GATE EC 2022 Set 1 — Question 43
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Digital Circuits → Sequential Logic → Ripple & Synchronous Counters
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Question
For the circuit shown, the clock frequency is and the duty cycle is 25%. For the signal at the Q output of the Flip-Flop, _______.

Correct answer
(A) frequency is f₀/4 and duty cycle is 50%
Solution
Read the figure. The counter's LSB drives both and ; the MSB is not connected. With , the JK flip-flop acts as a T flip-flop with .Counter LSB. In a 2-bit binary counter the LSB toggles on every clock edge, so at successive edges Flip-flop output. toggles only on edges where , i.e. on every second clock edge:
So stays high for 2 clock periods and low for 2 clock periods. Its period is , giving frequency with a 50% duty cycle. The 25% duty cycle of the clock does not matter, because the flip-flop changes state only on clock edges.
| Edge | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| LSB before edge | 0 | 1 | 0 | 1 | 0 |
| after edge | 0 | 1 | 1 | 0 | 0 |
- (B) a 25% duty cycle would need high for only one clock period in four.
- (C), (D): the frequency is not or .
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