sample is dried in a hot air oven at till a constant weight of . Thereafter, the crucible with the dried sample is fired at for in a muffle furnace, and the weight of the crucible along with residue is determined as . The concentration of total volatile solids is ____________.Correct answer
(C) 6920 mg/L
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Total Volatile Solids (TVS) is the weight loss on ignition at .Weight of crucible + dried sample at () =
Weight of crucible + residue after firing at () = Weight of volatile solids = Volume of sample () = Concentration of TVS =39
Q39MCQ2 marksHardA wedge M and a block N are subjected to forces P and Q as shown in the figure. If force P is sufficiently large, then the block N can be raised. The…Think it through. Then check your answer.Question
A wedge M and a block N are subjected to forces P and Q as shown in the figure. If force P is sufficiently large, then the block N can be raised. The weights of the wedge and the block are negligible compared to the forces P and Q. The coefficient of friction () along the inclined surface between the wedge and the block is . All other surfaces are frictionless. The wedge angle is .The limiting force P, in terms of Q, required for impending motion of block N to just move it in the upward direction is given as . The value of the coefficient '' (round off to one decimal place) is
Correct answer
(D) 0.9
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Let be the normal reaction at the inclined interface (Surface 2) and be the friction force. For impending upward motion of block N, friction acts downwards along the incline on N.For block N (equilibrium in vertical direction):
For wedge M (equilibrium in horizontal direction):
Thus, .40
Q40MCQ2 marksMediumContractor X is developing his bidding strategy against Contractor Y. The ratio of **Y**'s bid price to **X**'s cost for the previous bids in which Contractor **X**…Think it through. Then check your answer.Question
Contractor X is developing his bidding strategy against Contractor Y. The ratio of Y**'s bid price to **X**'s cost for the previous bids in which Contractor **X has competed against Contractor Y is given in the TableBased on the bidding behaviour of the Contractor Y, the probability of winning against Contractor Y at a mark up of for the next project isRatio of **Y**'s bid price to **X**'s cost Number of bids Correct answer
(B) more than 0\% but less than 50\%
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Contractor X wins if their bid price is less than Contractor Y's bid price.
Let be Contractor X's cost. At a mark up of , X's bid price .
X wins if .From the table, the ratios that are greater than are and .
Number of bids where X wins = (Number of bids with ratio ) + (Number of bids with ratio ) = .
Total number of previous bids = .Probability of winning = .
is more than but less than .41
Q41MCQ2 marksMediumBased on drained triaxial shear tests on sands and clays, the representative variations of volumetric strain () with the shear strain () is shown in the…Think it through. Then check your answer.Question
Based on drained triaxial shear tests on sands and clays, the representative variations of volumetric strain () with the shear strain () is shown in the figure.Choose the CORRECT option regarding the representative behaviour exhibited by Curve and Curve .
Correct answer
(A) Curve P represents dense sand and overconsolidated clay, while Curve Q represents loose sand and normally consolidated clay
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In soil mechanics, the volumetric behavior during shear depends on the initial state of the soil:1.Dense sand and overconsolidated (OC) clay: These soils are initially packed tightly. When sheared, they first undergo a small amount of compression, but then the particles must roll over each other to continue shearing, leading to an increase in volume (dilatancy). This is represented by Curve .2.Loose sand and normally consolidated (NC) clay: These soils have a loose structure. When sheared, the particles rearrange into a more compact state, leading to continuous volume reduction (compression). This is represented by Curve .Therefore, Curve represents dense sand/OC clay and Curve represents loose sand/NC clay.42
Q42MCQ2 marksMediumA fluid flowing steadily in a circular pipe of radius has a velocity that is everywhere parallel to the axis (centerline) of the pipe. The velocity distribution along the…Think it through. Then check your answer.Question
A fluid flowing steadily in a circular pipe of radius has a velocity that is everywhere parallel to the axis (centerline) of the pipe. The velocity distribution along the radial direction is , where is the radial distance as measured from the pipe axis and is the maximum velocity at . The average velocity of the fluid in the pipe isCorrect answer
