The PYQ practice room
GATE EC 2016 Set 3
All 65 solved GATE EC 2016 Set 3 questions in exam order. Open a question, commit to an answer, and learn from the step-by-step solution. One question at a time.
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65
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100
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General Aptitude (GA)
101
Q1MCQ1 markEasyAn apple costs Rs. 10. An onion costs Rs. 8. Select the most suitable sentence with respect to grammar and usage.Think it through. Then check your answer.Question
An apple costs Rs. 10. An onion costs Rs. 8.Select the most suitable sentence with respect to grammar and usage.Correct answer
(C) The price of an apple is greater than that of an onion.
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Option (C) is grammatically correct because it correctly compares the price of one item with the price of another using the phrase 'that of'.- Option (A) incorrectly compares a 'price' to an 'onion'.
- Option (B) incorrectly compares a 'price' to an 'onion' and lacks the necessary article 'an'.
- Option (D) contains a double comparative error ('more costlier').
2
Q2MCQ1 markEasyThe Buddha said, “Holding on to anger is like grasping a hot coal with the intent of throwing it at someone else; you are the one who gets burnt.” Select the word below…Think it through. Then check your answer.Question
The Buddha said, “Holding on to anger is like grasping a hot coal with the intent of throwing it at someone else; you are the one who gets burnt.”Select the word below which is closest in meaning to the word underlined above.Correct answer
(C) clutching
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In this context, 'grasping' means to seize and hold firmly. 'Clutching' is the closest synonym among the choices, as it also means to grasp or seize something tightly.3
Q3MCQ1 markEasyhas a son and a daughter . He has no other children. is the mother of and daughter-in-law of . How is related to ?Think it through. Then check your answer.Question
has a son and a daughter . He has no other children. is the mother of and daughter-in-law of . How is related to ?Correct answer
(B) P is the grandchild of M.
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1. has two children: (son) and (daughter).2. is the daughter-in-law of . Since has only one son (), must be the wife of .3. is the mother of . Since is married to , is the child of and .4.Since is the child of 's son (), is the grandchild of .4
Q4MCQ1 markEasyThe number that least fits this set: (324, 441, 97 and 64) is ________.Think it through. Then check your answer.Question
The number that least fits this set: (324, 441, 97 and 64) is ________.- A.324
- B.441
- C.97
- D.64
Answer checking is unavailable for this question. You can review the published solution without a score.
Correct answer
(C;D)
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To find the number that least fits the set , we examine the mathematical properties of each number:1.Perfect Squares:- is a prime number and is not a perfect square.
- Logic: Since 324, 441, and 64 are perfect squares and 97 is not, 97 (Option C) is the odd one out.
- are not perfect cubes.
- Logic: Since 64 is the only perfect cube in the set, 64 (Option D) is the odd one out.
- A.
5
Q5MCQ1 markEasyIt takes 10 s and 15 s, respectively, for two trains travelling at different constant speeds to completely pass a telegraph post. The length of the first train is 120 m and that…Think it through. Then check your answer.Question
It takes 10 s and 15 s, respectively, for two trains travelling at different constant speeds to completely pass a telegraph post. The length of the first train is 120 m and that of the second train is 150 m. The magnitude of the difference in the speeds of the two trains (in m/s) is ____________.Correct answer
(A) 2.0
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Speed of the first train, .
Speed of the second train, .
The magnitude of the difference in speeds is .6
Q6MCQ2 marksEasyThe velocity of a vehicle along a straight line is measured in m/s and plotted as shown with respect to time in seconds. At the end of the 7 seconds, how much will the…Think it through. Then check your answer.Question
The velocity of a vehicle along a straight line is measured in m/s and plotted as shown with respect to time in seconds. At the end of the 7 seconds, how much will the odometer reading increase by (in m)?
Correct answer
(D) 5
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The odometer reading increase is equal to the total distance traveled, which is the area under the speed-time graph (the absolute value of the velocity-time graph).Distance = Calculating the area for each interval:- : Area =
- : Area =
- : Area =
- : Area =
- : Area =
- : Area =
- : Area =
7
Q7MCQ2 marksEasyThe overwhelming number of people infected with rabies in India has been flagged by the World Health Organization as a source of concern. It is estimated that inoculating 70% of…Think it through. Then check your answer.Question
The overwhelming number of people infected with rabies in India has been flagged by the World Health Organization as a source of concern. It is estimated that inoculating 70% of pets and stray dogs against rabies can lead to a significant reduction in the number of people infected with rabies.Which of the following can be logically inferred from the above sentences?Correct answer
(A) The number of people in India infected with rabies is high.
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The passage states that the "overwhelming number of people infected with rabies in India" has been flagged as a "source of concern" by the WHO. This directly supports the inference that the number of people infected is high. Option (C) is incorrect because the text mentions a "significant reduction," not "eradication." Options (B) and (D) make claims about the rest of the world or the primary source of rabies worldwide, which are not discussed in the provided text.8
Q8MCQ2 marksEasyA flat is shared by four first year undergraduate students. They agreed to allow the oldest of them to enjoy some extra space in the flat. Manu is two months older than Sravan,…Think it through. Then check your answer.Question
A flat is shared by four first year undergraduate students. They agreed to allow the oldest of them to enjoy some extra space in the flat. Manu is two months older than Sravan, who is three months younger than Trideep. Pavan is one month older than Sravan. Who should occupy the extra space in the flat?Correct answer
(C) Trideep
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Let Sravan's age be .1.Manu is two months older than Sravan: .2.Sravan is three months younger than Trideep: .3.Pavan is one month older than Sravan: .Comparing the ages: .
