GATE CS 2014 Set 1 — Question 19
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Computer Organization & Architecture → Instructions & Addressing Modes → Instruction Formats
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Question
A machine has a 32-bit architecture, with 1-word long instructions. It has 64 registers, each of which is 32 bits long. It needs to support 45 instructions, which have an immediate operand in addition to two register operands. Assuming that the immediate operand is an unsigned integer, the maximum value of the immediate operand is ____________.
Correct answer
16383 to 16383
Solution
1.Instruction Length: The architecture is 32-bit with 1-word long instructions, so each instruction is 32 bits.
2.Opcode Bits: To support 45 instructions, we need bits for the opcode.
3.Register Operand Bits: There are 64 registers, so each register address requires bits. Since there are two register operands, they take bits.
4.Immediate Operand Bits: The remaining bits in the 32-bit instruction are used for the immediate operand.
Bits for immediate operand = Total bits - Opcode bits - Register bitsBits for immediate operand = bits.
5.Maximum Value: For an unsigned 14-bit integer, the maximum value is .
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