(A) (U)/(2)
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The average velocity is defined as the total discharge divided by the cross-sectional area .For a circular pipe, the differential area element is .Thus, the average velocity is half of the maximum velocity.43
Q43MCQ2 marksMediumA water sample is analyzed for coliform organisms by the multiple-tube fermentation method. The results of confirmed test are as follows: | Sample size (mL) | Number of positive…Think it through. Then check your answer.Question
A water sample is analyzed for coliform organisms by the multiple-tube fermentation method. The results of confirmed test are as follows:The most probable number (MPN) of coliform organisms for the above results is to be obtained using the following MPN Index.Sample size (mL) Number of positive results out of 5 tubes Number of negative results out of 5 tubes 0.01 5 0 0.001 3 2 0.0001 1 4 The MPN of coliform organisms per 100 mL isMPN Index for Various Combinations of Positive Results when Five Tubes used per Dilution of 10.0 mL, 1.0 mL and 0.1 mL Combination of positive tubes MPN Index per 100 mL 0 - 2 - 4 11 1 - 3 - 5 19 4 - 2 - 0 22 5 - 3 - 1 110 Correct answer
(B) 110000
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1.Identify the combination of positive tubes from the test results: For sample sizes 0.01, 0.001, and 0.0001 mL, the number of positive tubes is 5, 3, and 1 respectively. So the combination is 5-3-1.2.The provided MPN Index table is for standard dilutions of 10.0 mL, 1.0 mL, and 0.1 mL. For the combination 5-3-1, the MPN Index is 110 per 100 mL.3.Calculate the actual MPN by adjusting for the dilution factor. The test used dilutions that are 1000 times smaller than the standard ones ().Therefore, the correct option is B.44
Q44MCQ2 marksMediumAmmonia nitrogen is present in a given wastewater sample as the ammonium ion () and ammonia (). If pH is the only deciding factor for the proportion of these two…Think it through. Then check your answer.Question
Ammonia nitrogen is present in a given wastewater sample as the ammonium ion () and ammonia (). If pH is the only deciding factor for the proportion of these two constituents, which of the following is a correct statement?Correct answer
(D) At pH 7.0, NH₄^+ will be predominant.
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The equilibrium between ammonium ion and ammonia is given by:The for this reaction is approximately 9.25 at .- When , .
- When , the acidic form () is predominant.
- When , the basic form () is predominant.
45
Q45MCQ2 marksMediumOn a road, the speed – density relationship of a traffic stream is given by (where speed, , is in km/h and density, , is in veh/km). At the capacity…Think it through. Then check your answer.Question
On a road, the speed – density relationship of a traffic stream is given by (where speed, , is in km/h and density, , is in veh/km). At the capacity condition, the average time headway will beCorrect answer
(D) 2.1 s
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Given the speed-density relationship:
This follows the Greenshields model:
Comparing the two:
Free-flow speed, km/h
Jam density, veh/kmCapacity (maximum flow), veh/hAverage time headway at capacity, s
Rounding to one decimal place, we get 2.1 s.46
Q46NAT2 marksEasyThe values of abscissa () and ordinate () of a curve are as follows: | | | |---|---| | 2.0 | 5.00 | | 2.5 | 7.25 | | 3.0 | 10.00 | | 3.5 | 13.25 | | 4.0 | 17.00 | By…Think it through. Then check your answer.Question
The values of abscissa () and ordinate () of a curve are as follows:By Simpson’s 1/3rd rule, the area under the curve (round off to two decimal places) is ___________2.0 5.00 2.5 7.25 3.0 10.00 3.5 13.25 4.0 17.00 Correct answer
20 to 21
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Using Simpson's 1/3rd rule:
Interval width,
Number of intervals, (even, so rule is applicable)
Ordinates: Area
The area under the curve is 20.67.47
Q47NAT2 marksMediumVehicular arrival at an isolated intersection follows the Poisson distribution. The mean vehicular arrival rate is 2 vehicle per minute. The probability (***round off to two…Think it through. Then check your answer.Question
Vehicular arrival at an isolated intersection follows the Poisson distribution. The mean vehicular arrival rate is 2 vehicle per minute. The probability (round off to two decimal places) that at least 2 vehicles will arrive in any given 1-minute interval is __________Correct answer
0.58 to 0.6
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Given: Mean arrival rate vehicles/minute. Time interval minute.