Trideep is the oldest and should occupy the extra space.9
Q9MCQ2 marksMediumFind the area bounded by the lines , in the first quadrant.Think it through. Then check your answer.Question
Find the area bounded by the lines , in the first quadrant.Correct answer
(B) 15.25
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The lines are and .Step 1: Find the intersection point.
Multiply by 3:
Multiply by 2:
Adding the equations: .
Substitute into : .
The intersection point is .Step 2: Identify the vertices of the region in the first quadrant.- Origin:
- x-intercept of (): . Point:
- Intersection point:
- y-intercept of (): . Point:
Area
Area
Area .10
Q10MCQ2 marksEasyA straight line is fit to a data set . This line intercepts the abscissa at and has a slope of . What is the value of at from the fit?Think it through. Then check your answer.Question
A straight line is fit to a data set . This line intercepts the abscissa at and has a slope of . What is the value of at from the fit?Correct answer
(A) -0.030
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The equation of a straight line in the plane can be expressed as , where is the slope and is the y-intercept.Given:1.Slope .2.The line intercepts the abscissa (the axis, where ) at .Using the point-slope form of the line equation:
Substituting the intercept point :
To find the value of at , we first calculate :
Now, substitute this value into the equation:
Rounding to three decimal places, we get .Therefore, the correct option is (A).
Electronics and Communication Engineering (Set 3)
5511
Q11MCQ1 markEasyConsider a square matrix where x is unknown. If the eigenvalues of the matrix A are…Think it through. Then check your answer.Question
Consider a square matrix where x is unknown. If the eigenvalues of the matrix A are and , then x is equal toCorrect answer
(D) -ω
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The eigenvalues of a matrix are given by the characteristic equation .
For the given matrix , the characteristic equation is:
We are given that the eigenvalues are and .
Comparing these with , we have:
Squaring both sides:
If , we can divide by :
Therefore, the correct option is (D).12
Q12NAT1 markEasyFor , the residue of the pole at isThink it through. Then check your answer.Question
For , the residue of the pole at isCorrect answer
1 to 1
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The function is .
The pole is at .
We need to find the order of the pole.
The Taylor series expansion of around is:
So,
This is the Laurent series expansion of around .
The residue of at is the coefficient of the term in its Laurent series expansion.
From the expansion, the coefficient of is .
Thus, the residue of the pole at is .13
Q13NAT1 markEasyThe probability of getting a “head” in a single toss of a biased coin is . The coin is tossed repeatedly till a “head” is obtained. If the tosses are independent, then the…Think it through. Then check your answer.Question
The probability of getting a “head” in a single toss of a biased coin is . The coin is tossed repeatedly till a “head” is obtained. If the tosses are independent, then the probability of getting "head" for the first time in the fifth toss isCorrect answer
0.07 to 0.08
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LetP(H)be the probability of getting a head in a single toss, so .
LetP(T)be the probability of getting a tail in a single toss, so .
We want to find the probability of getting a "head" for the first time in the fifth toss.
This means the first four tosses must be tails, and the fifth toss must be a head.
Since the tosses are independent, the probability is:14
Q14NAT1 markEasyThe integral is equal to __________Think it through. Then check your answer.Question
The integral is equal to __________Correct answer
2 to 2
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To evaluate the integral , we use the substitution . Then .
When . When .
.15
Q15NAT1 markHardConsider the first order initial value problem with exact solution . For , the percentage difference…Think it through. Then check your answer.Question
Consider the first order initial value problem with exact solution . For , the percentage difference between the exact solution and the solution obtained using a single iteration of the second-order Runge-Kutta method with step-size is __________Correct answer
0.06 to 0.063
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1.Exact Solution:At , .2.Runge-Kutta 2nd Order (Heun's Method):Given , .
.
.
.3.Percentage Difference:.
Rounding to two decimal places, we get 0.06.16
Q16MCQ1 markMediumConsider the signal , where is in seconds. The Nyquist sampling rate (in samples/second) for the signal isThink it through. Then check your answer.Question
Consider the signal , where is in seconds. The Nyquist sampling rate (in samples/second) for the signal isCorrect answer
(C) 16
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The signal consists of two frequency components:
Hz and Hz.
The maximum frequency in is Hz. The signal is a time-scaled and shifted version of . Time scaling by a factor of scales the frequencies by the same factor.
Frequencies in are Hz and Hz.
The maximum frequency in is Hz. The Nyquist sampling rate is samples/second.17
Q17MCQ1 markEasyIf the signal with denoting the convolution operation, then is equal toThink it through. Then check your answer.Question
If the signal with denoting the convolution operation, then is equal toCorrect answer
(A) \sin(t){\pi t}
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Let . Its Fourier transform is .
Convolution in the time domain corresponds to multiplication in the frequency domain:
.
Taking the inverse Fourier transform, we get .18
Q18MCQ1 markEasyA discrete-time signal has z-transform . If is the z-transform of another signal , thenThink it through. Then check your answer.Question
A discrete-time signal has z-transform . If is the z-transform of another signal , thenCorrect answer
(C) y[n] = -x[n]
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The property of the z-transform states that if , then .
Given , it follows that .
For the given signal :
.19
Q19MCQ1 markMediumIn the RLC circuit shown in the figure, the input voltage is given by . The output voltage isThink it through. Then check your answer.Question
In the RLC circuit shown in the figure, the input voltage is given by
.
The output voltage isCorrect answer
(B) 2cos(200t) + 4 sin(500t)
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The circuit is a symmetric lattice network. The parallel LC tanks have resonant frequencies:
rad/s
rad/s
At rad/s, the top parallel LC tank is in resonance (). At rad/s, the bottom parallel LC tank is in resonance ().
For a symmetric lattice with series arms and cross arms , the transfer function is or depending on polarity.
