GATE CS 2024 Set 2 — Question 53
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Question
Consider a disk with the following specifications: rotation speed of 6000 RPM, average seek time of 5 milliseconds, 500 sectors/track, 512-byte sectors.
A file has content stored in 3000 sectors located randomly on the disk. Assuming average rotational latency, the total time (in seconds, rounded off to 2 decimal places) to read the entire file from the disk is _________
A file has content stored in 3000 sectors located randomly on the disk. Assuming average rotational latency, the total time (in seconds, rounded off to 2 decimal places) to read the entire file from the disk is _________
Correct answer
29.5 to 30.5
Solution
Given:
Since there are 500 sectors per track, the time to read one sector is the time for one rotation divided by the number of sectors:Step 3: Calculate Total Time
Since the sectors are located randomly, each sector access requires independent Seek, Rotational Latency, and Transfer.Total time for 3000 sectors:The value 30.06 lies within the accepted range of 29.50 to 30.50.
- Rotation speed = 6000 RPM
- Average seek time () = 5 ms
- Sectors per track = 500
- Total sectors to read = 3000
- Sectors are located randomly.
Since there are 500 sectors per track, the time to read one sector is the time for one rotation divided by the number of sectors:Step 3: Calculate Total Time
Since the sectors are located randomly, each sector access requires independent Seek, Rotational Latency, and Transfer.Total time for 3000 sectors:The value 30.06 lies within the accepted range of 29.50 to 30.50.
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