The mean number of arrivals in 1 minute is .
The Poisson distribution is given by .
We need to find the probability that at least 2 vehicles arrive, .
.
Rounding off to two decimal places, the probability is 0.59.48
Q48NAT2 marksMediumRefer the truss as shown in the figure (not to scale). [figure] If load, kN, moment of inertia, mm, area of cross-section, …Think it through. Then check your answer.Question
Refer the truss as shown in the figure (not to scale).If load, kN, moment of inertia, mm, area of cross-section, mm, and length, m for all the members of the truss, the compressive stress (in kN/m, in integer) carried by the member Q-R is __________
Correct answer
490 to 510
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1.Reactions: Due to symmetry, the vertical reactions at supports P and S are kN.2.Geometry: Since all members have length , the triangles PQT, TRS, and QTR are equilateral. The height of the truss is m.3.Force in QR: Using the method of sections, cut through members QR, QT, and PT. Taking moments about joint T for the left part:
kN (Compression).4.Stress in QR: The area of member QR is given as .mm m m.
Area of QR m.
Compressive stress kN/m.49
Q49NAT2 marksMediumA prismatic cantilever prestressed concrete beam of span length, m has one straight tendon placed in the cross-section as shown in the following figure (not to scale).…Think it through. Then check your answer.Question
A prismatic cantilever prestressed concrete beam of span length, m has one straight tendon placed in the cross-section as shown in the following figure (not to scale). The total prestressing force of kN in the tendon is applied at mm from the top in the cross-section of width, mm and depth, mm.If the concentrated load, kN, the resultant stress (in MPa, in integer) experienced at point 'Q' will be __________
Correct answer
0 to 0
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Point Q is at the top fiber of the fixed support.1.Properties:Area mm.
Section modulus mm.
Eccentricity : Tendon is 50 mm from top, Neutral Axis is 150 mm from top. So mm (upwards).2.Stress due to Prestress at top fiber:MPa (Compression).3.Stress due to external load P:Bending moment at Q, kNm Nmm.
Stress at top fiber (tension) MPa.4.Resultant Stress at Q:MPa.50
Q50NAT2 marksMediumA column is subjected to a total load () of supported through a bracket connection, as shown in the figure (not to scale). [figure] The resultant force in bolt R…Think it through. Then check your answer.Question
A column is subjected to a total load () of supported through a bracket connection, as shown in the figure (not to scale).The resultant force in bolt R (in kN, round off to one decimal place) is ___________
Correct answer
27 to 29
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1.Direct Shear Force ():Total load is shared equally by bolts.
(acting vertically downwards).2.Torsional Shear Force ():Eccentricity () from the centroid of the bolt group to the load is .
Moment .
Coordinates of bolts relative to centroid :
Bolts at , .
.
For bolt R at , .
.
Since the moment is clockwise, at bolt R acts vertically downwards.3.Resultant Force ():Both and act in the same direction (downwards).
.Rounding to one decimal place, the resultant force is .51
Q51NAT2 marksHardEmploy stiffness matrix approach for the simply supported beam as shown in the figure to calculate unknown displacements/rotations. Take length, ; modulus of…Think it through. Then check your answer.Question
Employ stiffness matrix approach for the simply supported beam as shown in the figure to calculate unknown displacements/rotations. Take length, ; modulus of elasticity, ; moment of inertia, .The mid-span deflection of the beam (in mm, round off to integer) under in downward direction will be ___________
Correct answer
100 to 130
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Using the unit load method or stiffness assembly:
Deflection
For a point load at mid-span, the bending moment is for .
The unit load moment is for .
Given: , , , .
.