Given the options, the gain at resonance is 1, implying .20
Q20MCQ1 markMediumThe I-V characteristics of three types of diodes at the room temperature, made of semiconductors X, Y and Z, are shown in the figure. Assume that the diodes are uniformly doped…Think it through. Then check your answer.Question
The I-V characteristics of three types of diodes at the room temperature, made of semiconductors X, Y and Z, are shown in the figure. Assume that the diodes are uniformly doped and identical in all respects except their materials. If , and are the band gaps of X, Y and Z, respectively, then
Correct answer
(C) E_(gX) < E_(gY) < E_(gZ)
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The turn-on voltage () of a p-n junction diode is approximately proportional to the band gap () of the semiconductor material for similar doping levels. From the given I-V characteristics, the turn-on voltages follow the order . Therefore, the band gaps must follow the same order: .21
Q21MCQ1 markMediumThe figure shows the band diagram of a Metal Oxide Semiconductor (MOS). The surface region of this MOS is in [figure]Think it through. Then check your answer.Question
The figure shows the band diagram of a Metal Oxide Semiconductor (MOS). The surface region of this MOS is in
Correct answer
(A) inversion
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In the bulk of the semiconductor (right side), the intrinsic Fermi level is above the Fermi level , indicating a p-type substrate. At the surface (near the interface), the bands bend downwards, moving closer to . Since is still above at the surface but the hole concentration is reduced compared to the bulk, the surface is in depletion. If had crossed below , it would be in inversion. If the bands bent upwards, it would be in accumulation.22
Q22NAT1 markMediumThe figure shows the I-V characteristics of a solar cell illuminated uniformly with solar light of power . The solar cell has an area of and a…Think it through. Then check your answer.Question
The figure shows the I-V characteristics of a solar cell illuminated uniformly with solar light of power . The solar cell has an area of and a fill factor of . The maximum efficiency (in %) of the device is __________
Correct answer
20.5 to 21.5
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1.Calculate the input power ():.2.Calculate the maximum output power ():
From the figure, and .
.3.Calculate the efficiency ():.23
Q23NAT1 markMediumThe diodes D1 and D2 in the figure are ideal and the capacitors are identical. The product RC is very large compared to the time period of the ac voltage. Assuming that the diodes…Think it through. Then check your answer.Question
The diodes D1 and D2 in the figure are ideal and the capacitors are identical. The product RC is very large compared to the time period of the ac voltage. Assuming that the diodes do not breakdown in the reverse bias, the output voltage (in volt) at the steady state is __________Correct answer
0 to 0
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In the steady state, the top capacitor charges to the peak positive value of the input voltage, which is , through diode D1. Similarly, the bottom capacitor charges to the peak positive value of the input voltage, which is also , through diode D2. The output voltage is the difference between the voltages across the two capacitors. Due to the symmetry of the circuit and identical components, both capacitors charge to the same potential. Therefore, the steady-state output voltage .24
Q24NAT1 markMediumConsider the circuit shown in the figure. Assuming volt, the value of the dc voltage (in volt) is __________Think it through. Then check your answer.Question
Consider the circuit shown in the figure. Assuming volt, the value of the dc voltage (in volt) is __________Correct answer
0.45 to 0.55
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From the circuit, . Thus, . Since the emitter of Q1 is connected to the base of Q2, . The emitter of Q2 is at , so , which is consistent with the given value. The current through the resistor is . The collector current is given by . For the output voltage to be across the resistor, must be . This implies . The total emitter current of Q1 is . This set of currents and voltages is self-consistent for the given circuit configuration. Thus, .25
Q25NAT1 markMediumIn the astable multivibrator circuit shown in the figure, the frequency of oscillation (in kHz) at the output pin 3 is __________Think it through. Then check your answer.Question
In the astable multivibrator circuit shown in the figure, the frequency of oscillation (in kHz) at the output pin 3 is __________Correct answer
5.55 to 5.75
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For a 555 timer in astable mode, the frequency of oscillation is given by . Given , , and . Substituting these values: . The value lies within the range 5.55 to 5.75 kHz.26
Q26MCQ1 markMediumIn an 8085 microprocessor, the contents of the accumulator and the carry flag are A7 (in hex) and 0, respectively. If the instruction RLC is executed, then the contents of the…Think it through. Then check your answer.Question
In an 8085 microprocessor, the contents of the accumulator and the carry flag are A7 (in hex) and 0, respectively. If the instruction RLC is executed, then the contents of the accumulator (in hex) and the carry flag, respectively, will beCorrect answer
(D) 4F and 1
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In an 8085 microprocessor, the RLC (Rotate Left Accumulator) instruction rotates the contents of the accumulator one bit to the left. The most significant bit () is moved to the least significant bit () and also copied into the Carry Flag ().1.Initial Accumulator (A) = .2.Initial Carry Flag (CY) = .3.Bit of the accumulator is .4.After executing RLC:- The bits to are shifted left to positions to .
- The original bit () is moved to .
- The original bit () is also moved to the Carry Flag ().
6.New Carry Flag: .Therefore, the contents of the accumulator and the carry flag are 4F and 1, respectively.27
Q27MCQ1 markEasyThe logic functionality realized by the circuit shown below is [figure]Think it through. Then check your answer.Question
The logic functionality realized by the circuit shown below is
Correct answer
(D) AND
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The given circuit consists of two NMOS transistors acting as pass transistors.1.Top Transistor: Its gate is connected to , drain to , and source to . It is ON when .2.Bottom Transistor: Its gate is connected to , drain to , and source to ground (). It is ON when (i.e., ).Let's analyze the output for different values of :- If : The top transistor is ON and the bottom transistor is OFF. The output is connected to . Thus, .
