GATE CS 2016 Set 2 — Question 41
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Computer Organization & Architecture → Instructions & Addressing Modes → Instruction Formats
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Question
Consider a processor with 64 registers and an instruction set of size twelve. Each instruction has five distinct fields, namely, opcode, two source register identifiers, one destination register identifier, and a twelve-bit immediate value. Each instruction must be stored in memory in a byte-aligned fashion. If a program has 100 instructions, the amount of memory (in bytes) consumed by the program text is ________ .
Correct answer
500 to 500
Solution
1.Calculate bits required for each field:
- Opcode: For an instruction set of size 12, we need bits.
- Registers: For 64 registers, we need bits per register identifier.
- Immediate value: Given as 12 bits.
- Opcode: 4 bits
- Source Register 1: 6 bits
- Source Register 2: 6 bits
- Destination Register: 6 bits
- Immediate: 12 bits
- Total = bits.
- The problem states instructions are stored in a byte-aligned fashion. This means each instruction must occupy an integer number of bytes.
- Size in bytes = bytes.
- Total memory = Number of instructions Size per instruction
- Total memory = bytes.
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