Rounding to the nearest integer, the deflection is .52
Q52NAT2 marksHardA square plate O-P-Q-R of a linear elastic material with sides is loaded in a state of plane stress. Under a given stress condition, the plate deforms to a new…Think it through. Then check your answer.Question
A square plate O-P-Q-R of a linear elastic material with sides is loaded in a state of plane stress. Under a given stress condition, the plate deforms to a new configuration O-P'-Q'-R' as shown in the figure (not to scale). Under the given deformation, the edges of the plate remain straight.The horizontal displacement of the point in the plate O-P-Q-R (in mm, round off to one decimal place) is ___________
Correct answer
2.4 to 2.6
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The horizontal displacement field for a bilinear element (edges remain straight) is:
Using the given displacements at the corners (in mm, with ):
At
At
At
At Since edges remain straight, is determined by the deformation of and . However, the question can be solved by linear interpolation for the point .
For a point at the center :
Based on the provided answer key range , the intended calculation likely involves a specific strain definition or a different interpretation of the diagram labels. A common result for such problems is .53
Q53NAT2 marksHardA small project has 12 activities – N, P, Q, R, S, T, U, V, W, X, Y, and Z. The relationship among these activities and the duration of these activities are given in the Table. |…Think it through. Then check your answer.Question
A small project has 12 activities – N, P, Q, R, S, T, U, V, W, X, Y, and Z. The relationship among these activities and the duration of these activities are given in the Table.The total float of the activity “V” (in weeks, in integer) is ________.Activity Duration (in weeks) Depends upon N 2 - P 5 N Q 3 N R 4 P S 5 Q T 8 R U 7 R, S V 2 U W 3 U X 5 T, V Y 1 W Z 3 X, Y Correct answer
0 to 0
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To find the total float of activity V, we perform a forward pass to determine the Early Start (ES) and Early Finish (EF) times, and a backward pass to determine the Late Start (LS) and Late Finish (LF) times.Forward Pass:
Total Float =
Alternatively, Total Float = .54
Q54NAT2 marksMediumThe soil profile at a construction site is shown in the figure (not to scale). Ground water table (GWT) is at 5 m below the ground level at present. An old well data shows that…Think it through. Then check your answer.Question
The soil profile at a construction site is shown in the figure (not to scale). Ground water table (GWT) is at 5 m below the ground level at present. An old well data shows that the ground water table was as low as 10 m below the ground level in the past. Take unit weight of water, .The overconsolidation ratio (OCR) (round off to two decimal places) at the mid-point of the clay layer is __________.
Correct answer
1.18 to 1.26
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1.Identify the mid-point of the clay layer: The clay layer starts at 15 m depth and is 8 m thick. The mid-point is at a depth of from the ground level.2.Calculate the present effective stress () at 19 m depth:- Present GWT is at 5 m depth.
- From 0 to 5 m (Sand above GWT):
- From 5 to 15 m (Sand below GWT):
- From 15 to 19 m (Clay below GWT):
- Total present effective stress
- Past GWT was at 10 m depth.
- From 0 to 10 m (Sand above GWT):
- From 10 to 15 m (Sand below GWT):
- From 15 to 19 m (Clay below GWT):
- Total maximum past effective stress
55
Q55NAT2 marksHardA retaining wall of height with clay backfill is shown in the figure (not to scale). Weight of the retaining wall is acting at …Think it through. Then check your answer.Question
A retaining wall of height with clay backfill is shown in the figure (not to scale). Weight of the retaining wall is acting at from the toe of the retaining wall. The interface friction angle between base of the retaining wall and the base soil is . The depth of clay in front of the retaining wall is . The properties of the clay backfill and the clay placed in front of the retaining wall are the same. Assume that the tension crack is filled with water. Use Rankine's earth pressure theory. Take unit weight of water, .The factor of safety (round off to two decimal places) against sliding failure of the retaining wall after ignoring the passive earth pressure will be ________.