- If : The top transistor is OFF and the bottom transistor is ON. The output is connected to ground. Thus, .
This corresponds to the logical AND operation.28
Q28MCQ1 markEasyThe minimum number of -input NAND gates required to implement a -input XOR gate isThink it through. Then check your answer.Question
The minimum number of -input NAND gates required to implement a -input XOR gate isCorrect answer
(A) 4
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To implement a 2-input XOR gate () using only 2-input NAND gates, the standard implementation requires 4 gates:1.First NAND gate:2.Second NAND gate:3.Third NAND gate:4.Fourth NAND gate:Thus, the minimum number of 2-input NAND gates required is 4.29
Q29MCQ1 markMediumThe block diagram of a feedback control system is shown in the figure. The overall closed-loop gain of the system is [figure]Think it through. Then check your answer.Question
The block diagram of a feedback control system is shown in the figure. The overall closed-loop gain of the system is
Correct answer
(B) G = (G₁ G₂)/(1 + G₁ G₂ + G₁ H₁)
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The system consists of an inner feedback loop and an outer unity feedback loop.1.The inner loop has forward gain and feedback gain . Its transfer function is .2.This inner loop is in series with , so the total forward path gain is .3.The overall system has unity negative feedback. The closed-loop gain is:This matches option (B).30
Q30MCQ1 markEasyFor the unity feedback control system shown in the figure, the open-loop transfer function is given as The steady state error due to a…Think it through. Then check your answer.Question
For the unity feedback control system shown in the figure, the open-loop transfer function is given asThe steady state error due to a unit step input is
Correct answer
(A) 0
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The open-loop transfer function is .
This is a Type 1 system because there is one pole at the origin ().
For a unit step input, the position error constant is:The steady state error for a unit step input is:Thus, the steady state error is 0.31
Q31NAT1 markMediumFor a superheterodyne receiver, the intermediate frequency is and the local oscillator frequency is . If the frequency of the received signal is…Think it through. Then check your answer.Question
For a superheterodyne receiver, the intermediate frequency is and the local oscillator frequency is . If the frequency of the received signal is greater than the local oscillator frequency, then the image frequency (in MHz) is __________Correct answer
3485 to 3485
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Given:
Intermediate Frequency,
Local Oscillator Frequency,
Received signal frequency, .
In a superheterodyne receiver, the intermediate frequency is the difference between the signal and LO frequencies:
Since , we have .
The image frequency is the frequency that also produces the same when mixed with , but lies on the opposite side of :
.
Alternatively, .32
Q32NAT1 markMediumAn analog baseband signal, bandlimited to 100 Hz, is sampled at the Nyquist rate. The samples are quantized into four message symbols that occur independently with probabilities…Think it through. Then check your answer.Question
An analog baseband signal, bandlimited to 100 Hz, is sampled at the Nyquist rate. The samples are quantized into four message symbols that occur independently with probabilities and . The information rate (bits/sec) of the message source is __________Correct answer
360 to 363
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1.Determine the sampling rate ():The signal is bandlimited to Hz. The Nyquist sampling rate is defined as:
2.Determine the probabilities of the message symbols:There are four symbols with probabilities . We are given:
3.Calculate the entropy ():Entropy is the average information per symbol:
Using :
4.Calculate the information rate ():The information rate is the product of the sampling rate and the entropy:
The value falls within the acceptable range of 360 to 363.33
Q33MCQ1 markEasyA binary baseband digital communication system employs the signal [figure] …Think it through. Then check your answer.Question
A binary baseband digital communication system employs the signalfor transmission of bits. The graphical representation of the matched filter output for this signal will be
Correct answer
(C) [figure]
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The matched filter impulse response for a signal of duration is .
For the given rectangular pulse for , the impulse response is also a rectangular pulse:
for .
The output of the matched filter is the convolution of and :
The convolution of two identical rectangular pulses of width and height is a triangular pulse of width with a peak at .
The peak value is .
Thus, is a triangle from to with a peak value of at . This matches option (C).34
Q34MCQ1 markEasyIf a right-handed circularly polarized wave is incident normally on a plane perfect conductor, then the reflected wave will beThink it through. Then check your answer.Question
If a right-handed circularly polarized wave is incident normally on a plane perfect conductor, then the reflected wave will beCorrect answer
(B) left-handed circularly polarized
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When a circularly polarized wave is incident normally on a perfect conductor, the tangential electric field must be zero at the boundary. This requires a phase shift for the reflected electric field components parallel to the surface.
For a right-handed circularly polarized (RHCP) wave, the electric field vector rotates in a clockwise direction when viewed in the direction of propagation. Upon reflection, the direction of propagation is reversed. The phase shift, combined with the reversal of the propagation direction, changes the sense of rotation relative to the direction of propagation from right-handed to left-handed. Therefore, the reflected wave is left-handed circularly polarized (LHCP).35
Q35MCQ1 markEasyFaraday’s law of electromagnetic induction is mathematically described by which one of the following equations?Think it through. Then check your answer.Question
Faraday’s law of electromagnetic induction is mathematically described by which one of the following equations?Correct answer
(C) × E = -∂ B∂ t
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Faraday's law of induction in differential form states that the curl of the electric field is equal to the negative of the time rate of change of the magnetic flux density:Other options represent different Maxwell's equations:
(A) Gauss's law for magnetism:
(B) Gauss's law for electricity:
(D) Ampere-Maxwell law: , where is the conduction current density.36
Q36MCQ2 marksMediumThe particular solution of the initial value problem given below is…Think it through. Then check your answer.Question
The particular solution of the initial value problem given below isCorrect answer
(A) (3 - 18x) e^(-6x)
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The given differential equation is a second-order linear homogeneous ODE with constant coefficients:The characteristic equation is , which factors as . The roots are repeated: .
The general solution is:Applying the initial conditions:1..2.Differentiating : ..
Substituting : .
Thus, the particular solution is .37
Q37MCQ2 marksMediumIf the vectors , and form an orthogonal basis of the three-dimensional real space ,…Think it through. Then check your answer.Question
If the vectors , and form an orthogonal basis of the three-dimensional real space , then the vector can be expressed asCorrect answer
(D) u = -(2)/(5)e₁ + 3e₂ - (11)/(5)e₃
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Since is an orthogonal basis, any vector can be expressed as , where the coefficients are found using the projection formula:Calculating the coefficients:
Therefore, .38
Q38NAT2 marksMediumA triangle in the -plane is bounded by the straight lines , and . The volume above the triangle and under the plane is __________Think it through. Then check your answer.Question
A triangle in the -plane is bounded by the straight lines , and . The volume above the triangle and under the plane is __________Correct answer
10 to 10
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The region in the -plane is a triangle bounded by , , and . The volume under the surface and above this region is given by the double integral:Setting up the limits:Evaluating the inner integral:Evaluating the outer integral:The volume is 10.39
Q39MCQ2 marksMediumThe values of the integral along a closed contour in anti-clockwise direction for (i) the point inside the contour…Think it through. Then check your answer.Question
The values of the integral along a closed contour in anti-clockwise direction for
(i) the point inside the contour , and
(ii) the point outside the contour ,
respectively, areCorrect answer
(B) (i) 7.39, (ii) 0
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According to Cauchy's Integral Formula, if is analytic within and on a closed contour , then:Here, and .
(i) When is inside the contour, the value is .
(ii) When is outside the contour, the value is 0.
Thus, the values are 7.39 and 0 respectively.40
Q40MCQ2 marksMediumA signal is the input to an LTI system with the transfer function If denotes the …Think it through. Then check your answer.Question
A signal is the input to an LTI system with the transfer functionIf denotes the coefficient in the exponential Fourier series of the output signal, then is equal toCorrect answer
(B) 1
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The input signal is .
The frequencies are and .
The fundamental frequency .
Expressing in terms of :
Using Euler's formula:
The input Fourier coefficients are .
The transfer function is . The frequency response is .
The output Fourier coefficients are .
We need .41
Q41MCQ2 marksMediumThe ROC (region of convergence) of the -transform of a discrete-time signal is represented by the shaded region in the -plane. If the signal…Think it through. Then check your answer.Question
The ROC (region of convergence) of the -transform of a discrete-time signal is represented by the shaded region in the -plane. If the signal , then the ROC of its -transform is represented byCorrect answer
(D) [figure]
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The given discrete-time signal is for .
We can decompose this signal into its causal and anti-causal parts:1.For the causal part , the -transform is and its ROC is .2.For the anti-causal part , the -transform is and its ROC is .The ROC of the total signal is the intersection of the individual ROCs:Since there is no region in the -plane that satisfies both and , the intersection is an empty set. Therefore, the -transform of does not converge for any value of , and the ROC does not exist.Hence, option (D) is the correct representation.42
Q42NAT2 marksHardAssume that the circuit in the figure has reached the steady state before time when the resistor suddenly burns out, resulting in an open circuit. The current…Think it through. Then check your answer.Question
Assume that the circuit in the figure has reached the steady state before time when the resistor suddenly burns out, resulting in an open circuit. The current (in ampere) at is __________
Correct answer
0.98 to 1.02
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1.Steady State Analysis at :- In steady state, capacitors act as open circuits.
- The total resistance of the circuit is .
- The total current from the source is .
- The voltage at the top node of the bridge is .
- The voltage at the right junction (between the and resistors) is .
- Since no current flows through the bridge resistor (), the voltage at the left junction (between the capacitors) is .
- The initial voltages across the capacitors are:
- At , the resistor burns out, creating an open circuit in that branch.
- Capacitors maintain their voltages instantaneously: and .
- Consequently, and .
- The current flows from node to node through the bridge resistor.
- Since the branch is open, the top-right resistor and the bridge resistor are now in series between and .
- .
43
Q43NAT2 marksMediumIn the figure shown, the current (in ampere) is __________ [figure]Think it through. Then check your answer.Question
In the figure shown, the current (in ampere) is __________
Correct answer
-1.05
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To find the current , we use nodal analysis on the given circuit.1.Identify Node Voltages:- Let the bottom wire be the reference node (ground, ). Since the left and right vertical wires are connected to the bottom wire, they are also at .
- The top wire is connected to the positive terminal of an voltage source whose negative terminal is at ground. Therefore, the voltage at the top node is .
- The central node of the star-connected resistors is connected to the positive terminal of another voltage source whose negative terminal is at ground. Therefore, the voltage at the central node is .
- The current source is connected between ground and the top node, supplying into the node.
- The resistor is connected between the top node and ground. The current through it is flowing away from the node.
- The resistor connected between the top node and the central node has a current .
- The current is defined as the current flowing away from the top node through the rightmost source branch.
4.Conclusion:The magnitude of the current is . Based on the official GATE answer range of to , the magnitude is the required value.Final Answer:44
Q44MCQ2 marksMediumThe z-parameter matrix for the two-port network shown is [figure]Think it through. Then check your answer.Question
The z-parameter matrix for the two-port network shown is
Correct answer
(A) [figure], [-2, 2]]]
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To find the z-parameters, we use the definitions:
and .1.Calculate :When , the output port is open. The input current splits into two parallel paths:- Path 1: Through the resistor and the cross-wire to the return terminal. Resistance = .
- Path 2: Through the cross-wire and the resistor to the return terminal. Resistance = .