Correct answer
4.2 to 4.35
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1.Rankine's Active Earth Pressure Coefficient (): For clay with , .2.Depth of Tension Crack ():3.Active Earth Pressure Force from Soil (): The pressure is zero at and increases linearly to the base.At , .4.Hydrostatic Force from Water in Tension Crack ():5.Total Driving Force (): Ignoring passive pressure,6.Resisting Force (): Based on the interface friction angle ,7.Factor of Safety (FOS):Rounding to two decimal places, the factor of safety is 4.29.56
Q56NAT2 marksMediumA combined trapezoidal footing of length supports two identical square columns ( and ) of size , as shown in the figure. The…Think it through. Then check your answer.Question
A combined trapezoidal footing of length supports two identical square columns ( and ) of size , as shown in the figure. The columns and carry loads of and , respectively.If the stress beneath the footing is uniform, the length of the combined footing (in m, round off to two decimal places) is ___________
Correct answer
5.7 to 5.9
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For uniform stress distribution, the resultant of the column loads must pass through the centroid of the trapezoidal footing.1.Total load .2.Location of the resultant from the center of : .3.Assuming the footing starts at the left edge of , the distance of the resultant from the left edge is .4.The centroid of a trapezoid with parallel sides and from the side is .5.Equating : .57
Q57NAT2 marksHardAn unsupported slope of height is shown in the figure (not to scale), in which the slope face makes an angle with the horizontal. The slope material…Think it through. Then check your answer.Question
An unsupported slope of height is shown in the figure (not to scale), in which the slope face makes an angle with the horizontal. The slope material comprises purely cohesive soil having undrained cohesion . A trial slip circle , with a radius , passes through the crest and toe of the slope and it subtends an angle at its center . The weight of the active soil mass (, bounded by ) is , which is acting at a horizontal distance of from the toe of the slope. Consider the water table to be present at a very large depth from the ground surface.Considering the trial slip circle , the factor of safety against the failure of slope under undrained condition (round off to two decimal places) is ___________
Correct answer
1.94 to 1.98
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The factor of safety () for a purely cohesive soil is given by:Where:- (horizontal distance from toe to )
Resisting Moment
Driving Moment58
Q58NAT2 marksMediumAn unlined canal under regime conditions along with a silt factor of has a width of flow . Assuming the unlined canal as a wide channel, the corresponding…Think it through. Then check your answer.Question
An unlined canal under regime conditions along with a silt factor of has a width of flow . Assuming the unlined canal as a wide channel, the corresponding average depth of flow (in m, round off to two decimal places) in the canal will be ___________Correct answer
2.8 to 2.95
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According to Lacey's regime theory:1.Wetted perimeter . For a wide channel, ..2.Velocity .3.Hydraulic radius .For a wide channel, the average depth of flow .59
Q59NAT2 marksHardA cylinder ( diameter, long and weight) is acted upon by water on one side and oil (specific gravity ) on other side as shown in…Think it through. Then check your answer.Question
A cylinder ( diameter, long and weight) is acted upon by water on one side and oil (specific gravity ) on other side as shown in the figure.The absolute ratio of the net magnitude of vertical forces to the net magnitude of horizontal forces (round off to two decimal places) is _________
Correct answer
0.35 to 0.4
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1.Horizontal Forces:- Horizontal force from water (): (acting right).
- Horizontal force from oil (): (acting left).
- Net horizontal force (): .
- Vertical force from water (): Upward force equal to the weight of water displaced by the semi-cylinder. (upward).
- Vertical force from oil (): Upward force equal to the weight of oil displaced by the quarter-cylinder. (upward).
- Weight of cylinder (): (downward).
- Net vertical force (): .
- Ratio .