By symmetry, .2.Calculate :. Let the input bottom terminal be the reference (0V). Then .
From the circuit connections:
(connected by wire).
(connected by wire).
So, .3.Reciprocity:Since the network is passive and bilateral, .The z-parameter matrix is .45
Q45NAT2 marksHardA continuous-time speech signal is sampled at a rate of 8 kHz and the samples are subsequently grouped in blocks, each of size . The DFT of each block is to be…Think it through. Then check your answer.Question
A continuous-time speech signal is sampled at a rate of 8 kHz and the samples are subsequently grouped in blocks, each of size . The DFT of each block is to be computed in real time using the radix-2 decimation-in-frequency FFT algorithm. If the processor performs all operations sequentially, and takes 20 s for computing each complex multiplication (including multiplications by 1 and ) and the time required for addition/subtraction is negligible, then the maximum value of is __________Correct answer
4096 to 4096
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Given:
Sampling frequency Hz.
Time to collect samples = seconds.For a radix-2 FFT algorithm, the number of complex multiplications required for an -point DFT is .
Time for one complex multiplication = s.
Total computation time for one block = s.For real-time processing, the computation time must be less than or equal to the time taken to collect the samples for the next block:
Since must be a power of 2 for the radix-2 FFT algorithm, the maximum possible value for is .46
Q46MCQ2 marksMediumThe direct form structure of an FIR (finite impulse response) filter is shown in the figure. [figure]…Think it through. Then check your answer.Question
The direct form structure of an FIR (finite impulse response) filter is shown in the figure.y[n]$.]The filter can be used to approximate a
Correct answer
(C) band-pass filter
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From the given block diagram, the difference equation for the filter is:
Taking the Z-transform:
To find the frequency response, substitute :
The magnitude response is .- At (DC/Low frequency), .
- At (High frequency), .
- At (Mid frequency), .
47
Q47NAT2 marksMediumThe injected excess electron concentration profile in the base region of an npn BJT, biased in the active region, is linear, as shown in the figure. If the area of the…Think it through. Then check your answer.Question
The injected excess electron concentration profile in the base region of an npn BJT, biased in the active region, is linear, as shown in the figure. If the area of the emitter-base junction is , in the base region and depletion layer widths are negligible, then the collector current (in mA) at room temperature is __________(Given: thermal voltage at room temperature, electronic charge )Correct answer
6.55 to 6.75
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The collector current in an npn BJT is given by the diffusion current formula:1.Calculate the diffusion constant using the Einstein relation:2.Determine the concentration gradient from the linear profile shown in the figure:3.Substitute the values into the formula:
The value falls within the range 6.55 to 6.75.48
Q48NAT2 marksMediumFigures I and II show two MOS capacitors of unit area. The capacitor in Figure I has insulator materials X (of thickness and dielectric constant…Think it through. Then check your answer.Question
Figures I and II show two MOS capacitors of unit area. The capacitor in Figure I has insulator materials X (of thickness and dielectric constant ) and Y (of thickness and dielectric constant ). The capacitor in Figure II has only insulator material X of thickness . If the capacitors are of equal capacitance, then the value of (in nm) is __________Correct answer
1.55 to 1.65
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The capacitance per unit area for a multi-layer dielectric is given by the series combination of individual capacitances:
For Figure II, the capacitance is:
Given :
The value falls within the range 1.55 to 1.65.49
Q49MCQ2 marksMediumThe I-V characteristics of the zener diodes D1 and D2 are shown in Figure I. These diodes are used in the circuit given in Figure II. If the supply voltage is varied from 0 to 100…Think it through. Then check your answer.Question
The I-V characteristics of the zener diodes D1 and D2 are shown in Figure I. These diodes are used in the circuit given in Figure II. If the supply voltage is varied from 0 to 100 V, then breakdown occurs inCorrect answer
(A) D1 only
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In Figure II, the two Zener diodes D1 and D2 are connected in series with opposing orientations.1.When the supply voltage is positive (0 to 100 V), D1 is reverse-biased and D2 is forward-biased.2.From Figure I, the Zener breakdown voltage for D1 is 80 V and for D2 is 70 V.3.As the supply voltage increases, D2 remains forward-biased (acting like a closed switch with a small forward drop).4.D1 is in reverse bias and will enter Zener breakdown when the voltage across it reaches its breakdown threshold of 80 V.5.Since the supply goes up to 100 V, D1 will definitely break down. D2, being forward-biased, does not undergo breakdown.Therefore, breakdown occurs in D1 only.50
Q50NAT2 marksMediumFor the circuit shown in the figure, , and . If the input , then the overall…Think it through. Then check your answer.Question
For the circuit shown in the figure, , and . If the input , then the overall voltage gain () of the circuit is __________Correct answer
-1
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Given .
The impedance of the inductor is .
The impedance of the capacitor is .The first stage is a non-inverting amplifier configuration:
The second stage is an inverting amplifier configuration:
Substituting :
Therefore, the overall voltage gain is .51
Q51MCQ2 marksMediumIn the circuit shown in the figure, the channel length modulation of all transistors is non-zero (). Also, all transistors operate in saturation and have…Think it through. Then check your answer.Question
In the circuit shown in the figure, the channel length modulation of all transistors is non-zero (). Also, all transistors operate in saturation and have negligible body effect. The ac small signal voltage gain () of the circuit isCorrect answer
(C) -gₘ₁ (rₒ₁ (1gₘ₂ rₒ₂) rₒ₃)
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In the small-signal model:1.Transistor is the driver NMOS with transconductance and output resistance .2.Transistor is a PMOS with its gate at a constant bias (AC ground). Its small-signal resistance is .3.Transistor is a diode-connected PMOS (gate connected to drain). Its small-signal resistance is .All three resistances are in parallel at the output node . The total output resistance is:
The small-signal voltage gain is:
This matches option (C).52
Q52NAT2 marksHardIn the circuit shown in the figure, transistor M1 is in saturation and has transconductance siemens. Ignoring internal parasitic capacitances and assuming the channel…Think it through. Then check your answer.Question
In the circuit shown in the figure, transistor M1 is in saturation and has transconductance siemens. Ignoring internal parasitic capacitances and assuming the channel length modulation to be zero, the small signal input pole frequency (in kHz) is __________Correct answer
56 to 63
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Given:
Transconductance S
Load resistance k
Source resistance k
Feedback capacitance (gate-to-drain) pFStep 1: Calculate the voltage gain of the common-source amplifier.
Step 2: Calculate the Miller capacitance at the input.
pFStep 3: Calculate the input pole frequency .
The input pole is formed by the source resistance and the total input capacitance (dominated by Miller capacitance).
kHzThe value kHz lies within the specified range of 56 to 63.53
Q53MCQ2 marksMediumFollowing is the K-map of a Boolean function of five variables P, Q, R, S and X. The minimum sum-of-product (SOP) expression for the function is [figure]Think it through. Then check your answer.Question
Following is the K-map of a Boolean function of five variables P, Q, R, S and X. The minimum sum-of-product (SOP) expression for the function is
Correct answer
(B) QSX + QSX
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The K-map for X=0 is given as:The 1s in the X=0 K-map are at minterms (P,Q,R,S,X):RS\PQ 00 01 11 10 00 0 0 0 0 01 1 0 0 1 11 1 0 0 1 10 0 0 0 0
(0,0,0,1,0), (1,0,0,1,0), (0,0,1,1,0), (1,0,1,1,0).
These four 1s form a quad covering .The K-map for X=1 is given as:The 1s in the X=1 K-map are at minterms:RS\PQ 00 01 11 10 00 0 1 1 0 01 0 0 0 0 11 0 0 0 0 10 0 0 1 0
(0,1,0,0,1), (1,1,0,0,1), (1,1,1,0,1).
These combine to .Thus, the function derived strictly from the given K-maps is .However, none of the options directly match this derived expression. In competitive exams, sometimes there are minor discrepancies in figures or options. If we consider option (B) which is , the first term perfectly matches the X=0 K-map. If the X=1 K-map was intended to represent , it would have 1s at (0,0,0,0,1), (1,0,0,0,1), (0,0,1,0,1), (1,0,1,0,1), which is different from the image. Assuming the question intends for option B to be correct, it implies the X=1 K-map should have been for .If we assume the intended function is , then:
.Given the options, and common patterns in such questions, option B is often the intended answer when the X=0 map gives and the X=1 map is expected to give .The final answer is54
Q54NAT2 marksMediumFor the circuit shown in the figure, the delays of NOR gates, multiplexers and inverters are , and , respectively. If all the inputs…Think it through. Then check your answer.Question
For the circuit shown in the figure, the delays of NOR gates, multiplexers and inverters are , and , respectively. If all the inputs and are applied at the same time instant, the maximum propagation delay (in ns) of the circuit is __________Correct answer
6 to 6
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To find the maximum propagation delay, we analyze the paths from the inputs to the output based on the state of the select signal .1.Multiplexer Logic:- MUX1 select input .
- MUX2 select input (due to the inverter).
- MUX1 selects input '1', which is .
- MUX2 select is , so it selects input '0', which is .
- The critical path is: .
- Total delay = .
- MUX1 selects input '0', which is .
- MUX2 select is , so it selects input '1', which is the output of MUX1.
- The critical path is: .
- Total delay = .
55
Q55MCQ2 marksHardFor the circuit shown in the figure, the delay of the bubbled NAND gate is and that of the counter is assumed to be zero. [figure] If the clock (Clk) frequency is…Think it through. Then check your answer.Question
For the circuit shown in the figure, the delay of the bubbled NAND gate is and that of the counter is assumed to be zero.If the clock (Clk) frequency is , then the counter behaves as a
Correct answer
(D) mod-8 counter
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1.Clock Period: The clock frequency is , so the clock period .2.Gate Logic: The "bubbled NAND" gate shown has bubbles on its inputs. According to De Morgan's law, a NAND gate with inverted inputs is equivalent to an OR gate: .3.Reset Condition: The output of this gate is connected to the active-low RESET pin. The counter resets when the gate output is , which occurs only when (state 0).4.Timing Analysis: The gate has a propagation delay of , which is twice the clock period (). In a synchronous counter, for a reset to truncate the sequence, the reset signal must be generated and applied within the same clock cycle or be synchronized.5.Conclusion: Since the reset condition only occurs at the initial state (000) and the logic delay () exceeds the clock period (), the reset signal does not effectively truncate the natural states of the 3-bit counter. Therefore, the counter cycles through all 8 states (0 to 7) and behaves as a mod-8 counter.56
Q56MCQ2 marksMediumThe first two rows in the Routh table for the characteristic equation of a certain closed-loop control system are given as | | | | |---|---|---| | | 1 | | | …Think it through. Then check your answer.Question
The first two rows in the Routh table for the characteristic equation of a certain closed-loop control system are given asThe range of for which the system is stable is1 4 Correct answer
(D) 0.5 < K < ∞
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The Routh table is constructed as follows:For stability, all elements in the first column must be positive:1 4 0 4 1.2. (since )
Since , we must have .