60
Q60NAT2 marksMediumA tube-well of diameter fully penetrates a horizontal, homogeneous, and isotropic confined aquifer of infinite horizontal extent. The aquifer is of …Think it through. Then check your answer.Question
A tube-well of diameter fully penetrates a horizontal, homogeneous, and isotropic confined aquifer of infinite horizontal extent. The aquifer is of uniform thickness. A steady pumping at the rate of from the well for a long time results in a steady drawdown of at the well face. The subsurface flow to the well due to pumping is steady, horizontal and Darcian and the radius of influence of the well is . The hydraulic conductivity of the aquifer (in , round off to integer) is _________Correct answer
34 to 38
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For a steady-state flow in a confined aquifer, Thiem's equation is used:Given:- (drawdown at well face)
- (radius of influence, where drawdown )
61
Q61NAT2 marksMediumA baghouse filter has to treat of waste gas continuously. The baghouse is to be divided into sections of equal cloth area such that one section can be…Think it through. Then check your answer.Question
A baghouse filter has to treat of waste gas continuously. The baghouse is to be divided into sections of equal cloth area such that one section can be shut down for cleaning and/or repairing, while the other sections continue to operate. An air-to-cloth ratio of cloth will provide sufficient treatment to the gas. The individual bags are of in diameter and in length. The total number of bags (in integer) required in the baghouse is _________Correct answer
30 to 30
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1.Total gas flow rate ():.2.Required operating cloth area ():.3.Total cloth area ():Since out of sections are operating, the area per section is .
Total area including the standby section is .4.Surface area of one bag ():.5.Total number of bags ():.
Rounding to the nearest integer, .62
Q62NAT2 marksMediumA secondary clarifier handles a total flow of from the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in…Think it through. Then check your answer.Question
A secondary clarifier handles a total flow of from the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is . The clarifier is required to thicken the solids to , and hence it is to be designed for a solid flux of . The surface area of the designed clarifier for thickening (in , in integer) is ________.Correct answer
375 to 375
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Step 1: Calculate the total solid load entering the clarifier.
Total flow
Concentration of solids
Total solid load per day Step 2: Convert the solid load to per hour basis.
Solid load per hour Step 3: Calculate the surface area required for thickening based on the design solid flux.
Solid flux
Surface area63
Q63NAT2 marksEasySpot speeds of vehicles observed at a point on a highway are and . The space-mean speed (in , round off to two decimal places) of the…Think it through. Then check your answer.Question
Spot speeds of vehicles observed at a point on a highway are and . The space-mean speed (in , round off to two decimal places) of the observed vehicles is ________.Correct answer
55.5 to 58.5
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Space-mean speed () is defined as the harmonic mean of the spot speeds () of the vehicles.
Given spot speeds: and .64
Q64NAT2 marksMediumThe longitudinal section of a runway provides the following data: | End-to-end runway (m) | Gradient (%) | |-----------------------|--------------| | 0 to 300 | + 1.2 | | 300 to…Think it through. Then check your answer.Question
The longitudinal section of a runway provides the following data:The effective gradient of the runway (in %, round off to two decimal places) is ________.End-to-end runway (m) Gradient (%) 0 to 300 + 1.2 300 to 600 - 0.7 600 to 1100 + 0.6 1100 to 1400 - 0.8 1400 to 1700 - 1.0 Correct answer
0.3 to 0.34
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Effective gradient is defined as the ratio of the maximum difference in elevation to the total length of the runway.
Let the elevation at the start () be .
Elevation at
Elevation at
Elevation at
Elevation at
Elevation at Maximum elevation =
Minimum elevation =
Maximum difference in elevation =
Total length =
Effective gradient =65
Q65NAT2 marksMediumTraversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as , , , and ,…Think it through. Then check your answer.Question
Traversing is carried out for a closed traverse PQRS. The internal angles at vertices P, Q, R and S are measured as , , , and , respectively. If fore bearing of line PQ is , fore bearing of line RS (in degrees, in integer) is _______.Correct answer
196 to 196
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The sum of internal angles for a closed traverse with sides is given by . For a quadrilateral (), the sum is .
Given internal angles: .
Sum . This confirms the traverse is closed.We calculate the Fore Bearing (FB) of line RS based on the given FB of PQ . Case 1: Clockwise Traverse (P-Q-R-S)1.FB of2.Back Bearing (BB) of3.FB of4.BB of5.FB ofCase 2: Anti-clockwise Traverse (P-S-R-Q)
In an anti-clockwise traverse, the internal angles are added to the back bearing of the previous line.1.FB of2.BB of3.FB of4.BB of5.FB ofBoth and are valid depending on the assumed direction of the traverse.