Thus, the range is .57
Q57MCQ2 marksMediumA second-order linear time-invariant system is described by the following state equations where…Think it through. Then check your answer.Question
A second-order linear time-invariant system is described by the following state equationswhere and are the two state variables and denotes the input. If the output , then the system isCorrect answer
(A) controllable but not observable
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The state equations can be written in matrix form and :
, , Controllability:
. The system is controllable.Observability:
. The system is not observable.Therefore, the system is controllable but not observable.58
Q58NAT2 marksMediumThe forward-path transfer function and the feedback-path transfer function of a single loop negative feedback control system are given as…Think it through. Then check your answer.Question
The forward-path transfer function and the feedback-path transfer function of a single loop negative feedback control system are given asrespectively. If the variable parameter is real positive, then the location of the breakaway point on the root locus diagram of the system is __________Correct answer
-3.45
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The characteristic equation is :
For breakaway/break-in points, :
Open-loop poles are at and the zero is at . The root locus exists on the real axis for . Thus, is the valid break-in point on the root locus.59
Q59MCQ2 marksMediumA wide sense stationary random process passes through the LTI system shown in the figure. If the autocorrelation function of is , then the autocorrelation…Think it through. Then check your answer.Question
A wide sense stationary random process passes through the LTI system shown in the figure. If the autocorrelation function of is , then the autocorrelation function of the output is equal to
Correct answer
(B) 2R_X(τ) - R_X(τ - T₀) - R_X(τ + T₀)
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From the block diagram, the output is given by:
The autocorrelation function of the output is defined as:
Expanding the product:
Using the linearity of expectation and the definition of for a WSS process:
Thus, option (B) is correct.60
Q60NAT2 marksHardA voice-grade AWGN (additive white Gaussian noise) telephone channel has a bandwidth of kHz and two-sided noise power spectral density …Think it through. Then check your answer.Question
A voice-grade AWGN (additive white Gaussian noise) telephone channel has a bandwidth of kHz and two-sided noise power spectral density Watt per Hz. If information at the rate of kbps is to be transmitted over this channel with arbitrarily small bit error rate, then the minimum bit-energy (in mJ/bit) necessary is __________Correct answer
30 to 33
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Given:
Bandwidth kHz Hz
Two-sided noise power spectral density W/Hz W/Hz
Information rate kbps bpsAccording to Shannon's capacity theorem, for error-free transmission:
Noise power W
Signal power WMinimum bit energy Joules/bit
in mJ/bit mJ/bit61
Q61NAT2 marksMediumThe bit error probability of a memoryless binary symmetric channel is . If bits are sent over this channel, then the probability that not more than one bit will be…Think it through. Then check your answer.Question
The bit error probability of a memoryless binary symmetric channel is . If bits are sent over this channel, then the probability that not more than one bit will be in error is __________Correct answer
0.7 to 0.75
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Given:
Probability of bit error
Number of bits This follows a binomial distribution . Since is large and is small, we can use the Poisson approximation with .The probability that not more than one bit is in error is .
Using Poisson distribution :62
Q62NAT2 marksMediumConsider an air-filled rectangular waveguide with dimensions and . At operating frequency, the value of the propagation…Think it through. Then check your answer.Question
Consider an air-filled rectangular waveguide with dimensions and . At operating frequency, the value of the propagation constant (per meter) of the corresponding propagating mode is __________Correct answer
155 to 162
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For an air-filled rectangular waveguide, the cut-off frequency for the dominant mode is given by:Given and :Since the operating frequency is greater than , the mode is propagating. The propagation constant for a lossless waveguide is:Substituting the values:The value of the propagation constant is approximately .63
Q63MCQ2 marksMediumConsider an air-filled rectangular waveguide with dimensions and . The increasing order of the cut-off frequencies for different modes isThink it through. Then check your answer.Question
Consider an air-filled rectangular waveguide with dimensions and . The increasing order of the cut-off frequencies for different modes isCorrect answer
(C) TE₁₀ < TE₂₀ < TE₀₁ < TE₁₁
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The cut-off frequency is .
Given and . Note that and ().1.2.3.4.Comparing the denominators:
Therefore, the frequencies are in the order:
This corresponds to option (C).64
Q64NAT2 marksHardA radar operating at uses a common antenna for transmission and reception. The antenna has a gain of 150 and is aligned for maximum directional radiation and…Think it through. Then check your answer.Question
A radar operating at uses a common antenna for transmission and reception. The antenna has a gain of 150 and is aligned for maximum directional radiation and reception to a target away having radar cross-section of . If it transmits , then the received power (in ) is __________Correct answer
0.01 to 0.02
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The radar range equation for received power is:Given:- Transmitted power
- Antenna gain
- Frequency
- Radar cross-section
- Distance
65
Q65MCQ2 marksMediumConsider the charge profile shown in the figure. The resultant potential distribution is best described by [figure]Think it through. Then check your answer.Question
Consider the charge profile shown in the figure. The resultant potential distribution is best described by
Correct answer
(D) [figure]
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The relationship between charge density and electric potential is governed by Poisson's equation in one dimension:Also, the electric field is related to the potential by:And from Gauss's Law:Step 1: Analyze the Electric Field- For , .
- For , (a negative constant). Thus, . Since and , is negative and decreases linearly from at to its minimum value at .
- For , (a positive constant). Thus, . Since , increases linearly from its minimum at back to at (assuming total charge neutrality).
- Since is negative throughout the region , the slope of the potential is positive. Therefore, is strictly increasing from to .
- Curvature: The second derivative determines the concavity.
- In : , so the curve is concave up (parabolic).
- In : , so the curve is concave down (parabolic).
- Boundary Slopes: At and , , so . The potential curve must be horizontal (zero slope) at these points.
The potential distribution starts flat at , increases with a concave-up shape until , then continues increasing with a concave-down shape until it levels off at . This behavior is correctly represented in option (D).